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eigenschmeigenBest ResponseYou've already chosen the best response.0
tan(x) does not tend to a limit as x tends to infinity. tan is periodic remember? dw:1346458442949:dw
 one year ago

virtusBest ResponseYou've already chosen the best response.0
because the answer says pi/2, but i don't get why that is
 one year ago

eigenschmeigenBest ResponseYou've already chosen the best response.0
i think you mean inverse tan
 one year ago

eigenschmeigenBest ResponseYou've already chosen the best response.0
all names for the same thing
 one year ago

virtusBest ResponseYou've already chosen the best response.0
yes sorry thats what i had meant, could you please explain
 one year ago

helder_edwinBest ResponseYou've already chosen the best response.0
http://www.wolframalpha.com/input/?i=graph+arctan+x
 one year ago

helder_edwinBest ResponseYou've already chosen the best response.0
these graphs might help
 one year ago

helder_edwinBest ResponseYou've already chosen the best response.0
the idea is \[ \large \lim_{x\to\pi/2}\tan x=+\infty \] \[ \large \lim_{x\to\pi/2}\tan x=\infty \] then \[ \large \lim_{x\to+\infty}\arctan x=\frac{\pi}{2} \] \[ \large \lim_{x\to\infty}\arctan x=\frac{\pi}{2} \]
 one year ago
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