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anonymous
 4 years ago
What is the simplified form of x^2  16 / x + 4
anonymous
 4 years ago
What is the simplified form of x^2  16 / x + 4

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jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.2Hint: x^2  16 x^2  4^2 (x4)(x+4)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0x  4, with the restriction x ≠ 4 x + 4, with the restriction x ≠  4 x  4, with the restriction x ≠  4 x + 4, with the restriction x ≠ 4

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.2I'm using the difference of squares rule

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@jim_thompson5910 is it A?

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.2it is x4, but the restriction is not x ≠ 4 since 4 is a perfectly valid input in the original expression

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.2x+4 = 0 x = 4 is the value that makes the denominator zero, so this is the restricted value

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@jim_thompson5910 can u plz explain me more i'm confused

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.2which part are you confused about?

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.2if you want, you can ask the question in a separate post

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.2\[\Large \frac{x^2  16}{x+4}\] \[\Large \frac{x^2  4^2}{x+4}\] \[\Large \frac{(x4)(x+4)}{x+4}\] \[\Large \frac{(x4)\cancel{(x+4)}}{\cancel{x+4}}\] \[\Large x4\] So \[\Large \frac{x^2  16}{x+4}\] simplifies to \[\Large x4\] Keep in mind that x cannot equal 4 in the original expression. So for the two expressions to be completely equivalent, x cannot equal 4 in the final expression.
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