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virtus

tan (infinity) =?

  • one year ago
  • one year ago

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  1. eigenschmeigen
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    tan(x) does not tend to a limit as x tends to infinity. tan is periodic remember? |dw:1346458442949:dw|

    • one year ago
  2. virtus
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    because the answer says pi/2, but i don't get why that is

    • one year ago
  3. eigenschmeigen
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    i think you mean inverse tan

    • one year ago
  4. eigenschmeigen
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    or tan^-1

    • one year ago
  5. eigenschmeigen
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    or arctan

    • one year ago
  6. eigenschmeigen
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    all names for the same thing

    • one year ago
  7. virtus
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    yes sorry thats what i had meant, could you please explain

    • one year ago
  8. helder_edwin
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    http://www.wolframalpha.com/input/?i=graph+arctan+x

    • one year ago
  9. helder_edwin
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    these graphs might help

    • one year ago
  10. helder_edwin
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    the idea is \[ \large \lim_{x\to\pi/2}\tan x=+\infty \] \[ \large \lim_{x\to-\pi/2}\tan x=-\infty \] then \[ \large \lim_{x\to+\infty}\arctan x=\frac{\pi}{2} \] \[ \large \lim_{x\to-\infty}\arctan x=-\frac{\pi}{2} \]

    • one year ago
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