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HELP???
Limits by Direct Substitution
FInd the limits.
lim 3sq.root2x^210
x> 3
 one year ago
 one year ago
HELP??? Limits by Direct Substitution FInd the limits. lim 3sq.root2x^210 x> 3
 one year ago
 one year ago

This Question is Closed

jessiedeeeBest ResponseYou've already chosen the best response.1
dw:1346625101290:dw
 one year ago

jessiedeeeBest ResponseYou've already chosen the best response.1
dw:1346625172663:dw
 one year ago

jessiedeeeBest ResponseYou've already chosen the best response.1
dw:1346625274472:dw
 one year ago

hal_stirrupBest ResponseYou've already chosen the best response.1
as limit approches 3 , we call it 3 and solve as you did.
 one year ago

jessiedeeeBest ResponseYou've already chosen the best response.1
soo I solved it correctly?:)
 one year ago

hal_stirrupBest ResponseYou've already chosen the best response.1
dw:1346626250356:dw
 one year ago

hal_stirrupBest ResponseYou've already chosen the best response.1
lim_(x>3) (2 x^210)^(1/3) = 2
 one year ago

hal_stirrupBest ResponseYou've already chosen the best response.1
you arithmetic in wrong but you have the idea right.
 one year ago

jessiedeeeBest ResponseYou've already chosen the best response.1
awww ... ok I thought I was getting it :/
 one year ago

hal_stirrupBest ResponseYou've already chosen the best response.1
you are but simple arithmetic mistake .
 one year ago

jessiedeeeBest ResponseYou've already chosen the best response.1
(2 x^210)^(1/3) = 2 < where'd the 1/3 come from on here...
 one year ago

hal_stirrupBest ResponseYou've already chosen the best response.1
^^(1/3) = 3sq.root
 one year ago

hal_stirrupBest ResponseYou've already chosen the best response.1
anther way of writing it. thats all
 one year ago

jessiedeeeBest ResponseYou've already chosen the best response.1
oh ok thank you so much!
 one year ago

jessiedeeeBest ResponseYou've already chosen the best response.1
will you help me with one more??
 one year ago

jessiedeeeBest ResponseYou've already chosen the best response.1
its limit by direct substitution also
 one year ago

hal_stirrupBest ResponseYou've already chosen the best response.1
ok . dont for get you can always rate me and write Fan Testimonials.
 one year ago

jessiedeeeBest ResponseYou've already chosen the best response.1
this one is a bit complicated
 one year ago

jessiedeeeBest ResponseYou've already chosen the best response.1
lim x sec (x) x> pi
 one year ago

hal_stirrupBest ResponseYou've already chosen the best response.1
sec meaning secant?
 one year ago

hal_stirrupBest ResponseYou've already chosen the best response.1
sec ??????????????????????????????
 one year ago

hal_stirrupBest ResponseYou've already chosen the best response.1
what happend to you? :)
 one year ago

hal_stirrupBest ResponseYou've already chosen the best response.1
lim_(x>pi) x sec(x) = pi
 one year ago

jessiedeeeBest ResponseYou've already chosen the best response.1
aren't you supposed to plug in pi
 one year ago

hal_stirrupBest ResponseYou've already chosen the best response.1
pi has an infinite vale so the answare pi
 one year ago

hal_stirrupBest ResponseYou've already chosen the best response.1
yes but make sure you are clear about: secan=1/cos(x)
 one year ago
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