hiralpatel121
I need help with the attached problem please.



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hiralpatel121
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hartnn
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first use the distributive property twice
\[a(b+c)=ab+ac\]
tell me what u get?

hartnn
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*thrice

dpaInc
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9x + 5(2x + 11) = 3(x + 21) + 2(8x  3)
yep... use distributive property first.... then combine like terms...

hiralpatel121
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9x+10x+55 = 3x+63 + 16x6

dpaInc
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CLT.. combine like terms, then solve for x now....

hartnn
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correct,now combine like terms
9x,10x,3x,16x
55,63,6

hiralpatel121
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Then you get: 19x+55 = 19x+57

hiralpatel121
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Would this be a no solution? Since 19x19x = 0?

hartnn
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thats correct,so now that 19x gets cancelled
and there will be no solution

dpaInc
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nice work...

hiralpatel121
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So the answer is "No Solution" ?

hartnn
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yup :)

hiralpatel121
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Okayy. I need help with 2 more problems.

hartnn
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sure,go ahead and ask

hiralpatel121
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hartnn
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what u got?

hiralpatel121
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I don't know how to solve this..

hartnn
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1.divide by W
2.subtract 2
3.divide by z
all these to both sides

hiralpatel121
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You don't distribute W first?

hartnn
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that would complicate it,though possible.

hiralpatel121
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This is what I got:
G = W (2+zp)
G/W = W(2+zp)/W
G/W – 2 = zp
G/W/z – 2 = p

hartnn
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ok,in last step,u missed dividing z to 2
also
G/W/z=G/Wz

hiralpatel121
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So it would be: G/Wz  2/z = p ?

hartnn
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yup,which u can write as
\[\frac{G2W}{Wz}\]

hiralpatel121
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Okay...one more problem, please.

hiralpatel121
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