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amin_alam_siddiqui Group Title

i want to ask the cube of 3x-1/3y plzz answer this algebraic question with steps

  • 2 years ago
  • 2 years ago

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  1. punnus Group Title
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    There is an algebraic identity for such question. You want to cube of (3x-1/3y). Such type is identified by (a-b)^3. i.e \[a ^{3}-b ^{3}-3ab(a-b)\] Now put the value of a=3x and b=1/3y and solve it.

    • 2 years ago
  2. amin_alam_siddiqui Group Title
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    ACTUALLY THATS WHAT I CANNOT DO ALTHOUGH I KNOW THE IDENTITY PLZZ HELP ME WITH THE STEPS

    • 2 years ago
  3. punnus Group Title
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    where do you get stuck

    • 2 years ago
  4. amin_alam_siddiqui Group Title
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    FROM THE FIRST STEP

    • 2 years ago
  5. punnus Group Title
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    see since a=3x and b=1/3y, first find the cube of both a and b i.e a^3=27x^3 and b^3=1/27y^3. Do you get it...

    • 2 years ago
  6. amin_alam_siddiqui Group Title
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    WHAT DOES ^ THIS SIGN MEANS

    • 2 years ago
  7. punnus Group Title
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    raise to power of

    • 2 years ago
  8. amin_alam_siddiqui Group Title
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    ok yah am getting it then

    • 2 years ago
  9. punnus Group Title
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    now calculate the value of 3a^2b i.e \[3\times(3x)^{2}\times(1/3y)\] Which is equal to \[9x ^{2}/y\]

    • 2 years ago
  10. punnus Group Title
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    are you there

    • 2 years ago
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