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nohegarcia

  • 2 years ago

Find the area of the trapezoidal cross-section of the irrigation canal shown below. Your answer will be in terms of h, w, and θ. http://www.webassign.net/hgmcalc5/1-5-049.jpg

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  1. NoelGreco
    • 2 years ago
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    |dw:1346472458903:dw| Can you calculate p from some trig function of theta ("th" is theta in drawing)

  2. nohegarcia
    • 2 years ago
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    1/2*p*h=area?

  3. NoelGreco
    • 2 years ago
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    Yeah, but we really need to use p temporarily. First of all do you see how I got the theta near the p?

  4. nohegarcia
    • 2 years ago
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    its a complmentary angle? sorry im totally lost

  5. NoelGreco
    • 2 years ago
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    No, actually, it's congruent to the theta given in the problem because alternate interior angles of transversals and parallel lines are congruent. Does that ring any bells?

  6. nohegarcia
    • 2 years ago
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    kindof but i dont know why you would do that

  7. NoelGreco
    • 2 years ago
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    Well, if I knew an expression for p, I could say that the long base of the trapezoid was w + 2p, the other base is w, and we have h. That's all you need for the area of a trapezoid.

  8. NoelGreco
    • 2 years ago
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    Isn't \[\tan \theta = \frac{ h }{ p}\]

  9. nohegarcia
    • 2 years ago
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    yeah so what would the area be?

  10. nohegarcia
    • 2 years ago
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    tan(theta)*p/h

  11. nohegarcia
    • 2 years ago
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    @NoelGreco

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