znimon
I don't understand what they want me to do or where to begin. Pre-calculus maybe a proof not sure
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precal
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with what
precal
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post your math question and I will try to help you
znimon
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its attached
precal
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what course is this? looks like you are doing a proof
znimon
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this is pre-caculus
znimon
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calculus
precal
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calculus or precal?
znimon
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sorry for the confusion precalculus
precal
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ok did not look like calculus
precal
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looks like I might not be able to help after all but I can tell you that they multiply d to both sides to get this|dw:1346461339585:dw|
precal
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not sure what is going on after that, I find all of those blanks confusing
precal
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don't they have a lecture part prior to this?
znimon
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I am supposed to fill in the blanks
precal
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yes, I realize that but I am not following the logic to it. I am sure they are applying many algebraic properties along the way
znimon
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Well thanks anyway dude
precal
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sorry, maybe someone else will come help you. You can always close this problem and repost it but it might help if you write it out using draw (some people will not open attachments). btw I am a girl
znimon
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alright I think I'll take my chances with the attachment since it would take me forever to write that out and it might not even be legible
helder_edwin
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it says add \(a\) to both sides so the 3rd line would be
\[ \large a+\frac{ad}{b}<a+c \]
znimon
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where does it say add a?
znimon
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Ill take that on faith for now
helder_edwin
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it is on the third line to the right
helder_edwin
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it also says simplify
znimon
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"Adding a to both sides and simplifying, we see that" I see but I'm not sure what to do still. What do they want me to do for the next line?
znimon
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put a common denominator on a?
helder_edwin
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no. just what i wrote.
helder_edwin
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then add the fractions on the left side
\[ \large \frac{ab+ad}{b}<a+c \]
helder_edwin
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then factor \(a\)
\[ \large \frac{a}{b}\cdot(b+d)<a+c \]
znimon
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Thanks I think I get it now.
helder_edwin
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then \(b+d\) passes to the other side to divide
\[ \large \frac{a}{b}<\frac{a+c}{b+d} \]
helder_edwin
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this covers the first part :)
znimon
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is the second part different?
znimon
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concept wise
helder_edwin
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not at all, try it.
znimon
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Thanks alot. I'm new. Should I keep the question open? Until I work it out?
helder_edwin
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it's up to u.
i'll be here for one more hour or so.
znimon
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sweet thanks
helder_edwin
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do u know how to call someone's atention??
helder_edwin
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write @ to the left of his "name".
like this @znimon
znimon
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@helder_edwin it says my lines 3(half of line 3) and 4 are wrong. I have (b+d)/b and in the last blank I have (ab+cb)/(b+d)
znimon
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of part 1
helder_edwin
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the first two blanks (line 3) should be \(a\)
znimon
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ok says my 5th and 7th blanks are wrong
helder_edwin
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next line should be
\[ \large ab+ad\qquad\text{and}\qquad a \]
znimon
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have that
helder_edwin
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next line should be
\[ \large b+d\qquad\text{and}\qquad a \]
znimon
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why isn't b+d divided by b
helder_edwin
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u r factoring a from the denominator and just puting the dominator (b) under what u just factored
znimon
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hmm I don't really get it
helder_edwin
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it is this
\[ \large \frac{r\cdot s}{m}=\frac{r}{m}\cdot s \]
znimon
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oh I get it not breaking the number into its prime factors
helder_edwin
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so
\[ \large \frac{ab+ad}{b}=\frac{a(b+d)}{b}=\frac{a}{b}\cdot(b+d) \]
znimon
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now*
znimon
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got it thanks
znimon
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so the final blank should be (a+c)/b+d
helder_edwin
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the next (last) line would be
\[ \large \frac{a+c}{b+d} \]
helder_edwin
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yes
znimon
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hurray
helder_edwin
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now do the next part
znimon
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ok
helder_edwin
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as i told u it's very similar
znimon
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first two lines should both be c
helder_edwin
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yes
helder_edwin
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@znimon next??
znimon
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finished
helder_edwin
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great.
znimon
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@helder_edwin finished and all correct
znimon
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thanks again
helder_edwin
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u r welcome