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eigenschmeigen Group TitleBest ResponseYou've already chosen the best response.0
tan(x) does not tend to a limit as x tends to infinity. tan is periodic remember? dw:1346458442949:dw
 2 years ago

virtus Group TitleBest ResponseYou've already chosen the best response.0
because the answer says pi/2, but i don't get why that is
 2 years ago

eigenschmeigen Group TitleBest ResponseYou've already chosen the best response.0
i think you mean inverse tan
 2 years ago

eigenschmeigen Group TitleBest ResponseYou've already chosen the best response.0
or tan^1
 2 years ago

eigenschmeigen Group TitleBest ResponseYou've already chosen the best response.0
or arctan
 2 years ago

eigenschmeigen Group TitleBest ResponseYou've already chosen the best response.0
all names for the same thing
 2 years ago

virtus Group TitleBest ResponseYou've already chosen the best response.0
yes sorry thats what i had meant, could you please explain
 2 years ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.0
http://www.wolframalpha.com/input/?i=graph+arctan+x
 2 years ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.0
these graphs might help
 2 years ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.0
the idea is \[ \large \lim_{x\to\pi/2}\tan x=+\infty \] \[ \large \lim_{x\to\pi/2}\tan x=\infty \] then \[ \large \lim_{x\to+\infty}\arctan x=\frac{\pi}{2} \] \[ \large \lim_{x\to\infty}\arctan x=\frac{\pi}{2} \]
 2 years ago
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