amin_alam_siddiqui
i want to ask the cube of 3x-1/3y plzz answer this algebraic question with steps
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punnus
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There is an algebraic identity for such question.
You want to cube of (3x-1/3y).
Such type is identified by (a-b)^3.
i.e \[a ^{3}-b ^{3}-3ab(a-b)\]
Now put the value of a=3x and b=1/3y and solve it.
amin_alam_siddiqui
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ACTUALLY THATS WHAT I CANNOT DO ALTHOUGH I KNOW THE IDENTITY PLZZ HELP ME WITH THE STEPS
punnus
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where do you get stuck
amin_alam_siddiqui
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FROM THE FIRST STEP
punnus
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see since a=3x and b=1/3y, first find the cube of both a and b i.e a^3=27x^3 and b^3=1/27y^3. Do you get it...
amin_alam_siddiqui
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WHAT DOES ^ THIS SIGN MEANS
punnus
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raise to power of
amin_alam_siddiqui
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ok yah am getting it then
punnus
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now calculate the value of 3a^2b i.e \[3\times(3x)^{2}\times(1/3y)\]
Which is equal to \[9x ^{2}/y\]
punnus
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are you there