## hiralpatel121 3 years ago I need help with the attached problem please.

1. hiralpatel121

2. hartnn

lets begin with 13-4x<16 subtract 13 from both sides

3. hiralpatel121

You get: -4x<3

4. hartnn

good,now divide by -4 remember to flip the sign,as u are dividing by a negative number so < becomes >

5. hiralpatel121

You get: x>-3/4

6. hartnn

thats your 1st part 13-4x>= -10 again subtract 13 from both sides

7. hiralpatel121

You get: -4x>-23

8. hartnn

ok,don't forget = sign also now divide by -4 and flip sign

9. hiralpatel121

You get: x< = 23/4

10. hartnn

now can u put the two thing together in interval notation ?

11. hiralpatel121

Like this: First Part: X >-3/4 Second Part: x< = 23/4 Interval Notation: -3/4 < x < 23/4

12. hartnn

let me give example: 2<=x<6 [2,6)

13. hiralpatel121

So... is it: [-3/4, 23/4) ?

14. hartnn

so, -3/4<x<=23/4 will give u (-3/4,23/4]

15. hartnn

as = part is with 23/4,u have ] bracket with 23/4

16. hartnn

got that?

17. hiralpatel121

Okay I got it. I put the bracket for -3/4 before. That's where I went wrong.