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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@Yahoo! solve this...it is for you...i will assume your kinematics is prepared

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0u sure the information is enough

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0decelleration = 0.5m/s^2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@zaphod Do u have answer key

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i knw how to do the next one...i think we have to resolve it a = g ( sin alpha)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1346508274972:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@ajprincess wat do u think?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0for a) assuming constant acceleration, v^2 = u^2 + 2as

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yes.....we want 2 nd question

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.06.25 = 2.25 + 8a a = 1/2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0now \[mgsin \alpha = ma\] dw:1346511156184:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so \[gsin \alpha = \frac{1}{2}\] \[\sin \alpha = \frac{1}{2g}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0now inverse sine gets you alpha

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yup..thxx.....and i was correct
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