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A astronaut has 100 kg of mass. Unfortunately the mass of his body was spread out in a sphere. After that, the density inside the sphere is 2x10^-28 kg/m^3. What is the radius of the sphere where the mass of the astronaut was spread out?

Physics
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Density = MASS/VOLUME
use it to find the volume of the sphere
I just set up the following relation 6x10^-28=100kg/V

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Other answers:

Yes u r correct. PLZ CONTINUE
So, with some algebric manipulation i found this relation V=1x10^2/6x10^-28 and i got V=1/6x10^30.
I think this is the volume of the sphere.
Now, Volume of a sphere=4/3 pi r^3
Use it to find r
I just plug it in the formual, right?
YEp, 1/6x10^30 = 4/3 pi r^3
got it?
Just one moment.
i got 1,46459
But I got different
What do you got?
i write the equation in this order. cubic root of 1/6x10^30=4/3phi*r
Now i got 4,12740906x10^9 m
Density= MASS/ VOLUME 2x10^-28=100/VOLUME VOLUME=50 * 10 ^28 4/3 pi r^3 = 50 * 10^28 r^3=4923725109
That ´s right.
r=4923725109
How do u calculate the 2x10^-28=100/VOLUME. Plz do it step by step.
DEnsity =MASS/ VOLUME
Now, substitute the given values
thanks
:)yw
But sorry i can´t understant how do you calculate 2x10^-28=100/VOLUME. May you do it plz?
When i calculate V i have found 50/3x10^28. How did you got 50 * 10 ^28. PLz.
100/2 =50 right?
Yes, but where did you find the number two? If we have the division 100/6?
Did you divide 6/3. I got it. now.

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