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with what

post your math question and I will try to help you

its attached

what course is this? looks like you are doing a proof

this is pre-caculus

calculus

calculus or precal?

sorry for the confusion precalculus

ok did not look like calculus

not sure what is going on after that, I find all of those blanks confusing

don't they have a lecture part prior to this?

I am supposed to fill in the blanks

Well thanks anyway dude

where does it say add a?

Ill take that on faith for now

it is on the third line to the right

it also says simplify

put a common denominator on a?

no. just what i wrote.

Thanks I think I get it now.

then \(b+d\) passes to the other side to divide
\[ \large \frac{a}{b}<\frac{a+c}{b+d} \]

this covers the first part :)

is the second part different?

concept wise

not at all, try it.

Thanks alot. I'm new. Should I keep the question open? Until I work it out?

it's up to u.
i'll be here for one more hour or so.

sweet thanks

do u know how to call someone's atention??

write @ to the left of his "name".
like this @znimon

of part 1

the first two blanks (line 3) should be \(a\)

ok says my 5th and 7th blanks are wrong

next line should be
\[ \large ab+ad\qquad\text{and}\qquad a \]

have that

next line should be
\[ \large b+d\qquad\text{and}\qquad a \]

why isn't b+d divided by b

u r factoring a from the denominator and just puting the dominator (b) under what u just factored

hmm I don't really get it

it is this
\[ \large \frac{r\cdot s}{m}=\frac{r}{m}\cdot s \]

oh I get it not breaking the number into its prime factors

so
\[ \large \frac{ab+ad}{b}=\frac{a(b+d)}{b}=\frac{a}{b}\cdot(b+d) \]

now*

got it thanks

so the final blank should be (a+c)/b+d

the next (last) line would be
\[ \large \frac{a+c}{b+d} \]

yes

hurray

now do the next part

ok

as i told u it's very similar

first two lines should both be c

yes

@znimon next??

finished

great.

@helder_edwin finished and all correct

thanks again

u r welcome