KE8717504
Divide... 4x^3-8x^2+19 / x-2 please
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KarlaKalurky
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you can use the long method or the synthetic division...
KarlaKalurky
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let's use synthetic division:
REMEMBER to solve for x of the divisor (in this case the divisor is x-2):
wherein x = 2
(x-2=0)
(x=2)
|dw:1345775020773:dw|
KarlaKalurky
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give your conclusion...@KE8717504
KE8717504
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no idea i hate doing these honestly
HelpMe94
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hello again
HelpMe94
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|dw:1346381401417:dw|
HelpMe94
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|dw:1346381459960:dw|
HelpMe94
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Answer: 4 Remainder: 19
KarlaKalurky
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you need to become interested....
anyways...
i guess you know why 2 is on that very left side...
4, 8, 0, then 19
because 4 has its variable x^3 (highest)
8 has its variable x^2 (second highest)
0 because there should be a variable x but since there's none it is zero
19 is at the end because it has no variable...
the answer:
(4x^2) +(19)/(x-2)
KarlaKalurky
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\[4x ^{2}+ \frac{ 19 }{ x-2 }\]
KE8717504
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can u put another one in the same format for me please
KE8717504
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the answer was 2x^2+6x-2 remainder of 7
KE8717504
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oh on that one they want to know what the quotient is
KarlaKalurky
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where? 2x^2....?
KE8717504
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the problem is (2y^3+14y^2+22y-15) / (y+4) it says to find the quotient
KarlaKalurky
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just like on your first prob.
y+4=0
y=?
KE8717504
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is the quotient 4 then?
KarlaKalurky
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no...but i'm discussing it step by step...
you should know that
y=-4
KarlaKalurky
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and then....
|dw:1345777191348:dw|
KE8717504
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ok i see that so far