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I need help with the attached problem please.

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first use the distributive property twice \[a(b+c)=ab+ac\] tell me what u get?

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Other answers:

9x + 5(2x + 11) = 3(x + 21) + 2(8x - 3) yep... use distributive property first.... then combine like terms...
9x+10x+55 = 3x+63 + 16x-6
CLT.. combine like terms, then solve for x now....
correct,now combine like terms 9x,10x,3x,16x 55,63,-6
Then you get: 19x+55 = 19x+57
Would this be a no solution? Since 19x-19x = 0?
thats correct,so now that 19x gets cancelled and there will be no solution
nice work...
So the answer is "No Solution" ?
yup :)
Okayy. I need help with 2 more problems.
sure,go ahead and ask
what u got?
I don't know how to solve this..
1.divide by W 2.subtract 2 3.divide by z all these to both sides
You don't distribute W first?
that would complicate it,though possible.
This is what I got: G = W (2+zp) G/W = W(2+zp)/W G/W – 2 = zp G/W/z – 2 = p
ok,in last step,u missed dividing z to 2 also G/W/z=G/Wz
So it would be: G/Wz - 2/z = p ?
yup,which u can write as \[\frac{G-2W}{Wz}\] more problem, please.

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