Here's the question you clicked on:
lindseyharrison
What is the simplified form of x^2 - 16 / x + 4
Hint: x^2 - 16 x^2 - 4^2 (x-4)(x+4)
x - 4, with the restriction x ≠ 4 x + 4, with the restriction x ≠ - 4 x - 4, with the restriction x ≠ - 4 x + 4, with the restriction x ≠ 4
I'm using the difference of squares rule
@jim_thompson5910 is it A?
it is x-4, but the restriction is not x ≠ 4 since 4 is a perfectly valid input in the original expression
x+4 = 0 x = -4 is the value that makes the denominator zero, so this is the restricted value
So it would be C
@jim_thompson5910 can u plz explain me more i'm confused
which part are you confused about?
if you want, you can ask the question in a separate post
\[\Large \frac{x^2 - 16}{x+4}\] \[\Large \frac{x^2 - 4^2}{x+4}\] \[\Large \frac{(x-4)(x+4)}{x+4}\] \[\Large \frac{(x-4)\cancel{(x+4)}}{\cancel{x+4}}\] \[\Large x-4\] So \[\Large \frac{x^2 - 16}{x+4}\] simplifies to \[\Large x-4\] Keep in mind that x cannot equal -4 in the original expression. So for the two expressions to be completely equivalent, x cannot equal -4 in the final expression.