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LolWolf
 2 years ago
Best ResponseYou've already chosen the best response.0\[\binom{pa}{pb}\equiv\binom{a}{b}\mod p^3\]Where p is prime and\[p>2\]

LolWolf
 2 years ago
Best ResponseYou've already chosen the best response.0Well, it'd be a grad level number theory class, but it's a problem I was given in a summer camp as part of a worksheet.

Lethal
 2 years ago
Best ResponseYou've already chosen the best response.0haha well idk anything have you tried looking up similar problems or proofs like this http://f2.org/maths/nthproof.html

LolWolf
 2 years ago
Best ResponseYou've already chosen the best response.0Eeyup, haven't found anything.

Lethal
 2 years ago
Best ResponseYou've already chosen the best response.0oh, well i'm sorry i won't be of any help then. I just barged in here due to the fact no one else was trying to help. good luck.

LolWolf
 2 years ago
Best ResponseYou've already chosen the best response.0It's fine, thanks. Yeah, I haven't been able to solve this problem since quite the time.

Lethal
 2 years ago
Best ResponseYou've already chosen the best response.0and you could try posting this on Yahoo! answers.

Herp_Derp
 2 years ago
Best ResponseYou've already chosen the best response.0Have you tried: http://math.stackexchange.com/ http://mathoverflow.net/ http://www.mathworld.wolfram.com Wikipedia??? (Actually, if you post your question on the talk page of a user who seems knowledgeable, you can occasionally get an answer.)

LolWolf
 2 years ago
Best ResponseYou've already chosen the best response.0I've tried the latter of the three, but I was going to post it on Math Overflow/Stack Exchange, haven't yet... thanks, though...
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