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Divide... 4x^3-8x^2+19 / x-2 please

Mathematics
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you can use the long method or the synthetic division...
let's use synthetic division: REMEMBER to solve for x of the divisor (in this case the divisor is x-2): wherein x = 2 (x-2=0) (x=2) |dw:1345775020773:dw|
give your conclusion...@KE8717504

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Other answers:

no idea i hate doing these honestly
hello again
|dw:1346381401417:dw|
|dw:1346381459960:dw|
Answer: 4 Remainder: 19
you need to become interested.... anyways... i guess you know why 2 is on that very left side... 4, 8, 0, then 19 because 4 has its variable x^3 (highest) 8 has its variable x^2 (second highest) 0 because there should be a variable x but since there's none it is zero 19 is at the end because it has no variable... the answer: (4x^2) +(19)/(x-2)
\[4x ^{2}+ \frac{ 19 }{ x-2 }\]
can u put another one in the same format for me please
the answer was 2x^2+6x-2 remainder of 7
oh on that one they want to know what the quotient is
where? 2x^2....?
the problem is (2y^3+14y^2+22y-15) / (y+4) it says to find the quotient
just like on your first prob. y+4=0 y=?
is the quotient 4 then?
no...but i'm discussing it step by step... you should know that y=-4
and then.... |dw:1345777191348:dw|
ok i see that so far

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