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znimon Group TitleBest ResponseYou've already chosen the best response.1
\[g(x) \sqrt{x^2  3x  40}\]
 one year ago

znimon Group TitleBest ResponseYou've already chosen the best response.1
I have \[\sqrt{(x8)(x+5)} \]
 one year ago

znimon Group TitleBest ResponseYou've already chosen the best response.1
\[(x8)(x+5) \ge 0\]
 one year ago

znimon Group TitleBest ResponseYou've already chosen the best response.1
The original problem is at the top.
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
Draw a number line and see for it
 one year ago

znimon Group TitleBest ResponseYou've already chosen the best response.1
I don't know what x can't be though
 one year ago

znimon Group TitleBest ResponseYou've already chosen the best response.1
I know the answer but I don't know how to get the answer.
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
(infinity , 5] U [8 , infinity)
 one year ago

znimon Group TitleBest ResponseYou've already chosen the best response.1
yeah but how do I find that?
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
just do trial and error method...)
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
(x−8)(x+5)≥0
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
luk for the vlue of x which satisfies this...
 one year ago

znimon Group TitleBest ResponseYou've already chosen the best response.1
There must be a logical way to find the answer, right?
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.2
(x8)(x+5) >= 0 its a parabola, right ?
 one year ago

znimon Group TitleBest ResponseYou've already chosen the best response.1
I could input it into my graphing calculator but other wise I don't know how to tell if its a parabola or not.
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.2
y = ax^2 + bx + c is a parabola
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.2
any quadratic function gives a parabola graph
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.2
can you find the x intercepts ?
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.2
once you find xintercepts, you would know where the parabola dips into x axis (goes negative)
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.2
dw:1346519548989:dw
 one year ago

znimon Group TitleBest ResponseYou've already chosen the best response.1
Oh ya that would be the point at which the g(x) function is 0, so its x  8 = 0, x = 8, x+ 5 = 0, x=5, and since its a parabola the graph only passes through zero twice. Nice dude, so the domain is (infinity, 5] U [8, +infinity]
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.2
yeah nice you got it :)
 one year ago

znimon Group TitleBest ResponseYou've already chosen the best response.1
Awesome, thanks again. Is there a way I could recognize any graph's shape or at least some and would you recommend memorizing those?
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.2
if the degree is 2, then its a parabola
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.2
finding domains for other polynomials is bit tricky... as they may dip into xaxis multiple times
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.2
do you knw sketching polynomilas (end behiavior thingy )
 one year ago

znimon Group TitleBest ResponseYou've already chosen the best response.1
never heard of it
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.2
end behavior helps you sketch ANY polynomial freehand
 one year ago

znimon Group TitleBest ResponseYou've already chosen the best response.1
Thanks dude, I'll look it up
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.2
process is basically : 1) find x intercepts 2) using endbehavior sketch the graph by hand
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.2
its easy concept and worth learning... im sure you wil get hang of it in few minutes....... good luck :)
 one year ago

znimon Group TitleBest ResponseYou've already chosen the best response.1
why is it that a polynomial with a degree of two is a parabola?
 one year ago

znimon Group TitleBest ResponseYou've already chosen the best response.1
Thanks again.
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.2
uhh il have to think...... idk exactly... i think it has something to do with local maximum/minimum + increasing/decreasing thingy. we need to turn to calculus for proper understanding. im also learning... . so im no good for answering this :(
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.2
@mukushla @eliassaab @experimentX
 one year ago

znimon Group TitleBest ResponseYou've already chosen the best response.1
Oh, I have enough to learn for now so it doesn't matter to me. I bet I wouldn't understand the explanation if it involves terms I've never had before haha.
 one year ago
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