anonymous
  • anonymous
the Figure shows four charges at the corners of a square of side L. Assume q and Q are positive. What is the magnitude of the net Force on q?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
|dw:1346286892631:dw|
anonymous
  • anonymous
|dw:1346298352562:dw|
anonymous
  • anonymous
the top right is also positive

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
|dw:1346298573822:dw|
anonymous
  • anonymous
|dw:1346298617109:dw|
anonymous
  • anonymous
|dw:1346299022875:dw| This is the real figure.. and the resultant force is along the diagonal but repulsive..
anonymous
  • anonymous
the answer is \[(2-\sqrt{2}) \frac{ KQq }{ L ^{2} }\].. i'm still confused on how to get it
anonymous
  • anonymous
See that F is the force by 2 -Qs on q... each of which is equal to F=Q∗q /(4Πϵ ∗L^2) and are attractive.. And each of these F act on q at 90 degree.. so their resultant is F ' = F*√2 towards the inside of the square .. along the diagonal.. And, the force on q by 4Q is 4Q∗q/(4Πϵ *2d^2) = 2F.. along the diagonal but outside the square.. So the forces 2F and F√2 are opposite .. Hence the resultant force will be 2F−F√2 = (2-√2) F Now put the value of F=Q∗q /(4Πϵ ∗L^2) to get the actual force..resultant. 4Πϵ can be written into a single constant K.
anonymous
  • anonymous
alright thanks!
anonymous
  • anonymous
Hi, did you have to draw vectors for this question? I can't seem to get it right.

Looking for something else?

Not the answer you are looking for? Search for more explanations.