anonymous
  • anonymous
A astronaut has 100 kg of mass. Unfortunately the mass of his body was spread out in a sphere. After that, the density inside the sphere is 2x10^-28 kg/m^3. What is the radius of the sphere where the mass of the astronaut was spread out?
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
Density = MASS/VOLUME
anonymous
  • anonymous
use it to find the volume of the sphere
anonymous
  • anonymous
I just set up the following relation 6x10^-28=100kg/V

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anonymous
  • anonymous
Yes u r correct. PLZ CONTINUE
anonymous
  • anonymous
So, with some algebric manipulation i found this relation V=1x10^2/6x10^-28 and i got V=1/6x10^30.
anonymous
  • anonymous
I think this is the volume of the sphere.
anonymous
  • anonymous
Now, Volume of a sphere=4/3 pi r^3
anonymous
  • anonymous
Use it to find r
anonymous
  • anonymous
I just plug it in the formual, right?
anonymous
  • anonymous
YEp, 1/6x10^30 = 4/3 pi r^3
anonymous
  • anonymous
got it?
anonymous
  • anonymous
Just one moment.
anonymous
  • anonymous
i got 1,46459
anonymous
  • anonymous
But I got different
anonymous
  • anonymous
What do you got?
anonymous
  • anonymous
i write the equation in this order. cubic root of 1/6x10^30=4/3phi*r
anonymous
  • anonymous
Now i got 4,12740906x10^9 m
anonymous
  • anonymous
Density= MASS/ VOLUME 2x10^-28=100/VOLUME VOLUME=50 * 10 ^28 4/3 pi r^3 = 50 * 10^28 r^3=4923725109
anonymous
  • anonymous
That ´s right.
anonymous
  • anonymous
r=4923725109
anonymous
  • anonymous
How do u calculate the 2x10^-28=100/VOLUME. Plz do it step by step.
anonymous
  • anonymous
DEnsity =MASS/ VOLUME
anonymous
  • anonymous
Now, substitute the given values
anonymous
  • anonymous
thanks
anonymous
  • anonymous
:)yw
anonymous
  • anonymous
But sorry i can´t understant how do you calculate 2x10^-28=100/VOLUME. May you do it plz?
anonymous
  • anonymous
When i calculate V i have found 50/3x10^28. How did you got 50 * 10 ^28. PLz.
anonymous
  • anonymous
100/2 =50 right?
anonymous
  • anonymous
Yes, but where did you find the number two? If we have the division 100/6?
anonymous
  • anonymous
Did you divide 6/3. I got it. now.

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