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\[g(x) \sqrt{x^2 - 3x - 40}\]

I have \[\sqrt{(x-8)(x+5)} \]

\[(x-8)(x+5) \ge 0\]

The original problem is at the top.

Draw a number line and see for it

I don't know what x can't be though

I know the answer but I don't know how to get the answer.

(-infinity , 5] U [8 , infinity)

yeah but how do I find that?

just do trial and error method...)

(x−8)(x+5)≥0

luk for the vlue of x which satisfies this...

There must be a logical way to find the answer, right?

(x-8)(x+5) >= 0
its a parabola, right ?

y = ax^2 + bx + c is a parabola

any quadratic function gives a parabola graph

ok

can you find the x intercepts ?

once you find x-intercepts, you would know where the parabola dips into x axis (goes negative)

|dw:1346519548989:dw|

yeah nice you got it :)

if the degree is 2, then its a parabola

finding domains for other polynomials is bit tricky... as they may dip into x-axis multiple times

okay

do you knw sketching polynomilas (end behiavior thingy )

never heard of it

end behavior helps you sketch ANY polynomial freehand

Thanks dude, I'll look it up

process is basically :
1) find x intercepts
2) using end-behavior sketch the graph by hand

why is it that a polynomial with a degree of two is a parabola?

Thanks again.