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amin_alam_siddiqui

  • 3 years ago

i want to ask the cube of 3x-1/3y plzz answer this algebraic question with steps

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  1. punnus
    • 3 years ago
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    There is an algebraic identity for such question. You want to cube of (3x-1/3y). Such type is identified by (a-b)^3. i.e \[a ^{3}-b ^{3}-3ab(a-b)\] Now put the value of a=3x and b=1/3y and solve it.

  2. amin_alam_siddiqui
    • 3 years ago
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    ACTUALLY THATS WHAT I CANNOT DO ALTHOUGH I KNOW THE IDENTITY PLZZ HELP ME WITH THE STEPS

  3. punnus
    • 3 years ago
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    where do you get stuck

  4. amin_alam_siddiqui
    • 3 years ago
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    FROM THE FIRST STEP

  5. punnus
    • 3 years ago
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    see since a=3x and b=1/3y, first find the cube of both a and b i.e a^3=27x^3 and b^3=1/27y^3. Do you get it...

  6. amin_alam_siddiqui
    • 3 years ago
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    WHAT DOES ^ THIS SIGN MEANS

  7. punnus
    • 3 years ago
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    raise to power of

  8. amin_alam_siddiqui
    • 3 years ago
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    ok yah am getting it then

  9. punnus
    • 3 years ago
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    now calculate the value of 3a^2b i.e \[3\times(3x)^{2}\times(1/3y)\] Which is equal to \[9x ^{2}/y\]

  10. punnus
    • 3 years ago
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    are you there

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