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jhonyy9 Group TitleBest ResponseYou've already chosen the best response.0
what sign the exponent 5 ?
 2 years ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.0
so if a^5 =a^2 *a^3 so than how can you writing your exercise ? fdor easy solve it
 2 years ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.0
for you can solve it easy
 2 years ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.0
let 3 sign a and 2y sign b so than in this case you can writing that (a+b)^5 =(a+b)^2 *(a+b)^3 yes ?
 2 years ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.0
so than your exersice will be (3+2y)^5 =(3+2y)^2 *(3+2y)^3 so what you hope so much that  can end it easy ,because you know the formula (a3b)^2 = ??? and formule for (a+b)^3 = ??? ok ? i think that this formules you have learned in your schooles till today ok ?
 2 years ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.0
sorry there wann being (a+b)^2 = ???
 2 years ago

henpen Group TitleBest ResponseYou've already chosen the best response.0
It will be \[a3^0(2y)^5+ba3^1(2y)^4+ca3^2(2y)^3+da3^3(2y)^2+ea3^4(2y)^1+fa3^5(2y)^0\]
 2 years ago

henpen Group TitleBest ResponseYou've already chosen the best response.0
Due to the symmetry of binomial expansion, a=f, b=e and c=d. To find what they ARE without bruteforcing your way expanding the brackets, look at the 5th (as it was ^5) row of Pascal's triangle.
 2 years ago

henpen Group TitleBest ResponseYou've already chosen the best response.0
dw:1346412351008:dw
 2 years ago

eliassaab Group TitleBest ResponseYou've already chosen the best response.0
http://www.wolframalpha.com/input/?i=expand+%283%2B2y%29^5
 2 years ago

muhammad9t5 Group TitleBest ResponseYou've already chosen the best response.0
i just got it myself. BTW thanks all of you.
 one year ago
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