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haganmc
 2 years ago
What are the strength and direction of the electric field at the position indicated by the dot in the figure (Figure 1) ?
I NEED DIRECTION NOW! Thanks
haganmc
 2 years ago
What are the strength and direction of the electric field at the position indicated by the dot in the figure (Figure 1) ? I NEED DIRECTION NOW! Thanks

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NoelGreco
 2 years ago
Best ResponseYou've already chosen the best response.1\[E = k \frac{ Q }{r ^{2} }\] Calculate that for each point charge. Then we'll add the vectors.

haganmc
 2 years ago
Best ResponseYou've already chosen the best response.0How do you find direction?

haganmc
 2 years ago
Best ResponseYou've already chosen the best response.0the answer is in degrees? I need how to find the angle

NoelGreco
 2 years ago
Best ResponseYou've already chosen the best response.1The direction of an electric field is the direction of the force on a positive test charge placed in the field. In this case the field is directed away from each of the positive charges.

Mikael
 2 years ago
Best ResponseYou've already chosen the best response.0hag  you'd be surprise but there are topics which u actuall y need to read and understand in detail. And this is it

henpen
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1346438409410:dw \[A=k3*10^{9}/\sqrt{125}^2\] \[B=k3*10^{9}/5^2\]

henpen
 2 years ago
Best ResponseYou've already chosen the best response.0The whole purpose of Openstudy is to surpass the inadequacies of current internet education by expounding concepts to people personally and helping their unique problems. Now that openstudy has been established, any less than that is a failure on the educators' parts.

henpen
 2 years ago
Best ResponseYou've already chosen the best response.0Vector addition is simple put the end of one on the point of the other (in any order), and take the final result.dw:1346438644261:dw Think of a parallelogram

henpen
 2 years ago
Best ResponseYou've already chosen the best response.0The length of the arrows= the values in the equations above.
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