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jessiedeee
Group Title
HELP???
Limits by Direct Substitution
FInd the limits.
lim 3sq.root2x^210
x> 3
 2 years ago
 2 years ago
jessiedeee Group Title
HELP??? Limits by Direct Substitution FInd the limits. lim 3sq.root2x^210 x> 3
 2 years ago
 2 years ago

This Question is Closed

jessiedeee Group TitleBest ResponseYou've already chosen the best response.1
dw:1346625101290:dw
 2 years ago

jessiedeee Group TitleBest ResponseYou've already chosen the best response.1
dw:1346625172663:dw
 2 years ago

jessiedeee Group TitleBest ResponseYou've already chosen the best response.1
dw:1346625274472:dw
 2 years ago

jessiedeee Group TitleBest ResponseYou've already chosen the best response.1
IS IT RIGHT?
 2 years ago

jessiedeee Group TitleBest ResponseYou've already chosen the best response.1
@hal_stirrup
 2 years ago

hal_stirrup Group TitleBest ResponseYou've already chosen the best response.1
as limit approches 3 , we call it 3 and solve as you did.
 2 years ago

jessiedeee Group TitleBest ResponseYou've already chosen the best response.1
soo I solved it correctly?:)
 2 years ago

hal_stirrup Group TitleBest ResponseYou've already chosen the best response.1
dw:1346626250356:dw
 2 years ago

hal_stirrup Group TitleBest ResponseYou've already chosen the best response.1
lim_(x>3) (2 x^210)^(1/3) = 2
 2 years ago

hal_stirrup Group TitleBest ResponseYou've already chosen the best response.1
you arithmetic in wrong but you have the idea right.
 2 years ago

jessiedeee Group TitleBest ResponseYou've already chosen the best response.1
awww ... ok I thought I was getting it :/
 2 years ago

hal_stirrup Group TitleBest ResponseYou've already chosen the best response.1
you are but simple arithmetic mistake .
 2 years ago

jessiedeee Group TitleBest ResponseYou've already chosen the best response.1
(2 x^210)^(1/3) = 2 < where'd the 1/3 come from on here...
 2 years ago

hal_stirrup Group TitleBest ResponseYou've already chosen the best response.1
^^(1/3) = 3sq.root
 2 years ago

hal_stirrup Group TitleBest ResponseYou've already chosen the best response.1
anther way of writing it. thats all
 2 years ago

jessiedeee Group TitleBest ResponseYou've already chosen the best response.1
oh ok thank you so much!
 2 years ago

jessiedeee Group TitleBest ResponseYou've already chosen the best response.1
will you help me with one more??
 2 years ago

jessiedeee Group TitleBest ResponseYou've already chosen the best response.1
its limit by direct substitution also
 2 years ago

hal_stirrup Group TitleBest ResponseYou've already chosen the best response.1
ok . dont for get you can always rate me and write Fan Testimonials.
 2 years ago

jessiedeee Group TitleBest ResponseYou've already chosen the best response.1
this one is a bit complicated
 2 years ago

jessiedeee Group TitleBest ResponseYou've already chosen the best response.1
lim x sec (x) x> pi
 2 years ago

hal_stirrup Group TitleBest ResponseYou've already chosen the best response.1
sec meaning secant?
 2 years ago

jessiedeee Group TitleBest ResponseYou've already chosen the best response.1
pi sec (pi)
 2 years ago

hal_stirrup Group TitleBest ResponseYou've already chosen the best response.1
sec ??????????????????????????????
 2 years ago

hal_stirrup Group TitleBest ResponseYou've already chosen the best response.1
what happend to you? :)
 2 years ago

jessiedeee Group TitleBest ResponseYou've already chosen the best response.1
nothing...
 2 years ago

hal_stirrup Group TitleBest ResponseYou've already chosen the best response.1
lim_(x>pi) x sec(x) = pi
 2 years ago

hal_stirrup Group TitleBest ResponseYou've already chosen the best response.1
is that clear !
 2 years ago

jessiedeee Group TitleBest ResponseYou've already chosen the best response.1
aren't you supposed to plug in pi
 2 years ago

hal_stirrup Group TitleBest ResponseYou've already chosen the best response.1
pi has an infinite vale so the answare pi
 2 years ago

hal_stirrup Group TitleBest ResponseYou've already chosen the best response.1
yes but make sure you are clear about: secan=1/cos(x)
 2 years ago
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