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haganmc

  • 2 years ago

What are the strength and direction of the electric field at the position indicated by the dot in the figure (Figure 1) ? I NEED DIRECTION NOW! Thanks

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  1. haganmc
    • 2 years ago
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  2. NoelGreco
    • 2 years ago
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    \[E = k \frac{ Q }{r ^{2} }\] Calculate that for each point charge. Then we'll add the vectors.

  3. haganmc
    • 2 years ago
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    How do you find direction?

  4. Mikael
    • 2 years ago
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    Addition of vectors

  5. Mikael
    • 2 years ago
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    http://www.youtube.com/watch?v=TAjJO1m4W_k

  6. haganmc
    • 2 years ago
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    the answer is in degrees? I need how to find the angle

  7. NoelGreco
    • 2 years ago
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    The direction of an electric field is the direction of the force on a positive test charge placed in the field. In this case the field is directed away from each of the positive charges.

  8. Mikael
    • 2 years ago
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    hag - you'd be surprise but there are topics which u actuall y need to read and understand in detail. And this is it

  9. Mikael
    • 2 years ago
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    http://www.youtube.com/watch?v=TAjJO1m4W_k

  10. henpen
    • 2 years ago
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    |dw:1346438409410:dw| \[A=k3*10^{-9}/\sqrt{125}^2\] \[B=k3*10^{-9}/5^2\]

  11. henpen
    • 2 years ago
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    The whole purpose of Openstudy is to surpass the inadequacies of current internet education by expounding concepts to people personally and helping their unique problems. Now that openstudy has been established, any less than that is a failure on the educators' parts.

  12. henpen
    • 2 years ago
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    Vector addition is simple- put the end of one on the point of the other (in any order), and take the final result.|dw:1346438644261:dw| Think of a parallelogram

  13. henpen
    • 2 years ago
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    The length of the arrows= the values in the equations above.

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