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zaphod Group Title

Please help :) http://screencast.com/t/nCUCq22y

  • 2 years ago
  • 2 years ago

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  1. Yahoo! Group Title
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    Draw FBD

    • 2 years ago
  2. ghazi Group Title
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    @Yahoo! solve this...it is for you...i will assume your kinematics is prepared

    • 2 years ago
  3. sauravshakya Group Title
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    u sure the information is enough

    • 2 years ago
  4. Yahoo! Group Title
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    decelleration = 0.5m/s^2

    • 2 years ago
  5. Yahoo! Group Title
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    @zaphod Do u have answer key

    • 2 years ago
  6. sauravshakya Group Title
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    Now, find alpha

    • 2 years ago
  7. zaphod Group Title
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    i knw how to do the next one...i think we have to resolve it a = -g ( sin alpha)

    • 2 years ago
  8. Yahoo! Group Title
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    mg sin x = ma

    • 2 years ago
  9. Yahoo! Group Title
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    sin x = a/g

    • 2 years ago
  10. Yahoo! Group Title
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    x = sin^-1 a/g

    • 2 years ago
  11. Yahoo! Group Title
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    |dw:1346508274972:dw|

    • 2 years ago
  12. Yahoo! Group Title
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    @ajprincess wat do u think?

    • 2 years ago
  13. Yahoo! Group Title
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    @eigenschmeigen

    • 2 years ago
  14. eigenschmeigen Group Title
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    for a) assuming constant acceleration, v^2 = u^2 + 2as

    • 2 years ago
  15. Yahoo! Group Title
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    Yes.....we want 2 nd question

    • 2 years ago
  16. eigenschmeigen Group Title
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    6.25 = 2.25 + 8a a = 1/2

    • 2 years ago
  17. eigenschmeigen Group Title
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    now \[mgsin \alpha = ma\] |dw:1346511156184:dw|

    • 2 years ago
  18. eigenschmeigen Group Title
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    so \[gsin \alpha = \frac{1}{2}\] \[\sin \alpha = \frac{1}{2g}\]

    • 2 years ago
  19. eigenschmeigen Group Title
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    now inverse sine gets you alpha

    • 2 years ago
  20. Yahoo! Group Title
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    Yup..thxx.....and i was correct

    • 2 years ago
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