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nohegarcia
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Find the area of the trapezoidal crosssection of the irrigation canal shown below. Your answer will be in terms of h, w, and θ.
http://www.webassign.net/hgmcalc5/15049.jpg
 one year ago
 one year ago
nohegarcia Group Title
Find the area of the trapezoidal crosssection of the irrigation canal shown below. Your answer will be in terms of h, w, and θ. http://www.webassign.net/hgmcalc5/15049.jpg
 one year ago
 one year ago

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NoelGreco Group TitleBest ResponseYou've already chosen the best response.0
dw:1346472458903:dw Can you calculate p from some trig function of theta ("th" is theta in drawing)
 one year ago

nohegarcia Group TitleBest ResponseYou've already chosen the best response.0
1/2*p*h=area?
 one year ago

NoelGreco Group TitleBest ResponseYou've already chosen the best response.0
Yeah, but we really need to use p temporarily. First of all do you see how I got the theta near the p?
 one year ago

nohegarcia Group TitleBest ResponseYou've already chosen the best response.0
its a complmentary angle? sorry im totally lost
 one year ago

NoelGreco Group TitleBest ResponseYou've already chosen the best response.0
No, actually, it's congruent to the theta given in the problem because alternate interior angles of transversals and parallel lines are congruent. Does that ring any bells?
 one year ago

nohegarcia Group TitleBest ResponseYou've already chosen the best response.0
kindof but i dont know why you would do that
 one year ago

NoelGreco Group TitleBest ResponseYou've already chosen the best response.0
Well, if I knew an expression for p, I could say that the long base of the trapezoid was w + 2p, the other base is w, and we have h. That's all you need for the area of a trapezoid.
 one year ago

NoelGreco Group TitleBest ResponseYou've already chosen the best response.0
Isn't \[\tan \theta = \frac{ h }{ p}\]
 one year ago

nohegarcia Group TitleBest ResponseYou've already chosen the best response.0
yeah so what would the area be?
 one year ago

nohegarcia Group TitleBest ResponseYou've already chosen the best response.0
tan(theta)*p/h
 one year ago

nohegarcia Group TitleBest ResponseYou've already chosen the best response.0
@NoelGreco
 one year ago
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