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x^2 - 1/9x all over x^2 + 2x + 1/ 3x^2

Mathematics
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|dw:1346439066411:dw|
start by factoring
I"m running out of time and stressing out!

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Other answers:

Then you should use WolframAlpha. http://wolframalpha.com
can't just give you the answer sorry you have to at least try
I'd actually recommend using\[\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{ad}{bc}\] first, and then factoring.
I forgot that step thanks now I know an easier why
But it doesn't really matter, commutative property and whatnot..
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Start factoring and canceling.
If you will do the numerator, I will do the denominator.
I got a numerator of higher degree than denominator, so I converted it to a mixed number. I don't think that's necessary though; usually with rational expressions, leaving everything in factored form as improper fractions is more convenient.
@lindseyharrison , the ball is in your court.
5x^4/4y^3
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|dw:1346440061907:dw|
|dw:1346440122163:dw| What do you have left?
|dw:1346440255206:dw|
a) 4y^3/5x^4 b) 4y^4/5x^3 c) 5x^4/4y^3 d) 5x^3/4y^4
those are my options
You are looking at the wrong answers. There is not a y in you problem. Please look at the problem you have entered in the problem box!
well that explains a lot lol
x(x+1/3(x-1) 3x(x+1)/(x-1) x(x-1)/x(x+1) (x-1)/3x(x+1)
So it's C!
I don't agree with C, but then again I don't agree with a lot of things. You will notice that C can be further simplified by a division of x to both numerator and denominator.
Are you sure that you copied D. correctly?
Yeah, there's a typo in there.
I think you are right @CliffSedge
I really don't see a correct answer lol.
Or on the other hand there may be an error in the solution???
If D were: x(x-1)/3(x+1) It would be more acceptable.

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