I don't understand what they want me to do or where to begin. Pre-calculus maybe a proof not sure

- anonymous

I don't understand what they want me to do or where to begin. Pre-calculus maybe a proof not sure

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- precal

with what

- precal

post your math question and I will try to help you

- anonymous

its attached

##### 1 Attachment

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## More answers

- precal

what course is this? looks like you are doing a proof

- anonymous

this is pre-caculus

- anonymous

calculus

- precal

calculus or precal?

- anonymous

sorry for the confusion precalculus

- precal

ok did not look like calculus

- precal

looks like I might not be able to help after all but I can tell you that they multiply d to both sides to get this|dw:1346461339585:dw|

- precal

not sure what is going on after that, I find all of those blanks confusing

- precal

don't they have a lecture part prior to this?

- anonymous

I am supposed to fill in the blanks

- precal

yes, I realize that but I am not following the logic to it. I am sure they are applying many algebraic properties along the way

- anonymous

Well thanks anyway dude

- precal

sorry, maybe someone else will come help you. You can always close this problem and repost it but it might help if you write it out using draw (some people will not open attachments). btw I am a girl

- anonymous

alright I think I'll take my chances with the attachment since it would take me forever to write that out and it might not even be legible

- anonymous

where does it say add a?

- anonymous

Ill take that on faith for now

- helder_edwin

it is on the third line to the right

- helder_edwin

it also says simplify

- anonymous

"Adding a to both sides and simplifying, we see that" I see but I'm not sure what to do still. What do they want me to do for the next line?

- anonymous

put a common denominator on a?

- helder_edwin

no. just what i wrote.

- anonymous

Thanks I think I get it now.

- helder_edwin

then \(b+d\) passes to the other side to divide
\[ \large \frac{a}{b}<\frac{a+c}{b+d} \]

- helder_edwin

this covers the first part :)

- anonymous

is the second part different?

- anonymous

concept wise

- helder_edwin

not at all, try it.

- anonymous

Thanks alot. I'm new. Should I keep the question open? Until I work it out?

- helder_edwin

it's up to u.
i'll be here for one more hour or so.

- anonymous

sweet thanks

- helder_edwin

do u know how to call someone's atention??

- helder_edwin

write @ to the left of his "name".
like this @znimon

- anonymous

@helder_edwin it says my lines 3(half of line 3) and 4 are wrong. I have (b+d)/b and in the last blank I have (ab+cb)/(b+d)

- anonymous

of part 1

- helder_edwin

the first two blanks (line 3) should be \(a\)

- anonymous

ok says my 5th and 7th blanks are wrong

- helder_edwin

next line should be
\[ \large ab+ad\qquad\text{and}\qquad a \]

- anonymous

have that

- helder_edwin

next line should be
\[ \large b+d\qquad\text{and}\qquad a \]

- anonymous

why isn't b+d divided by b

- helder_edwin

u r factoring a from the denominator and just puting the dominator (b) under what u just factored

- anonymous

hmm I don't really get it

- helder_edwin

it is this
\[ \large \frac{r\cdot s}{m}=\frac{r}{m}\cdot s \]

- anonymous

oh I get it not breaking the number into its prime factors

- helder_edwin

so
\[ \large \frac{ab+ad}{b}=\frac{a(b+d)}{b}=\frac{a}{b}\cdot(b+d) \]

- anonymous

now*

- anonymous

got it thanks

- anonymous

so the final blank should be (a+c)/b+d

- helder_edwin

the next (last) line would be
\[ \large \frac{a+c}{b+d} \]

- helder_edwin

yes

- anonymous

hurray

- helder_edwin

now do the next part

- anonymous

ok

- helder_edwin

as i told u it's very similar

- anonymous

first two lines should both be c

- helder_edwin

yes

- helder_edwin

@znimon next??

- anonymous

finished

- helder_edwin

great.

- anonymous

@helder_edwin finished and all correct

- anonymous

thanks again

- helder_edwin

u r welcome

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