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haganmc
What are the strength and direction of the electric field at the position indicated by the dot in the figure (Figure 1) ? I NEED DIRECTION NOW! Thanks
\[E = k \frac{ Q }{r ^{2} }\] Calculate that for each point charge. Then we'll add the vectors.
How do you find direction?
the answer is in degrees? I need how to find the angle
The direction of an electric field is the direction of the force on a positive test charge placed in the field. In this case the field is directed away from each of the positive charges.
hag - you'd be surprise but there are topics which u actuall y need to read and understand in detail. And this is it
|dw:1346438409410:dw| \[A=k3*10^{-9}/\sqrt{125}^2\] \[B=k3*10^{-9}/5^2\]
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Vector addition is simple- put the end of one on the point of the other (in any order), and take the final result.|dw:1346438644261:dw| Think of a parallelogram
The length of the arrows= the values in the equations above.