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karatechopperBest ResponseYou've already chosen the best response.0
\[Fe+ H _{2}S0_{4}> Fe _{2}(S0_{4})_{3}\]
 one year ago

karatechopperBest ResponseYou've already chosen the best response.0
My teacher told me to always solve them by using this box......
 one year ago

karatechopperBest ResponseYou've already chosen the best response.0
dw:1346283514093:dw
 one year ago

karatechopperBest ResponseYou've already chosen the best response.0
I am sure u understand i can't do subnotes in drawing:/
 one year ago

karatechopperBest ResponseYou've already chosen the best response.0
I am really way too stuck
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
okay...can you identify how many Fe you have on the left side?
 one year ago

karatechopperBest ResponseYou've already chosen the best response.0
which is what i put in the reactant
 one year ago

karatechopperBest ResponseYou've already chosen the best response.0
oh i thought SO went together....so then S has 1 O has 4
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
right dw:1346283890519:dw now how many Fe, H, S and O in the products?
 one year ago

karatechopperBest ResponseYou've already chosen the best response.0
Hold on lemme correct my box
 one year ago

karatechopperBest ResponseYou've already chosen the best response.0
Fe 2 S 1 o 4 But i got confuzzled when it has that parenthesis with a 3 out of it. So that means i multiply right?
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
yes. distribute that subscript into the original subscripts
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
i,e \[(H_2 O)_3 \implies H_6 O_3\]
 one year ago

karatechopperBest ResponseYou've already chosen the best response.0
So.... S 3 0 12 correct?
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
wait....did you type this right? we're missing H in the products?
 one year ago

karatechopperBest ResponseYou've already chosen the best response.0
Aw shoot. lemme show u i missed a part.
 one year ago

karatechopperBest ResponseYou've already chosen the best response.0
\[Fe _{2}+H _{2}SO _{4}> Fe _{2}(SO _{4})_{3}+ H _{2}\]
 one year ago

karatechopperBest ResponseYou've already chosen the best response.0
There! missed out on the ending!
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
dw:1346284521882:dw
 one year ago

karatechopperBest ResponseYou've already chosen the best response.0
No....The H stayed the same through it all....
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
lol oops. i jumbled it
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
dw:1346284649236:dw there better
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
so...you have \[\Large Fe_2 + H_2 SO_4 \rightarrow Fe_2 S_3 O_{12} + H_2\] you'll want to balance the Os first do you know how?
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
how many O on the right side?
 one year ago

karatechopperBest ResponseYou've already chosen the best response.0
I know i have to multiply and change some stuff on the box, to make the reactants and products become equal
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
so...according to your box...how many O in the right side?
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
and how many on the left?
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
so what do you multiply to 4 to get 12?
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
so multiply 3... \[\large \implies Fe_2 + 3H_2 SO_4\rightarrow Fe_2 S_3 O_{12} + H_2\] fllowing so far?
 one year ago

karatechopperBest ResponseYou've already chosen the best response.0
Now what....i get lost
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
so now... you solve the values again... dw:1346285448126:dw do you get why?
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
wait....your question at first had one Fe in the reactant side when you drew it again... it became Fe2.....so how many Fe are there really in the reactant side?
 one year ago

chemENGINEERBest ResponseYou've already chosen the best response.0
yes very good approach....
 one year ago
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