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jhonyy9 Group TitleBest ResponseYou've already chosen the best response.0
what sign the exponent 5 ?
 one year ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.0
so if a^5 =a^2 *a^3 so than how can you writing your exercise ? fdor easy solve it
 one year ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.0
for you can solve it easy
 one year ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.0
let 3 sign a and 2y sign b so than in this case you can writing that (a+b)^5 =(a+b)^2 *(a+b)^3 yes ?
 one year ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.0
so than your exersice will be (3+2y)^5 =(3+2y)^2 *(3+2y)^3 so what you hope so much that  can end it easy ,because you know the formula (a3b)^2 = ??? and formule for (a+b)^3 = ??? ok ? i think that this formules you have learned in your schooles till today ok ?
 one year ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.0
sorry there wann being (a+b)^2 = ???
 one year ago

henpen Group TitleBest ResponseYou've already chosen the best response.0
It will be \[a3^0(2y)^5+ba3^1(2y)^4+ca3^2(2y)^3+da3^3(2y)^2+ea3^4(2y)^1+fa3^5(2y)^0\]
 one year ago

henpen Group TitleBest ResponseYou've already chosen the best response.0
Due to the symmetry of binomial expansion, a=f, b=e and c=d. To find what they ARE without bruteforcing your way expanding the brackets, look at the 5th (as it was ^5) row of Pascal's triangle.
 one year ago

henpen Group TitleBest ResponseYou've already chosen the best response.0
dw:1346412351008:dw
 one year ago

eliassaab Group TitleBest ResponseYou've already chosen the best response.0
http://www.wolframalpha.com/input/?i=expand+%283%2B2y%29^5
 one year ago

muhammad9t5 Group TitleBest ResponseYou've already chosen the best response.0
i just got it myself. BTW thanks all of you.
 one year ago
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