## jessiedeee 3 years ago HELP??? Limits by Direct Substitution FInd the limits. lim 3sq.root2x^2-10 x----> 3

1. jessiedeee

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2. jessiedeee

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3. jessiedeee

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4. hal_stirrup

good

5. jessiedeee

IS IT RIGHT?

6. jessiedeee

@hal_stirrup

7. hal_stirrup

as limit approches 3 , we call it 3 and solve as you did.

8. jessiedeee

soo I solved it correctly?:)

9. hal_stirrup

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10. hal_stirrup

lim_(x->3) (2 x^2-10)^(1/3) = 2

11. hal_stirrup

you arithmetic in wrong but you have the idea right.

12. jessiedeee

awww ... ok I thought I was getting it :/

13. hal_stirrup

you are but simple arithmetic mistake .

14. jessiedeee

(2 x^2-10)^(1/3) = 2 <---- where'd the 1/3 come from on here...

15. hal_stirrup

^^(1/3) = 3sq.root

16. hal_stirrup

anther way of writing it. thats all

17. jessiedeee

oh ok thank you so much!

18. jessiedeee

will you help me with one more??

19. jessiedeee

its limit by direct substitution also

20. hal_stirrup

ok . dont for get you can always rate me and write Fan Testimonials.

21. jessiedeee

this one is a bit complicated

22. jessiedeee

lim x sec (x) x---> pi

23. hal_stirrup

ok

24. hal_stirrup

sec meaning secant?

25. jessiedeee

pi sec (pi)

26. hal_stirrup

sec ??????????????????????????????

27. jessiedeee

yesss

28. hal_stirrup

what happend to you? :)

29. jessiedeee

nothing...

30. hal_stirrup

lim_(x->pi) x sec(x) = -pi

31. hal_stirrup

is that clear !

32. jessiedeee

aren't you supposed to plug in pi

33. hal_stirrup

pi has an infinite vale so the answare -pi

34. hal_stirrup

yes but make sure you are clear about: secan=1/cos(x)