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ghazi Group TitleBest ResponseYou've already chosen the best response.0
@Yahoo! solve this...it is for you...i will assume your kinematics is prepared
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
u sure the information is enough
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
decelleration = 0.5m/s^2
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
@zaphod Do u have answer key
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
Now, find alpha
 2 years ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
i knw how to do the next one...i think we have to resolve it a = g ( sin alpha)
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
mg sin x = ma
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
x = sin^1 a/g
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
dw:1346508274972:dw
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
@ajprincess wat do u think?
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
@eigenschmeigen
 2 years ago

eigenschmeigen Group TitleBest ResponseYou've already chosen the best response.1
for a) assuming constant acceleration, v^2 = u^2 + 2as
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
Yes.....we want 2 nd question
 2 years ago

eigenschmeigen Group TitleBest ResponseYou've already chosen the best response.1
6.25 = 2.25 + 8a a = 1/2
 2 years ago

eigenschmeigen Group TitleBest ResponseYou've already chosen the best response.1
now \[mgsin \alpha = ma\] dw:1346511156184:dw
 2 years ago

eigenschmeigen Group TitleBest ResponseYou've already chosen the best response.1
so \[gsin \alpha = \frac{1}{2}\] \[\sin \alpha = \frac{1}{2g}\]
 2 years ago

eigenschmeigen Group TitleBest ResponseYou've already chosen the best response.1
now inverse sine gets you alpha
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
Yup..thxx.....and i was correct
 2 years ago
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