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lindseyharrison
Group Title
What is the simplified form of x^2  16 / x + 4
 one year ago
 one year ago
lindseyharrison Group Title
What is the simplified form of x^2  16 / x + 4
 one year ago
 one year ago

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jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.2
Hint: x^2  16 x^2  4^2 (x4)(x+4)
 one year ago

lindseyharrison Group TitleBest ResponseYou've already chosen the best response.0
x  4, with the restriction x ≠ 4 x + 4, with the restriction x ≠  4 x  4, with the restriction x ≠  4 x + 4, with the restriction x ≠ 4
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.2
I'm using the difference of squares rule
 one year ago

lindseyharrison Group TitleBest ResponseYou've already chosen the best response.0
@jim_thompson5910 is it A?
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.2
it is x4, but the restriction is not x ≠ 4 since 4 is a perfectly valid input in the original expression
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.2
x+4 = 0 x = 4 is the value that makes the denominator zero, so this is the restricted value
 one year ago

lindseyharrison Group TitleBest ResponseYou've already chosen the best response.0
So it would be C
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.2
yes, it's C
 one year ago

moha_10 Group TitleBest ResponseYou've already chosen the best response.0
@jim_thompson5910 can u plz explain me more i'm confused
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.2
which part are you confused about?
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.2
if you want, you can ask the question in a separate post
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.2
\[\Large \frac{x^2  16}{x+4}\] \[\Large \frac{x^2  4^2}{x+4}\] \[\Large \frac{(x4)(x+4)}{x+4}\] \[\Large \frac{(x4)\cancel{(x+4)}}{\cancel{x+4}}\] \[\Large x4\] So \[\Large \frac{x^2  16}{x+4}\] simplifies to \[\Large x4\] Keep in mind that x cannot equal 4 in the original expression. So for the two expressions to be completely equivalent, x cannot equal 4 in the final expression.
 one year ago
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