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hiralpatel121

  • 3 years ago

I need help with the attached problem please.

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  1. hiralpatel121
    • 3 years ago
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  2. hartnn
    • 3 years ago
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    lets begin with 13-4x<16 subtract 13 from both sides

  3. hiralpatel121
    • 3 years ago
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    You get: -4x<3

  4. hartnn
    • 3 years ago
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    good,now divide by -4 remember to flip the sign,as u are dividing by a negative number so < becomes >

  5. hiralpatel121
    • 3 years ago
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    You get: x>-3/4

  6. hartnn
    • 3 years ago
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    thats your 1st part 13-4x>= -10 again subtract 13 from both sides

  7. hiralpatel121
    • 3 years ago
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    You get: -4x>-23

  8. hartnn
    • 3 years ago
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    ok,don't forget = sign also now divide by -4 and flip sign

  9. hiralpatel121
    • 3 years ago
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    You get: x< = 23/4

  10. hartnn
    • 3 years ago
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    now can u put the two thing together in interval notation ?

  11. hiralpatel121
    • 3 years ago
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    Like this: First Part: X >-3/4 Second Part: x< = 23/4 Interval Notation: -3/4 < x < 23/4

  12. hartnn
    • 3 years ago
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    let me give example: 2<=x<6 [2,6)

  13. hiralpatel121
    • 3 years ago
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    So... is it: [-3/4, 23/4) ?

  14. hartnn
    • 3 years ago
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    so, -3/4<x<=23/4 will give u (-3/4,23/4]

  15. hartnn
    • 3 years ago
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    as = part is with 23/4,u have ] bracket with 23/4

  16. hartnn
    • 3 years ago
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    got that?

  17. hiralpatel121
    • 3 years ago
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    Okay I got it. I put the bracket for -3/4 before. That's where I went wrong.

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