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eigenschmeigen
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tan(x) does not tend to a limit as x tends to infinity. tan is periodic remember?
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virtus
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because the answer says pi/2, but i don't get why that is

eigenschmeigen
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i think you mean inverse tan

eigenschmeigen
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or tan^1

eigenschmeigen
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or arctan

eigenschmeigen
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all names for the same thing

virtus
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yes sorry thats what i had meant, could you please explain


helder_edwin
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these graphs might help

helder_edwin
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the idea is
\[ \large \lim_{x\to\pi/2}\tan x=+\infty \]
\[ \large \lim_{x\to\pi/2}\tan x=\infty \]
then
\[ \large \lim_{x\to+\infty}\arctan x=\frac{\pi}{2} \]
\[ \large \lim_{x\to\infty}\arctan x=\frac{\pi}{2} \]