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lizzy87

  • 3 years ago

How to solve X^2+10x=24 by completing the square.

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  1. earslan100
    • 3 years ago
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    what times what equals 24 and those same numbers have to add upto 10

  2. earslan100
    • 3 years ago
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    12 and -2 right?

  3. znimon
    • 3 years ago
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    or 4 and 6

  4. henpen
    • 3 years ago
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    \[x^2+10x=(x+5)^2-25\] Do you understand this?

  5. earslan100
    • 3 years ago
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    no 4 and 6 when u multiply its 24 not -24

  6. earslan100
    • 3 years ago
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    srry it has to multiply to -24

  7. henpen
    • 3 years ago
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    ... or we could actually help him with the mechanics of the question

  8. henpen
    • 3 years ago
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    *or her

  9. earslan100
    • 3 years ago
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    so the answer is (x-2)(x+10)

  10. earslan100
    • 3 years ago
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    if you multiply using foils u can see it equals the question

  11. henpen
    • 3 years ago
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    Really, that's not completing the square.

  12. henpen
    • 3 years ago
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    http://en.wikipedia.org/wiki/Completing_the_square Needs to be in the form (x+k)^2=c

  13. earslan100
    • 3 years ago
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    okie

  14. earslan100
    • 3 years ago
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    ur right srry

  15. henpen
    • 3 years ago
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    Okay, @lizzy87 , do you understand why\[x^2+10x=(x+5)^2-25\]?

  16. lizzy87
    • 3 years ago
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    how didi you get the 5?

  17. henpen
    • 3 years ago
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    |dw:1346521462011:dw| Because 2x5=10

  18. henpen
    • 3 years ago
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    |dw:1346521508364:dw|

  19. henpen
    • 3 years ago
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    And if you take away 25 and cancel the 2 5x's into one 10x, that happens.

  20. henpen
    • 3 years ago
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    |dw:1346521563679:dw|

  21. lizzy87
    • 3 years ago
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    oh ok see how you got that thanks

  22. henpen
    • 3 years ago
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    \[x^2+10x=24\] \[x^2+10x=(x+5)^2-25\] Therefore\[24=(x+5)^2-25\] and\[49=(x+5)^2\]

  23. henpen
    • 3 years ago
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    1- Did you understand that 2- What do you think we could do now to simplify?

  24. henpen
    • 3 years ago
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    \[\pm \sqrt{49}=x+5\]

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