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znimon Group TitleBest ResponseYou've already chosen the best response.1
\[g(x) \sqrt{x^2  3x  40}\]
 2 years ago

znimon Group TitleBest ResponseYou've already chosen the best response.1
I have \[\sqrt{(x8)(x+5)} \]
 2 years ago

znimon Group TitleBest ResponseYou've already chosen the best response.1
\[(x8)(x+5) \ge 0\]
 2 years ago

znimon Group TitleBest ResponseYou've already chosen the best response.1
The original problem is at the top.
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
Draw a number line and see for it
 2 years ago

znimon Group TitleBest ResponseYou've already chosen the best response.1
I don't know what x can't be though
 2 years ago

znimon Group TitleBest ResponseYou've already chosen the best response.1
I know the answer but I don't know how to get the answer.
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
(infinity , 5] U [8 , infinity)
 2 years ago

znimon Group TitleBest ResponseYou've already chosen the best response.1
yeah but how do I find that?
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
just do trial and error method...)
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
(x−8)(x+5)≥0
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
luk for the vlue of x which satisfies this...
 2 years ago

znimon Group TitleBest ResponseYou've already chosen the best response.1
There must be a logical way to find the answer, right?
 2 years ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.2
(x8)(x+5) >= 0 its a parabola, right ?
 2 years ago

znimon Group TitleBest ResponseYou've already chosen the best response.1
I could input it into my graphing calculator but other wise I don't know how to tell if its a parabola or not.
 2 years ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.2
y = ax^2 + bx + c is a parabola
 2 years ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.2
any quadratic function gives a parabola graph
 2 years ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.2
can you find the x intercepts ?
 2 years ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.2
once you find xintercepts, you would know where the parabola dips into x axis (goes negative)
 2 years ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.2
dw:1346519548989:dw
 2 years ago

znimon Group TitleBest ResponseYou've already chosen the best response.1
Oh ya that would be the point at which the g(x) function is 0, so its x  8 = 0, x = 8, x+ 5 = 0, x=5, and since its a parabola the graph only passes through zero twice. Nice dude, so the domain is (infinity, 5] U [8, +infinity]
 2 years ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.2
yeah nice you got it :)
 2 years ago

znimon Group TitleBest ResponseYou've already chosen the best response.1
Awesome, thanks again. Is there a way I could recognize any graph's shape or at least some and would you recommend memorizing those?
 2 years ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.2
if the degree is 2, then its a parabola
 2 years ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.2
finding domains for other polynomials is bit tricky... as they may dip into xaxis multiple times
 2 years ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.2
do you knw sketching polynomilas (end behiavior thingy )
 2 years ago

znimon Group TitleBest ResponseYou've already chosen the best response.1
never heard of it
 2 years ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.2
end behavior helps you sketch ANY polynomial freehand
 2 years ago

znimon Group TitleBest ResponseYou've already chosen the best response.1
Thanks dude, I'll look it up
 2 years ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.2
process is basically : 1) find x intercepts 2) using endbehavior sketch the graph by hand
 2 years ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.2
its easy concept and worth learning... im sure you wil get hang of it in few minutes....... good luck :)
 2 years ago

znimon Group TitleBest ResponseYou've already chosen the best response.1
why is it that a polynomial with a degree of two is a parabola?
 2 years ago

znimon Group TitleBest ResponseYou've already chosen the best response.1
Thanks again.
 2 years ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.2
uhh il have to think...... idk exactly... i think it has something to do with local maximum/minimum + increasing/decreasing thingy. we need to turn to calculus for proper understanding. im also learning... . so im no good for answering this :(
 2 years ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.2
@mukushla @eliassaab @experimentX
 2 years ago

znimon Group TitleBest ResponseYou've already chosen the best response.1
Oh, I have enough to learn for now so it doesn't matter to me. I bet I wouldn't understand the explanation if it involves terms I've never had before haha.
 2 years ago
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