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 2 years ago
(3x^33x^2+2x4) / (x1/3). Determine the remainder for the following using the remainder theorm. The remainder is different from 0 and is equal to??
 2 years ago
(3x^33x^2+2x4) / (x1/3). Determine the remainder for the following using the remainder theorm. The remainder is different from 0 and is equal to??

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jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.0The remainder theorem is If P(x) is divided by xk, then the remainder r is r = P(k)

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.0In this case, P(x) = 3x^33x^2+2x4 and k = 1/3

KE8717504
 2 years ago
Best ResponseYou've already chosen the best response.1ok so how would i work this. I've worked it once and it was wrong.

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.0P(x) = 3x^33x^2+2x4 P(1/3) = 3(1/3)^33(1/3)^2+2(1/3)4 Keep going

KE8717504
 2 years ago
Best ResponseYou've already chosen the best response.1ok one second let me work it

KE8717504
 2 years ago
Best ResponseYou've already chosen the best response.1would that be the end result?

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.034/9 is the remainder, so you are correct

KE8717504
 2 years ago
Best ResponseYou've already chosen the best response.1so that is the answer?

KE8717504
 2 years ago
Best ResponseYou've already chosen the best response.1i want to ask another one u going to be here a second? did u check my work on that one?

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.0yes, 34/9 is the correct answer

KE8717504
 2 years ago
Best ResponseYou've already chosen the best response.1It says to type it in as a simplifed fraction so would that be simplifed

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.0yes it's fully simplified, it's the final answer

KE8717504
 2 years ago
Best ResponseYou've already chosen the best response.1i'm going to post another one will u help me on it?
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