anonymous
  • anonymous
How to solve X^2+10x=24 by completing the square.
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
what times what equals 24 and those same numbers have to add upto 10
anonymous
  • anonymous
12 and -2 right?
anonymous
  • anonymous
or 4 and 6

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anonymous
  • anonymous
\[x^2+10x=(x+5)^2-25\] Do you understand this?
anonymous
  • anonymous
no 4 and 6 when u multiply its 24 not -24
anonymous
  • anonymous
srry it has to multiply to -24
anonymous
  • anonymous
... or we could actually help him with the mechanics of the question
anonymous
  • anonymous
*or her
anonymous
  • anonymous
so the answer is (x-2)(x+10)
anonymous
  • anonymous
if you multiply using foils u can see it equals the question
anonymous
  • anonymous
Really, that's not completing the square.
anonymous
  • anonymous
http://en.wikipedia.org/wiki/Completing_the_square Needs to be in the form (x+k)^2=c
anonymous
  • anonymous
okie
anonymous
  • anonymous
ur right srry
anonymous
  • anonymous
Okay, @lizzy87 , do you understand why\[x^2+10x=(x+5)^2-25\]?
anonymous
  • anonymous
how didi you get the 5?
anonymous
  • anonymous
|dw:1346521462011:dw| Because 2x5=10
anonymous
  • anonymous
|dw:1346521508364:dw|
anonymous
  • anonymous
And if you take away 25 and cancel the 2 5x's into one 10x, that happens.
anonymous
  • anonymous
|dw:1346521563679:dw|
anonymous
  • anonymous
oh ok see how you got that thanks
anonymous
  • anonymous
\[x^2+10x=24\] \[x^2+10x=(x+5)^2-25\] Therefore\[24=(x+5)^2-25\] and\[49=(x+5)^2\]
anonymous
  • anonymous
1- Did you understand that 2- What do you think we could do now to simplify?
anonymous
  • anonymous
\[\pm \sqrt{49}=x+5\]

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