i want to ask the cube of 3x-1/3y plzz answer this algebraic question with steps

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i want to ask the cube of 3x-1/3y plzz answer this algebraic question with steps

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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There is an algebraic identity for such question. You want to cube of (3x-1/3y). Such type is identified by (a-b)^3. i.e \[a ^{3}-b ^{3}-3ab(a-b)\] Now put the value of a=3x and b=1/3y and solve it.
ACTUALLY THATS WHAT I CANNOT DO ALTHOUGH I KNOW THE IDENTITY PLZZ HELP ME WITH THE STEPS
where do you get stuck

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Other answers:

FROM THE FIRST STEP
see since a=3x and b=1/3y, first find the cube of both a and b i.e a^3=27x^3 and b^3=1/27y^3. Do you get it...
WHAT DOES ^ THIS SIGN MEANS
raise to power of
ok yah am getting it then
now calculate the value of 3a^2b i.e \[3\times(3x)^{2}\times(1/3y)\] Which is equal to \[9x ^{2}/y\]
are you there

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