viniterranova
A astronaut has 100 kg of mass. Unfortunately the mass of his body was spread out in a sphere. After that, the density inside the sphere is 2x10^-28 kg/m^3. What is the radius of the sphere where the mass of the astronaut was spread out?
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sauravshakya
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Density = MASS/VOLUME
sauravshakya
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use it to find the volume of the sphere
viniterranova
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I just set up the following relation 6x10^-28=100kg/V
sauravshakya
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Yes u r correct. PLZ CONTINUE
viniterranova
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So, with some algebric manipulation i found this relation V=1x10^2/6x10^-28 and i got V=1/6x10^30.
viniterranova
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I think this is the volume of the sphere.
sauravshakya
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Now, Volume of a sphere=4/3 pi r^3
sauravshakya
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Use it to find r
viniterranova
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I just plug it in the formual, right?
sauravshakya
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YEp, 1/6x10^30 = 4/3 pi r^3
sauravshakya
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got it?
viniterranova
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Just one moment.
viniterranova
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i got 1,46459
sauravshakya
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But I got different
viniterranova
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What do you got?
viniterranova
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i write the equation in this order. cubic root of 1/6x10^30=4/3phi*r
viniterranova
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Now i got 4,12740906x10^9 m
sauravshakya
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Density= MASS/ VOLUME
2x10^-28=100/VOLUME
VOLUME=50 * 10 ^28
4/3 pi r^3 = 50 * 10^28
r^3=4923725109
viniterranova
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That ´s right.
sauravshakya
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r=4923725109
viniterranova
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How do u calculate the 2x10^-28=100/VOLUME. Plz do it step by step.
sauravshakya
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DEnsity =MASS/ VOLUME
sauravshakya
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Now, substitute the given values
viniterranova
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thanks
sauravshakya
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:)yw
viniterranova
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But sorry i can´t understant how do you calculate 2x10^-28=100/VOLUME. May you do it plz?
viniterranova
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When i calculate V i have found 50/3x10^28. How did you got 50 * 10 ^28. PLz.
sauravshakya
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100/2 =50 right?
viniterranova
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Yes, but where did you find the number two? If we have the division 100/6?
viniterranova
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Did you divide 6/3. I got it. now.