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ihatealgebrasomuch
 3 years ago
i have to solve this by factoring... 49=9x^2 ... can i put a sqr. root sign over both sides, get 7=9x, and then get x=7/9???
ihatealgebrasomuch
 3 years ago
i have to solve this by factoring... 49=9x^2 ... can i put a sqr. root sign over both sides, get 7=9x, and then get x=7/9???

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barrycarter
 3 years ago
Best ResponseYou've already chosen the best response.0Well, that's not actually factoring, and you lose the answer x=7/9

sami21
 3 years ago
Best ResponseYou've already chosen the best response.0since it says solve by factoring i would say do nt take square root write as 9x^249=0 or can be written as \[\Large \implies (3x)^2(7)^2=0\] now use the formula \[\Large a^2b^2=(a+b)(ab)\] in the above we have a=3x ,b=7 just put that in the given formula does this help you ?

kmalone99
 3 years ago
Best ResponseYou've already chosen the best response.1yes you can square both sides 49=9x^2 \[\sqrt{49}=\sqrt{9x ^2{}}\] 7=3x divide by 3 so x=3/7 but its plus or minus

kmalone99
 3 years ago
Best ResponseYou've already chosen the best response.1however is does say fator 49=9x^2 bring 49 to other side of equal sgn 9x^249=0 (3x7)(3x+7)=0 solve for x 3x7=0 3x=7 divide by 3 x=7/3 and 3x+7=0 3x=7 x=7/3
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