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(3x^33x^2+2x4) / (x1/3). Determine the remainder for the following using the remainder theorm. The remainder is different from 0 and is equal to??
 one year ago
 one year ago
(3x^33x^2+2x4) / (x1/3). Determine the remainder for the following using the remainder theorm. The remainder is different from 0 and is equal to??
 one year ago
 one year ago

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jim_thompson5910Best ResponseYou've already chosen the best response.0
The remainder theorem is If P(x) is divided by xk, then the remainder r is r = P(k)
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.0
In this case, P(x) = 3x^33x^2+2x4 and k = 1/3
 one year ago

KE8717504Best ResponseYou've already chosen the best response.1
ok so how would i work this. I've worked it once and it was wrong.
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.0
P(x) = 3x^33x^2+2x4 P(1/3) = 3(1/3)^33(1/3)^2+2(1/3)4 Keep going
 one year ago

KE8717504Best ResponseYou've already chosen the best response.1
ok one second let me work it
 one year ago

KE8717504Best ResponseYou've already chosen the best response.1
would that be the end result?
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.0
34/9 is the remainder, so you are correct
 one year ago

KE8717504Best ResponseYou've already chosen the best response.1
so that is the answer?
 one year ago

KE8717504Best ResponseYou've already chosen the best response.1
i want to ask another one u going to be here a second? did u check my work on that one?
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.0
yes, 34/9 is the correct answer
 one year ago

KE8717504Best ResponseYou've already chosen the best response.1
It says to type it in as a simplifed fraction so would that be simplifed
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.0
yes it's fully simplified, it's the final answer
 one year ago

KE8717504Best ResponseYou've already chosen the best response.1
i'm going to post another one will u help me on it?
 one year ago
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