## KE8717504 3 years ago Divide... 4x^3-8x^2+19 / x-2 please

1. KarlaKalurky

you can use the long method or the synthetic division...

2. KarlaKalurky

let's use synthetic division: REMEMBER to solve for x of the divisor (in this case the divisor is x-2): wherein x = 2 (x-2=0) (x=2) |dw:1345775020773:dw|

3. KarlaKalurky

4. KE8717504

no idea i hate doing these honestly

5. HelpMe94

hello again

6. HelpMe94

|dw:1346381401417:dw|

7. HelpMe94

|dw:1346381459960:dw|

8. HelpMe94

9. KarlaKalurky

you need to become interested.... anyways... i guess you know why 2 is on that very left side... 4, 8, 0, then 19 because 4 has its variable x^3 (highest) 8 has its variable x^2 (second highest) 0 because there should be a variable x but since there's none it is zero 19 is at the end because it has no variable... the answer: (4x^2) +(19)/(x-2)

10. KarlaKalurky

$4x ^{2}+ \frac{ 19 }{ x-2 }$

11. KE8717504

can u put another one in the same format for me please

12. KE8717504

the answer was 2x^2+6x-2 remainder of 7

13. KE8717504

oh on that one they want to know what the quotient is

14. KarlaKalurky

where? 2x^2....?

15. KE8717504

the problem is (2y^3+14y^2+22y-15) / (y+4) it says to find the quotient

16. KarlaKalurky

just like on your first prob. y+4=0 y=?

17. KE8717504

is the quotient 4 then?

18. KarlaKalurky

no...but i'm discussing it step by step... you should know that y=-4

19. KarlaKalurky

and then.... |dw:1345777191348:dw|

20. KE8717504

ok i see that so far