jessiedeee
HELP???
Limits by Direct Substitution
FInd the limits.
lim 3sq.root2x^210
x> 3



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jessiedeee
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dw:1346625101290:dw

jessiedeee
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dw:1346625172663:dw

jessiedeee
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dw:1346625274472:dw

hal_stirrup
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good

jessiedeee
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IS IT RIGHT?

jessiedeee
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@hal_stirrup

hal_stirrup
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as limit approches 3 , we call it 3 and solve as you did.

jessiedeee
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soo I solved it correctly?:)

hal_stirrup
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dw:1346626250356:dw

hal_stirrup
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lim_(x>3)
(2 x^210)^(1/3) = 2

hal_stirrup
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you arithmetic in wrong but you have the idea right.

jessiedeee
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awww ... ok I thought I was getting it :/

hal_stirrup
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you are but simple arithmetic mistake .

jessiedeee
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(2 x^210)^(1/3) = 2 < where'd the 1/3 come from on here...

hal_stirrup
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^^(1/3) = 3sq.root

hal_stirrup
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anther way of writing it. thats all

jessiedeee
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oh ok thank you so much!

jessiedeee
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will you help me with one more??

jessiedeee
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its limit by direct substitution also

hal_stirrup
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ok . dont for get you can always rate me and write Fan Testimonials.

jessiedeee
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this one is a bit complicated

jessiedeee
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lim x sec (x)
x> pi

hal_stirrup
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ok

hal_stirrup
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sec meaning secant?

jessiedeee
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pi sec (pi)

hal_stirrup
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sec ??????????????????????????????

jessiedeee
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yesss

hal_stirrup
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what happend to you? :)

jessiedeee
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nothing...

hal_stirrup
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lim_(x>pi)
x sec(x) = pi

hal_stirrup
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is that clear !

jessiedeee
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aren't you supposed to plug in pi

hal_stirrup
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pi has an infinite vale so the answare pi

hal_stirrup
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yes but make sure you are clear about: secan=1/cos(x)