A community for students.
Here's the question you clicked on:
 0 viewing
experimentX
 3 years ago
Prove:
\[ \lim_{N\rightarrow\infty}\sum_{k=1}^N\left(\frac{k1}{N}\right)^N = {1 \over e  1}\]
experimentX
 3 years ago
Prove: \[ \lim_{N\rightarrow\infty}\sum_{k=1}^N\left(\frac{k1}{N}\right)^N = {1 \over e  1}\]

This Question is Closed

zzr0ck3r
 3 years ago
Best ResponseYou've already chosen the best response.1I only know how to prove limits of sequences not series:(

zzr0ck3r
 3 years ago
Best ResponseYou've already chosen the best response.1what a cool series though..

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1yep!! this is very interesting!!

zzr0ck3r
 3 years ago
Best ResponseYou've already chosen the best response.1god we really dont know what we have on our hands with this math stuff.

Herp_Derp
 3 years ago
Best ResponseYou've already chosen the best response.1I messed up on my first one... \[\lim_{N\rightarrow\infty}\left(\frac{k1}{N}\right)^N=\lim_{N\rightarrow\infty}\left(1+\frac{k1N}{N}\right)^N=e^{k1N}.\]

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1you missed the sum. the approach is +ve ... BRB in 3 hrs

Herp_Derp
 3 years ago
Best ResponseYou've already chosen the best response.1And you can use a geometric series from there to get \(\displaystyle \frac{e^{1}}{1e^{1}}\)

Herp_Derp
 3 years ago
Best ResponseYou've already chosen the best response.1I know, it's not very rigorous. I've only learned as much analysis as I've taught myself, so I'm still not very good with proofs...

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1change of limits on the sum is the trick!!

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1sorry.. what do we call that ... k ... counter as in loop

Herp_Derp
 3 years ago
Best ResponseYou've already chosen the best response.1Are you allowed to take the limit through the sum, as I have done?

Herp_Derp
 3 years ago
Best ResponseYou've already chosen the best response.1For example, to go from:\[\large\lim_{x\rightarrow\infty}\sum_{k=0}^\infty f(x)\overset{?}{=}\sum_{k=0}^\infty \lim_{x\rightarrow\infty}f(x)\]

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1this is equivalent to lim n>inf (1  1/n)^n + (1  2/n)^n + (1  3/n)^n + ....

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1let's put a new counter m = N  k + 1 < this counts from opposite.

Herp_Derp
 3 years ago
Best ResponseYou've already chosen the best response.1Yeah, that's what I did too. I didn't know it was called a counter, though.

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1i don't know what it is called either ... may be some incremental variable.

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1in programming ... in loop ... it's called counter... :D
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.