anonymous
  • anonymous
What is the domain and range of the application? Then, give the answer/s in interval notation.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
helder_edwin
  • helder_edwin
it tells u that t is the number of years since 1974, then t>=0 (this is the domain) then since t>=0 \[ \large -203t\geq-203\cdot0=0 \] \[ \large V(t)=-203t+9655\geq9655 \] this is the range
anonymous
  • anonymous
I don't understand this. I thought it was (-inf, inf)

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
It's first degree equation, so domain ( -inf, inf), also range ( -inf, inf)
helder_edwin
  • helder_edwin
u would think so. but read carefully the wording of the problem. the definition of V(t) (without context) would lead you to this conclusions, but it has a context!!
anonymous
  • anonymous
the range is only from the specified year. so 1974 is t=0 to perhaps infinity or this year which is 2012=38. the range would be from 9655 to whatever

Looking for something else?

Not the answer you are looking for? Search for more explanations.