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A astronaut has 100 kg of mass. Unfortunately the mass of his body was spread out in a sphere. After that, the density inside the sphere is 2x10^28 kg/m^3. What is the radius of the sphere where the mass of the astronaut was spread out?
 one year ago
 one year ago
A astronaut has 100 kg of mass. Unfortunately the mass of his body was spread out in a sphere. After that, the density inside the sphere is 2x10^28 kg/m^3. What is the radius of the sphere where the mass of the astronaut was spread out?
 one year ago
 one year ago

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sauravshakyaBest ResponseYou've already chosen the best response.2
Density = MASS/VOLUME
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
use it to find the volume of the sphere
 one year ago

viniterranovaBest ResponseYou've already chosen the best response.0
I just set up the following relation 6x10^28=100kg/V
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
Yes u r correct. PLZ CONTINUE
 one year ago

viniterranovaBest ResponseYou've already chosen the best response.0
So, with some algebric manipulation i found this relation V=1x10^2/6x10^28 and i got V=1/6x10^30.
 one year ago

viniterranovaBest ResponseYou've already chosen the best response.0
I think this is the volume of the sphere.
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
Now, Volume of a sphere=4/3 pi r^3
 one year ago

viniterranovaBest ResponseYou've already chosen the best response.0
I just plug it in the formual, right?
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
YEp, 1/6x10^30 = 4/3 pi r^3
 one year ago

viniterranovaBest ResponseYou've already chosen the best response.0
Just one moment.
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
But I got different
 one year ago

viniterranovaBest ResponseYou've already chosen the best response.0
What do you got?
 one year ago

viniterranovaBest ResponseYou've already chosen the best response.0
i write the equation in this order. cubic root of 1/6x10^30=4/3phi*r
 one year ago

viniterranovaBest ResponseYou've already chosen the best response.0
Now i got 4,12740906x10^9 m
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
Density= MASS/ VOLUME 2x10^28=100/VOLUME VOLUME=50 * 10 ^28 4/3 pi r^3 = 50 * 10^28 r^3=4923725109
 one year ago

viniterranovaBest ResponseYou've already chosen the best response.0
How do u calculate the 2x10^28=100/VOLUME. Plz do it step by step.
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
DEnsity =MASS/ VOLUME
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
Now, substitute the given values
 one year ago

viniterranovaBest ResponseYou've already chosen the best response.0
But sorry i can´t understant how do you calculate 2x10^28=100/VOLUME. May you do it plz?
 one year ago

viniterranovaBest ResponseYou've already chosen the best response.0
When i calculate V i have found 50/3x10^28. How did you got 50 * 10 ^28. PLz.
 one year ago

viniterranovaBest ResponseYou've already chosen the best response.0
Yes, but where did you find the number two? If we have the division 100/6?
 one year ago

viniterranovaBest ResponseYou've already chosen the best response.0
Did you divide 6/3. I got it. now.
 one year ago
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