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jessiedeee

  • 3 years ago

HELP??? Limits by Direct Substitution FInd the limits. lim 3sq.root2x^2-10 x----> 3

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  1. jessiedeee
    • 3 years ago
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    |dw:1346625101290:dw|

  2. jessiedeee
    • 3 years ago
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    |dw:1346625172663:dw|

  3. jessiedeee
    • 3 years ago
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    |dw:1346625274472:dw|

  4. hal_stirrup
    • 3 years ago
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    good

  5. jessiedeee
    • 3 years ago
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    IS IT RIGHT?

  6. jessiedeee
    • 3 years ago
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    @hal_stirrup

  7. hal_stirrup
    • 3 years ago
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    as limit approches 3 , we call it 3 and solve as you did.

  8. jessiedeee
    • 3 years ago
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    soo I solved it correctly?:)

  9. hal_stirrup
    • 3 years ago
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    |dw:1346626250356:dw|

  10. hal_stirrup
    • 3 years ago
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    lim_(x->3) (2 x^2-10)^(1/3) = 2

  11. hal_stirrup
    • 3 years ago
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    you arithmetic in wrong but you have the idea right.

  12. jessiedeee
    • 3 years ago
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    awww ... ok I thought I was getting it :/

  13. hal_stirrup
    • 3 years ago
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    you are but simple arithmetic mistake .

  14. jessiedeee
    • 3 years ago
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    (2 x^2-10)^(1/3) = 2 <---- where'd the 1/3 come from on here...

  15. hal_stirrup
    • 3 years ago
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    ^^(1/3) = 3sq.root

  16. hal_stirrup
    • 3 years ago
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    anther way of writing it. thats all

  17. jessiedeee
    • 3 years ago
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    oh ok thank you so much!

  18. jessiedeee
    • 3 years ago
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    will you help me with one more??

  19. jessiedeee
    • 3 years ago
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    its limit by direct substitution also

  20. hal_stirrup
    • 3 years ago
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    ok . dont for get you can always rate me and write Fan Testimonials.

  21. jessiedeee
    • 3 years ago
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    this one is a bit complicated

  22. jessiedeee
    • 3 years ago
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    lim x sec (x) x---> pi

  23. hal_stirrup
    • 3 years ago
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    ok

  24. hal_stirrup
    • 3 years ago
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    sec meaning secant?

  25. jessiedeee
    • 3 years ago
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    pi sec (pi)

  26. hal_stirrup
    • 3 years ago
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    sec ??????????????????????????????

  27. jessiedeee
    • 3 years ago
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    yesss

  28. hal_stirrup
    • 3 years ago
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    what happend to you? :)

  29. jessiedeee
    • 3 years ago
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    nothing...

  30. hal_stirrup
    • 3 years ago
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    lim_(x->pi) x sec(x) = -pi

  31. hal_stirrup
    • 3 years ago
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    is that clear !

  32. jessiedeee
    • 3 years ago
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    aren't you supposed to plug in pi

  33. hal_stirrup
    • 3 years ago
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    pi has an infinite vale so the answare -pi

  34. hal_stirrup
    • 3 years ago
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    yes but make sure you are clear about: secan=1/cos(x)

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