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hiralpatel121

  • 2 years ago

I need help with the attached problem please.

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  1. hiralpatel121
    • 2 years ago
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  2. hartnn
    • 2 years ago
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    first use the distributive property twice \[a(b+c)=ab+ac\] tell me what u get?

  3. hartnn
    • 2 years ago
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    *thrice

  4. dpaInc
    • 2 years ago
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    9x + 5(2x + 11) = 3(x + 21) + 2(8x - 3) yep... use distributive property first.... then combine like terms...

  5. hiralpatel121
    • 2 years ago
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    9x+10x+55 = 3x+63 + 16x-6

  6. dpaInc
    • 2 years ago
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    CLT.. combine like terms, then solve for x now....

  7. hartnn
    • 2 years ago
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    correct,now combine like terms 9x,10x,3x,16x 55,63,-6

  8. hiralpatel121
    • 2 years ago
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    Then you get: 19x+55 = 19x+57

  9. hiralpatel121
    • 2 years ago
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    Would this be a no solution? Since 19x-19x = 0?

  10. hartnn
    • 2 years ago
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    thats correct,so now that 19x gets cancelled and there will be no solution

  11. dpaInc
    • 2 years ago
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    nice work...

  12. hiralpatel121
    • 2 years ago
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    So the answer is "No Solution" ?

  13. hartnn
    • 2 years ago
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    yup :)

  14. hiralpatel121
    • 2 years ago
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    Okayy. I need help with 2 more problems.

  15. hartnn
    • 2 years ago
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    sure,go ahead and ask

  16. hiralpatel121
    • 2 years ago
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  17. hartnn
    • 2 years ago
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    what u got?

  18. hiralpatel121
    • 2 years ago
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    I don't know how to solve this..

  19. hartnn
    • 2 years ago
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    1.divide by W 2.subtract 2 3.divide by z all these to both sides

  20. hiralpatel121
    • 2 years ago
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    You don't distribute W first?

  21. hartnn
    • 2 years ago
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    that would complicate it,though possible.

  22. hiralpatel121
    • 2 years ago
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    This is what I got: G = W (2+zp) G/W = W(2+zp)/W G/W – 2 = zp G/W/z – 2 = p

  23. hartnn
    • 2 years ago
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    ok,in last step,u missed dividing z to 2 also G/W/z=G/Wz

  24. hiralpatel121
    • 2 years ago
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    So it would be: G/Wz - 2/z = p ?

  25. hartnn
    • 2 years ago
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    yup,which u can write as \[\frac{G-2W}{Wz}\]

  26. hiralpatel121
    • 2 years ago
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    Okay...one more problem, please.

  27. hiralpatel121
    • 2 years ago
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