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hiralpatel121 Group Title

I need help with the attached problem please.

  • one year ago
  • one year ago

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  1. hiralpatel121 Group Title
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    • one year ago
  2. hartnn Group Title
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    lets begin with 13-4x<16 subtract 13 from both sides

    • one year ago
  3. hiralpatel121 Group Title
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    You get: -4x<3

    • one year ago
  4. hartnn Group Title
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    good,now divide by -4 remember to flip the sign,as u are dividing by a negative number so < becomes >

    • one year ago
  5. hiralpatel121 Group Title
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    You get: x>-3/4

    • one year ago
  6. hartnn Group Title
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    thats your 1st part 13-4x>= -10 again subtract 13 from both sides

    • one year ago
  7. hiralpatel121 Group Title
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    You get: -4x>-23

    • one year ago
  8. hartnn Group Title
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    ok,don't forget = sign also now divide by -4 and flip sign

    • one year ago
  9. hiralpatel121 Group Title
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    You get: x< = 23/4

    • one year ago
  10. hartnn Group Title
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    now can u put the two thing together in interval notation ?

    • one year ago
  11. hiralpatel121 Group Title
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    Like this: First Part: X >-3/4 Second Part: x< = 23/4 Interval Notation: -3/4 < x < 23/4

    • one year ago
  12. hartnn Group Title
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    let me give example: 2<=x<6 [2,6)

    • one year ago
  13. hiralpatel121 Group Title
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    So... is it: [-3/4, 23/4) ?

    • one year ago
  14. hartnn Group Title
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    so, -3/4<x<=23/4 will give u (-3/4,23/4]

    • one year ago
  15. hartnn Group Title
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    as = part is with 23/4,u have ] bracket with 23/4

    • one year ago
  16. hartnn Group Title
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    got that?

    • one year ago
  17. hiralpatel121 Group Title
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    Okay I got it. I put the bracket for -3/4 before. That's where I went wrong.

    • one year ago
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