- anonymous

A astronaut has 100 kg of mass. Unfortunately the mass of his body was spread out in a sphere. After that, the density inside the sphere is 2x10^-28 kg/m^3. What is the radius of the sphere where the mass of the astronaut was spread out?

- jamiebookeater

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- anonymous

Density = MASS/VOLUME

- anonymous

use it to find the volume of the sphere

- anonymous

I just set up the following relation 6x10^-28=100kg/V

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## More answers

- anonymous

Yes u r correct. PLZ CONTINUE

- anonymous

So, with some algebric manipulation i found this relation V=1x10^2/6x10^-28 and i got V=1/6x10^30.

- anonymous

I think this is the volume of the sphere.

- anonymous

Now, Volume of a sphere=4/3 pi r^3

- anonymous

Use it to find r

- anonymous

I just plug it in the formual, right?

- anonymous

YEp, 1/6x10^30 = 4/3 pi r^3

- anonymous

got it?

- anonymous

Just one moment.

- anonymous

i got 1,46459

- anonymous

But I got different

- anonymous

What do you got?

- anonymous

i write the equation in this order. cubic root of 1/6x10^30=4/3phi*r

- anonymous

Now i got 4,12740906x10^9 m

- anonymous

Density= MASS/ VOLUME
2x10^-28=100/VOLUME
VOLUME=50 * 10 ^28
4/3 pi r^3 = 50 * 10^28
r^3=4923725109

- anonymous

That ´s right.

- anonymous

r=4923725109

- anonymous

How do u calculate the 2x10^-28=100/VOLUME. Plz do it step by step.

- anonymous

DEnsity =MASS/ VOLUME

- anonymous

Now, substitute the given values

- anonymous

thanks

- anonymous

:)yw

- anonymous

But sorry i can´t understant how do you calculate 2x10^-28=100/VOLUME. May you do it plz?

- anonymous

When i calculate V i have found 50/3x10^28. How did you got 50 * 10 ^28. PLz.

- anonymous

100/2 =50 right?

- anonymous

Yes, but where did you find the number two? If we have the division 100/6?

- anonymous

Did you divide 6/3. I got it. now.

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