Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
lildancngurl
Group Title
No matter how hard I try I can not figure out how to factor this: 4a^232a+63. Any help please? Thanks so much. Please explain the steps!
 one year ago
 one year ago
lildancngurl Group Title
No matter how hard I try I can not figure out how to factor this: 4a^232a+63. Any help please? Thanks so much. Please explain the steps!
 one year ago
 one year ago

This Question is Closed

znimon Group TitleBest ResponseYou've already chosen the best response.1
(2 a9) (2 a7)
 one year ago

znimon Group TitleBest ResponseYou've already chosen the best response.1
So take the coefficient on the a squared term and multiply that to 63 you need to find two number (we will call them A and B) such that A * B = 4 * 63 and A + B = 32
 one year ago

znimon Group TitleBest ResponseYou've already chosen the best response.1
you do this with other polynomials but the coefficient on the squared term is usually a 1so most people don't teach it that way.
 one year ago

lildancngurl Group TitleBest ResponseYou've already chosen the best response.0
You are fabulous. Thank you so much! No matter how hard I tried, I could not understand it. You've made it so much simpler!
 one year ago

znimon Group TitleBest ResponseYou've already chosen the best response.1
Your welcome.
 one year ago

lildancngurl Group TitleBest ResponseYou've already chosen the best response.0
I do have one more question...The two numbers I got were 14 and 18.. How did you get 7 and 9 from that?
 one year ago

precal Group TitleBest ResponseYou've already chosen the best response.0
znimon is busy at the moment, have you tried to do factor by grouping
 one year ago

precal Group TitleBest ResponseYou've already chosen the best response.0
dw:1346462806136:dw
 one year ago

precal Group TitleBest ResponseYou've already chosen the best response.0
dw:1346462837874:dw
 one year ago

precal Group TitleBest ResponseYou've already chosen the best response.0
dw:1346462861944:dw
 one year ago

precal Group TitleBest ResponseYou've already chosen the best response.0
dw:1346462941803:dw
 one year ago

precal Group TitleBest ResponseYou've already chosen the best response.0
dw:1346462966127:dw
 one year ago

precal Group TitleBest ResponseYou've already chosen the best response.0
hope that helps
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
Alternatively, you can set the expression equal to zero to get \[\Large 4a^232a+63 = 0\] Now solve for 'a' using the quadratic formula \[\Large a = \frac{B\pm\sqrt{B^24AC}}{2A}\] \[\Large a = \frac{(32)\pm\sqrt{(32)^24(4)(63)}}{2(4)}\] \[\Large a = \frac{32\pm\sqrt{10241008}}{8}\] \[\Large a = \frac{32\pm\sqrt{16}}{8}\] \[\Large a = \frac{32+\sqrt{16}}{8} \ \text{or} \ a = \frac{32\sqrt{16}}{8}\] \[\Large a = \frac{32+4}{8} \ \text{or} \ a = \frac{324}{8}\] \[\Large a = \frac{36}{8} \ \text{or} \ a = \frac{28}{8}\] \[\Large a = \frac{9}{2} \ \text{or} \ a = \frac{7}{2}\] Now rearrange to get the right sides equal to zero \[\Large a = \frac{9}{2} \ \text{or} \ a = \frac{7}{2}\] \[\Large 2a = 9 \ \text{or} \ 2a = 7\] \[\Large 2a  9 = 0 \ \text{or} \ 2a  7 = 0\] Finally, use the zero product property to get \[\Large (2a  9)(2a  7) = 0\] So this shows us that \[\Large 4a^232a+63 = 0\] factors to \[\Large (2a  9)(2a  7)\]
 one year ago

lildancngurl Group TitleBest ResponseYou've already chosen the best response.0
Wow, extraordinarily helpful. Thank you!
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.