anonymous
  • anonymous
i want to ask the cube of 3x-1/3y plzz answer this algebraic question with steps
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
There is an algebraic identity for such question. You want to cube of (3x-1/3y). Such type is identified by (a-b)^3. i.e \[a ^{3}-b ^{3}-3ab(a-b)\] Now put the value of a=3x and b=1/3y and solve it.
anonymous
  • anonymous
ACTUALLY THATS WHAT I CANNOT DO ALTHOUGH I KNOW THE IDENTITY PLZZ HELP ME WITH THE STEPS
anonymous
  • anonymous
where do you get stuck

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anonymous
  • anonymous
FROM THE FIRST STEP
anonymous
  • anonymous
see since a=3x and b=1/3y, first find the cube of both a and b i.e a^3=27x^3 and b^3=1/27y^3. Do you get it...
anonymous
  • anonymous
WHAT DOES ^ THIS SIGN MEANS
anonymous
  • anonymous
raise to power of
anonymous
  • anonymous
ok yah am getting it then
anonymous
  • anonymous
now calculate the value of 3a^2b i.e \[3\times(3x)^{2}\times(1/3y)\] Which is equal to \[9x ^{2}/y\]
anonymous
  • anonymous
are you there

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