Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

I need help with the attached problem please.

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

first use the distributive property twice \[a(b+c)=ab+ac\] tell me what u get?
*thrice

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

9x + 5(2x + 11) = 3(x + 21) + 2(8x - 3) yep... use distributive property first.... then combine like terms...
9x+10x+55 = 3x+63 + 16x-6
CLT.. combine like terms, then solve for x now....
correct,now combine like terms 9x,10x,3x,16x 55,63,-6
Then you get: 19x+55 = 19x+57
Would this be a no solution? Since 19x-19x = 0?
thats correct,so now that 19x gets cancelled and there will be no solution
nice work...
So the answer is "No Solution" ?
yup :)
Okayy. I need help with 2 more problems.
sure,go ahead and ask
what u got?
I don't know how to solve this..
1.divide by W 2.subtract 2 3.divide by z all these to both sides
You don't distribute W first?
that would complicate it,though possible.
This is what I got: G = W (2+zp) G/W = W(2+zp)/W G/W – 2 = zp G/W/z – 2 = p
ok,in last step,u missed dividing z to 2 also G/W/z=G/Wz
So it would be: G/Wz - 2/z = p ?
yup,which u can write as \[\frac{G-2W}{Wz}\]
Okay...one more problem, please.

Not the answer you are looking for?

Search for more explanations.

Ask your own question