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lindseyharrison Group Title

What is the simplified form of x^2 - 16 / x + 4

  • one year ago
  • one year ago

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  1. jim_thompson5910 Group Title
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    Hint: x^2 - 16 x^2 - 4^2 (x-4)(x+4)

    • one year ago
  2. lindseyharrison Group Title
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    x - 4, with the restriction x ≠ 4 x + 4, with the restriction x ≠ - 4 x - 4, with the restriction x ≠ - 4 x + 4, with the restriction x ≠ 4

    • one year ago
  3. jim_thompson5910 Group Title
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    I'm using the difference of squares rule

    • one year ago
  4. lindseyharrison Group Title
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    @jim_thompson5910 is it A?

    • one year ago
  5. jim_thompson5910 Group Title
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    it is x-4, but the restriction is not x ≠ 4 since 4 is a perfectly valid input in the original expression

    • one year ago
  6. jim_thompson5910 Group Title
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    x+4 = 0 x = -4 is the value that makes the denominator zero, so this is the restricted value

    • one year ago
  7. lindseyharrison Group Title
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    So it would be C

    • one year ago
  8. jim_thompson5910 Group Title
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    yes, it's C

    • one year ago
  9. moha_10 Group Title
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    @jim_thompson5910 can u plz explain me more i'm confused

    • one year ago
  10. jim_thompson5910 Group Title
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    which part are you confused about?

    • one year ago
  11. jim_thompson5910 Group Title
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    if you want, you can ask the question in a separate post

    • one year ago
  12. moha_10 Group Title
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    all

    • one year ago
  13. jim_thompson5910 Group Title
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    \[\Large \frac{x^2 - 16}{x+4}\] \[\Large \frac{x^2 - 4^2}{x+4}\] \[\Large \frac{(x-4)(x+4)}{x+4}\] \[\Large \frac{(x-4)\cancel{(x+4)}}{\cancel{x+4}}\] \[\Large x-4\] So \[\Large \frac{x^2 - 16}{x+4}\] simplifies to \[\Large x-4\] Keep in mind that x cannot equal -4 in the original expression. So for the two expressions to be completely equivalent, x cannot equal -4 in the final expression.

    • one year ago
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