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## anonymous 4 years ago What are the strength and direction of the electric field at the position indicated by the dot in the figure (Figure 1) ? I NEED DIRECTION NOW! Thanks

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1. anonymous

2. NoelGreco

$E = k \frac{ Q }{r ^{2} }$ Calculate that for each point charge. Then we'll add the vectors.

3. anonymous

How do you find direction?

4. anonymous

Addition of vectors

5. anonymous
6. anonymous
7. anonymous

the answer is in degrees? I need how to find the angle

8. NoelGreco

The direction of an electric field is the direction of the force on a positive test charge placed in the field. In this case the field is directed away from each of the positive charges.

9. anonymous

hag - you'd be surprise but there are topics which u actuall y need to read and understand in detail. And this is it

10. anonymous
11. anonymous

|dw:1346438409410:dw| $A=k3*10^{-9}/\sqrt{125}^2$ $B=k3*10^{-9}/5^2$

12. anonymous

The whole purpose of Openstudy is to surpass the inadequacies of current internet education by expounding concepts to people personally and helping their unique problems. Now that openstudy has been established, any less than that is a failure on the educators' parts.

13. anonymous

Vector addition is simple- put the end of one on the point of the other (in any order), and take the final result.|dw:1346438644261:dw| Think of a parallelogram

14. anonymous

The length of the arrows= the values in the equations above.

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