anonymous
  • anonymous
I need help with the attached problem.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
anonymous
  • anonymous
In y=mx+c can u tell me what is the slope?
anonymous
  • anonymous
m = slope

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anonymous
  • anonymous
So, V(t)=-203t+9655........ what do u think is the slope
anonymous
  • anonymous
-203 = m = slope
anonymous
  • anonymous
Now, since slope is negative it means it is decreasing at the rate of 203 per year
anonymous
  • anonymous
So the value of the Gremlin is decreasing at the rate of 203 per year?
anonymous
  • anonymous
yep
anonymous
  • anonymous
Now, what do u think V intercept is?
anonymous
  • anonymous
V represents the value in year t. So, in 1974, V(1974) = -203(1974)+9655
anonymous
  • anonymous
At 1974, t=0
anonymous
  • anonymous
got it?
anonymous
  • anonymous
Yes. So what would V be then?
anonymous
  • anonymous
9655
anonymous
  • anonymous
Okay. And what would be the meaning of the V-intercept in this application?
anonymous
  • anonymous
Value of Albert Gebra's at 1974
anonymous
  • anonymous
Okay, thanks. Now I have to find the t-intercept for the application and explain what this means in terms of the application.
anonymous
  • anonymous
V(t)=0
anonymous
  • anonymous
Now, -203t+9655=0
anonymous
  • anonymous
So after you solve for t, I get 47.562
anonymous
  • anonymous
It represents after 47.562 years the Albert ... value will be zero
anonymous
  • anonymous
Okay. And if I have to sketch a graph of the function, labeling the axis, scale and equation, how would I do that?
anonymous
  • anonymous
|dw:1346511852592:dw|
anonymous
  • anonymous
Does it help?
anonymous
  • anonymous
Yes, but where would I write the equation on the graph?
anonymous
  • anonymous
y=-203x+410377
anonymous
  • anonymous
Okay. If I have to give the domain and range of the function and then write each of them in interval notation, how would I do that?
anonymous
  • anonymous
It's first degree equation, so domain ( -inf, inf), also range ( -inf, inf)

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