## lindseyharrison Group Title x^2 - 1/9x all over x^2 + 2x + 1/ 3x^2 2 years ago 2 years ago

1. lindseyharrison

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2. moser90

start by factoring

3. lindseyharrison

I"m running out of time and stressing out!

4. ParthKohli

Then you should use WolframAlpha. http://wolframalpha.com

5. moser90

can't just give you the answer sorry you have to at least try

6. CliffSedge

I'd actually recommend using$\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{ad}{bc}$ first, and then factoring.

7. moser90

I forgot that step thanks now I know an easier why

8. CliffSedge

But it doesn't really matter, commutative property and whatnot..

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Start factoring and canceling.

If you will do the numerator, I will do the denominator.

12. CliffSedge

I got a numerator of higher degree than denominator, so I converted it to a mixed number. I don't think that's necessary though; usually with rational expressions, leaving everything in factored form as improper fractions is more convenient.

@lindseyharrison , the ball is in your court.

14. lindseyharrison

5x^4/4y^3

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|dw:1346440122163:dw| What do you have left?

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19. lindseyharrison

a) 4y^3/5x^4 b) 4y^4/5x^3 c) 5x^4/4y^3 d) 5x^3/4y^4

20. lindseyharrison

those are my options

You are looking at the wrong answers. There is not a y in you problem. Please look at the problem you have entered in the problem box!

22. lindseyharrison

well that explains a lot lol

23. lindseyharrison

x(x+1/3(x-1) 3x(x+1)/(x-1) x(x-1)/x(x+1) (x-1)/3x(x+1)

24. lindseyharrison

So it's C!

I don't agree with C, but then again I don't agree with a lot of things. You will notice that C can be further simplified by a division of x to both numerator and denominator.

Are you sure that you copied D. correctly?

27. CliffSedge

Yeah, there's a typo in there.

I think you are right @CliffSedge

I really don't see a correct answer lol.