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gfields444

  • 3 years ago

Difficult question, please help!! What is the simplified form of the quantity 3 x squared over x squared minus 1 all over 9 x over the x squared plus 2 x plus 1 ? a)x times the quantity x minus 1 all over 3 times the quantity x plus 1 b)x times the sum x plus 1 all over 3 times the quantity x minus 1 c)3 x times the quantity x plus 1 all over the quantity x minus 1 d)the quantity x minus 1 all over 3 x times the quantity x plus 1

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  1. gfields444
    • 3 years ago
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    I tried to eliminate the choices, but I kept messing up. I just need help figuring out how to solve

  2. robtobey
    • 3 years ago
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    \[\frac{3x^2}{x^2-1}/\frac{9x}{x^2+2x+1} \]Is the above the problem expression?

  3. gfields444
    • 3 years ago
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    The first fraction that you put goes above the second.

  4. gfields444
    • 3 years ago
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    Oh I read that awrong. You're right!

  5. robtobey
    • 3 years ago
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    Well "/", although small, is a division sign.\[\left(\frac{3x^2}{x^2-1}/\frac{9x}{x^2+2x+1}\right)=\left(\frac{3x^2}{x^2-1}*\frac{x^2+2x+1}{9x}\right) \]Try factoring the expressions containing x^2. Also, 3x^2/9x will simplify.

  6. gfields444
    • 3 years ago
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    |dw:1346283896987:dw|

  7. robtobey
    • 3 years ago
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    The above is correct except for the 3x. Can you simplify the following.\[\frac{3x^2}{9x} \]

  8. gfields444
    • 3 years ago
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    Ohh would the 3x go on the bottom with the denominator? x^2

  9. gfields444
    • 3 years ago
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    Wait it would be .... (Hang on drawing it)

  10. gfields444
    • 3 years ago
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    |dw:1346284402022:dw|

  11. robtobey
    • 3 years ago
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    \[\frac{3x^2}{9x}=\frac{x}{3} \]Sorry, I had to leave the computer for a few minutes.

  12. robtobey
    • 3 years ago
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    Congratulations.\[\frac{x (x+1)}{3 (x-1)} \]is correct.

  13. gfields444
    • 3 years ago
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    Thank you so much!! You're so awesome!!

  14. robtobey
    • 3 years ago
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    And thank you for the medal.

  15. gfields444
    • 3 years ago
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    Anytime :)

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