lindseyharrison
x^2 - 1/9x all over x^2 + 2x + 1/ 3x^2
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lindseyharrison
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|dw:1346439066411:dw|
moser90
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start by factoring
lindseyharrison
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I"m running out of time and stressing out!
moser90
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can't just give you the answer sorry you have to at least try
CliffSedge
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I'd actually recommend using\[\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{ad}{bc}\] first, and then factoring.
moser90
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I forgot that step thanks now I know an easier why
CliffSedge
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But it doesn't really matter, commutative property and whatnot..
radar
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|dw:1346439505981:dw|
radar
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Start factoring and canceling.
radar
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If you will do the numerator, I will do the denominator.
CliffSedge
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I got a numerator of higher degree than denominator, so I converted it to a mixed number. I don't think that's necessary though; usually with rational expressions, leaving everything in factored form as improper fractions is more convenient.
radar
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@lindseyharrison , the ball is in your court.
lindseyharrison
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5x^4/4y^3
radar
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|dw:1346439990509:dw|
radar
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|dw:1346440061907:dw|
radar
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|dw:1346440122163:dw| What do you have left?
radar
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|dw:1346440255206:dw|
lindseyharrison
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a) 4y^3/5x^4
b) 4y^4/5x^3
c) 5x^4/4y^3
d) 5x^3/4y^4
lindseyharrison
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those are my options
radar
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You are looking at the wrong answers. There is not a y in you problem. Please look at the problem you have entered in the problem box!
lindseyharrison
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well that explains a lot lol
lindseyharrison
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x(x+1/3(x-1)
3x(x+1)/(x-1)
x(x-1)/x(x+1)
(x-1)/3x(x+1)
lindseyharrison
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So it's C!
radar
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I don't agree with C, but then again I don't agree with a lot of things. You will notice that C can be further simplified by a division of x to both numerator and denominator.
radar
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Are you sure that you copied D. correctly?
CliffSedge
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Yeah, there's a typo in there.
radar
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I think you are right @CliffSedge
radar
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I really don't see a correct answer lol.
radar
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Or on the other hand there may be an error in the solution???
radar
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If D were: x(x-1)/3(x+1)
It would be more acceptable.