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ghazi Group TitleBest ResponseYou've already chosen the best response.0
@Yahoo! solve this...it is for you...i will assume your kinematics is prepared
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
u sure the information is enough
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
decelleration = 0.5m/s^2
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
@zaphod Do u have answer key
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
Now, find alpha
 one year ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
i knw how to do the next one...i think we have to resolve it a = g ( sin alpha)
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
mg sin x = ma
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
sin x = a/g
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
x = sin^1 a/g
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
dw:1346508274972:dw
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
@ajprincess wat do u think?
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
@eigenschmeigen
 one year ago

eigenschmeigen Group TitleBest ResponseYou've already chosen the best response.1
for a) assuming constant acceleration, v^2 = u^2 + 2as
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
Yes.....we want 2 nd question
 one year ago

eigenschmeigen Group TitleBest ResponseYou've already chosen the best response.1
6.25 = 2.25 + 8a a = 1/2
 one year ago

eigenschmeigen Group TitleBest ResponseYou've already chosen the best response.1
now \[mgsin \alpha = ma\] dw:1346511156184:dw
 one year ago

eigenschmeigen Group TitleBest ResponseYou've already chosen the best response.1
so \[gsin \alpha = \frac{1}{2}\] \[\sin \alpha = \frac{1}{2g}\]
 one year ago

eigenschmeigen Group TitleBest ResponseYou've already chosen the best response.1
now inverse sine gets you alpha
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
Yup..thxx.....and i was correct
 one year ago
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