hiralpatel121
I need help with the attached problem please.



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hiralpatel121
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hartnn
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lets begin with 134x<16
subtract 13 from both sides

hiralpatel121
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You get: 4x<3

hartnn
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good,now divide by 4
remember to flip the sign,as u are dividing by a negative number
so < becomes >

hiralpatel121
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You get: x>3/4

hartnn
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thats your 1st part
134x>= 10
again subtract 13 from both sides

hiralpatel121
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You get: 4x>23

hartnn
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ok,don't forget = sign also
now divide by 4 and flip sign

hiralpatel121
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You get: x< = 23/4

hartnn
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now can u put the two thing together in interval notation ?

hiralpatel121
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Like this:
First Part:
X >3/4
Second Part:
x< = 23/4
Interval Notation:
3/4 < x < 23/4

hartnn
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let me give example:
2<=x<6
[2,6)

hiralpatel121
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So... is it: [3/4, 23/4) ?

hartnn
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so, 3/4<x<=23/4
will give u
(3/4,23/4]

hartnn
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as = part is with 23/4,u have ] bracket with 23/4

hartnn
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got that?

hiralpatel121
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Okay I got it. I put the bracket for 3/4 before. That's where I went wrong.