A passenger train leaves the train depot 2 hours after a freight train leaves the same depot. The freight train is traveling 20 mph slower than the passenger train. Find the rate of each train, if the passenger overtakes the freight train in 3 hours.

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Ok so first of all, let's assign two variables, a and b, as the speeds (or rates) of each train. But we do know that the freight train a is 20 less than the passenger, b. so a=b-20. We also know that a goes for 2 hours more than b. And the 2 extra hours plus the 3 hours is 5 hours that a was moving. so 5 hours x a mph is the distance they were from the depot when they crossed paths. And 3 hours x b mph is also that distance. We have a formula from before that we can use instead of a. so: 5 (b-20) is equal to 3b 5(b-20)=3b Do you get it? Solve for b, and tell me what you get! :)

5b- 100 = 3b 2b=100 b=50

yes! :) and then you can plug that back into a=b-20 to get...?

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