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eigenschmeigen
 2 years ago
Best ResponseYou've already chosen the best response.0tan(x) does not tend to a limit as x tends to infinity. tan is periodic remember? dw:1346458442949:dw

virtus
 2 years ago
Best ResponseYou've already chosen the best response.0because the answer says pi/2, but i don't get why that is

eigenschmeigen
 2 years ago
Best ResponseYou've already chosen the best response.0i think you mean inverse tan

eigenschmeigen
 2 years ago
Best ResponseYou've already chosen the best response.0all names for the same thing

virtus
 2 years ago
Best ResponseYou've already chosen the best response.0yes sorry thats what i had meant, could you please explain

helder_edwin
 2 years ago
Best ResponseYou've already chosen the best response.0these graphs might help

helder_edwin
 2 years ago
Best ResponseYou've already chosen the best response.0the idea is \[ \large \lim_{x\to\pi/2}\tan x=+\infty \] \[ \large \lim_{x\to\pi/2}\tan x=\infty \] then \[ \large \lim_{x\to+\infty}\arctan x=\frac{\pi}{2} \] \[ \large \lim_{x\to\infty}\arctan x=\frac{\pi}{2} \]
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