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znimon

  • 2 years ago

I don't understand what they want me to do or where to begin. Pre-calculus maybe a proof not sure

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  1. precal
    • 2 years ago
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    with what

  2. precal
    • 2 years ago
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    post your math question and I will try to help you

  3. znimon
    • 2 years ago
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    its attached

    1 Attachment
  4. precal
    • 2 years ago
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    what course is this? looks like you are doing a proof

  5. znimon
    • 2 years ago
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    this is pre-caculus

  6. znimon
    • 2 years ago
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    calculus

  7. precal
    • 2 years ago
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    calculus or precal?

  8. znimon
    • 2 years ago
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    sorry for the confusion precalculus

  9. precal
    • 2 years ago
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    ok did not look like calculus

  10. precal
    • 2 years ago
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    looks like I might not be able to help after all but I can tell you that they multiply d to both sides to get this|dw:1346461339585:dw|

  11. precal
    • 2 years ago
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    not sure what is going on after that, I find all of those blanks confusing

  12. precal
    • 2 years ago
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    don't they have a lecture part prior to this?

  13. znimon
    • 2 years ago
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    I am supposed to fill in the blanks

  14. precal
    • 2 years ago
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    yes, I realize that but I am not following the logic to it. I am sure they are applying many algebraic properties along the way

  15. znimon
    • 2 years ago
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    Well thanks anyway dude

  16. precal
    • 2 years ago
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    sorry, maybe someone else will come help you. You can always close this problem and repost it but it might help if you write it out using draw (some people will not open attachments). btw I am a girl

  17. znimon
    • 2 years ago
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    alright I think I'll take my chances with the attachment since it would take me forever to write that out and it might not even be legible

  18. helder_edwin
    • 2 years ago
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    it says add \(a\) to both sides so the 3rd line would be \[ \large a+\frac{ad}{b}<a+c \]

  19. znimon
    • 2 years ago
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    where does it say add a?

  20. znimon
    • 2 years ago
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    Ill take that on faith for now

  21. helder_edwin
    • 2 years ago
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    it is on the third line to the right

  22. helder_edwin
    • 2 years ago
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    it also says simplify

  23. znimon
    • 2 years ago
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    "Adding a to both sides and simplifying, we see that" I see but I'm not sure what to do still. What do they want me to do for the next line?

  24. znimon
    • 2 years ago
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    put a common denominator on a?

  25. helder_edwin
    • 2 years ago
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    no. just what i wrote.

  26. helder_edwin
    • 2 years ago
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    then add the fractions on the left side \[ \large \frac{ab+ad}{b}<a+c \]

  27. helder_edwin
    • 2 years ago
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    then factor \(a\) \[ \large \frac{a}{b}\cdot(b+d)<a+c \]

  28. znimon
    • 2 years ago
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    Thanks I think I get it now.

  29. helder_edwin
    • 2 years ago
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    then \(b+d\) passes to the other side to divide \[ \large \frac{a}{b}<\frac{a+c}{b+d} \]

  30. helder_edwin
    • 2 years ago
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    this covers the first part :)

  31. znimon
    • 2 years ago
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    is the second part different?

  32. znimon
    • 2 years ago
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    concept wise

  33. helder_edwin
    • 2 years ago
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    not at all, try it.

  34. znimon
    • 2 years ago
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    Thanks alot. I'm new. Should I keep the question open? Until I work it out?

  35. helder_edwin
    • 2 years ago
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    it's up to u. i'll be here for one more hour or so.

  36. znimon
    • 2 years ago
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    sweet thanks

  37. helder_edwin
    • 2 years ago
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    do u know how to call someone's atention??

  38. helder_edwin
    • 2 years ago
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    write @ to the left of his "name". like this @znimon

  39. znimon
    • 2 years ago
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    @helder_edwin it says my lines 3(half of line 3) and 4 are wrong. I have (b+d)/b and in the last blank I have (ab+cb)/(b+d)

  40. znimon
    • 2 years ago
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    of part 1

  41. helder_edwin
    • 2 years ago
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    the first two blanks (line 3) should be \(a\)

  42. znimon
    • 2 years ago
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    ok says my 5th and 7th blanks are wrong

  43. helder_edwin
    • 2 years ago
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    next line should be \[ \large ab+ad\qquad\text{and}\qquad a \]

  44. znimon
    • 2 years ago
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    have that

  45. helder_edwin
    • 2 years ago
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    next line should be \[ \large b+d\qquad\text{and}\qquad a \]

  46. znimon
    • 2 years ago
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    why isn't b+d divided by b

  47. helder_edwin
    • 2 years ago
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    u r factoring a from the denominator and just puting the dominator (b) under what u just factored

  48. znimon
    • 2 years ago
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    hmm I don't really get it

  49. helder_edwin
    • 2 years ago
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    it is this \[ \large \frac{r\cdot s}{m}=\frac{r}{m}\cdot s \]

  50. znimon
    • 2 years ago
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    oh I get it not breaking the number into its prime factors

  51. helder_edwin
    • 2 years ago
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    so \[ \large \frac{ab+ad}{b}=\frac{a(b+d)}{b}=\frac{a}{b}\cdot(b+d) \]

  52. znimon
    • 2 years ago
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    now*

  53. znimon
    • 2 years ago
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    got it thanks

  54. znimon
    • 2 years ago
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    so the final blank should be (a+c)/b+d

  55. helder_edwin
    • 2 years ago
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    the next (last) line would be \[ \large \frac{a+c}{b+d} \]

  56. helder_edwin
    • 2 years ago
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    yes

  57. znimon
    • 2 years ago
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    hurray

  58. helder_edwin
    • 2 years ago
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    now do the next part

  59. znimon
    • 2 years ago
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    ok

  60. helder_edwin
    • 2 years ago
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    as i told u it's very similar

  61. znimon
    • 2 years ago
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    first two lines should both be c

  62. helder_edwin
    • 2 years ago
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    yes

  63. helder_edwin
    • 2 years ago
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    @znimon next??

  64. znimon
    • 2 years ago
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    finished

  65. helder_edwin
    • 2 years ago
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    great.

  66. znimon
    • 2 years ago
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    @helder_edwin finished and all correct

  67. znimon
    • 2 years ago
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    thanks again

  68. helder_edwin
    • 2 years ago
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    u r welcome

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