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karatechopper Group Title

@lgbasallote

  • one year ago
  • one year ago

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  1. karatechopper Group Title
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    \[Fe+ H _{2}S0_{4}--> Fe _{2}(S0_{4})_{3}\]

    • one year ago
  2. lgbasallote Group Title
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    interesting

    • one year ago
  3. karatechopper Group Title
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    My teacher told me to always solve them by using this box......

    • one year ago
  4. karatechopper Group Title
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    |dw:1346283514093:dw|

    • one year ago
  5. karatechopper Group Title
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    I am sure u understand i can't do subnotes in drawing:/

    • one year ago
  6. karatechopper Group Title
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    I am really way too stuck

    • one year ago
  7. lgbasallote Group Title
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    okay...can you identify how many Fe you have on the left side?

    • one year ago
  8. karatechopper Group Title
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    1

    • one year ago
  9. karatechopper Group Title
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    which is what i put in the reactant

    • one year ago
  10. lgbasallote Group Title
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    how many H?

    • one year ago
  11. karatechopper Group Title
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    2

    • one year ago
  12. lgbasallote Group Title
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    how many S?

    • one year ago
  13. karatechopper Group Title
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    4

    • one year ago
  14. lgbasallote Group Title
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    nope

    • one year ago
  15. lgbasallote Group Title
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    check again

    • one year ago
  16. karatechopper Group Title
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    oh i thought SO went together....so then S has 1 O has 4

    • one year ago
  17. lgbasallote Group Title
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    right |dw:1346283890519:dw| now how many Fe, H, S and O in the products?

    • one year ago
  18. karatechopper Group Title
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    Hold on lemme correct my box

    • one year ago
  19. karatechopper Group Title
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    1 min

    • one year ago
  20. karatechopper Group Title
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    Fe 2 S 1 o 4 But i got confuzzled when it has that parenthesis with a 3 out of it. So that means i multiply right?

    • one year ago
  21. lgbasallote Group Title
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    yes. distribute that subscript into the original subscripts

    • one year ago
  22. lgbasallote Group Title
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    i,e \[(H_2 O)_3 \implies H_6 O_3\]

    • one year ago
  23. karatechopper Group Title
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    So.... S 3 0 12 correct?

    • one year ago
  24. lgbasallote Group Title
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    wait....did you type this right? we're missing H in the products?

    • one year ago
  25. karatechopper Group Title
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    Aw shoot. lemme show u i missed a part.

    • one year ago
  26. karatechopper Group Title
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    \[Fe _{2}+H _{2}SO _{4}--> Fe _{2}(SO _{4})_{3}+ H _{2}\]

    • one year ago
  27. karatechopper Group Title
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    There! missed out on the ending!

    • one year ago
  28. lgbasallote Group Title
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    |dw:1346284521882:dw|

    • one year ago
  29. karatechopper Group Title
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    No....The H stayed the same through it all....

    • one year ago
  30. lgbasallote Group Title
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    lol oops. i jumbled it

    • one year ago
  31. lgbasallote Group Title
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    |dw:1346284649236:dw| there better

    • one year ago
  32. karatechopper Group Title
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    yep

    • one year ago
  33. lgbasallote Group Title
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    so...you have \[\Large Fe_2 + H_2 SO_4 \rightarrow Fe_2 S_3 O_{12} + H_2\] you'll want to balance the Os first do you know how?

    • one year ago
  34. karatechopper Group Title
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    no...

    • one year ago
  35. lgbasallote Group Title
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    how many O on the right side?

    • one year ago
  36. karatechopper Group Title
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    I know i have to multiply and change some stuff on the box, to make the reactants and products become equal

    • one year ago
  37. lgbasallote Group Title
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    so...according to your box...how many O in the right side?

    • one year ago
  38. karatechopper Group Title
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    12

    • one year ago
  39. lgbasallote Group Title
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    and how many on the left?

    • one year ago
  40. karatechopper Group Title
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    4

    • one year ago
  41. lgbasallote Group Title
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    so what do you multiply to 4 to get 12?

    • one year ago
  42. karatechopper Group Title
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    3

    • one year ago
  43. lgbasallote Group Title
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    so multiply 3... \[\large \implies Fe_2 + 3H_2 SO_4\rightarrow Fe_2 S_3 O_{12} + H_2\] fllowing so far?

    • one year ago
  44. karatechopper Group Title
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    Yes

    • one year ago
  45. karatechopper Group Title
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    Now what....i get lost

    • one year ago
  46. lgbasallote Group Title
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    so now... you solve the values again... |dw:1346285448126:dw| do you get why?

    • one year ago
  47. lgbasallote Group Title
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    wait....your question at first had one Fe in the reactant side when you drew it again... it became Fe2.....so how many Fe are there really in the reactant side?

    • one year ago
  48. chemENGINEER Group Title
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    yes very good approach....

    • one year ago
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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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