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Can someone help me with this question: Using 1.5V cells with internal resistance of 0.05Ohms. a. draw a representation of a12V battery. b.Determine the numbers of cells required c. Calculate the internal resistance of the battery d. Calculate the battery terminal voltage when the load resistance is 10Ohm.

MIT 6.002 Circuits and Electronics, Spring 2007
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From data we have that each cell is represented as an ideal 1.5 V battery with a 0.05 Ohms series resistance: |dw:1346700404204:dw| The total requested voltage is 12V. We can obtain this voltage serially linking together the following number of cells: \[N _{C}=\frac{ V _{T} }{ V _{C} }=\frac{ 12 }{ 1.5 }=8\] |dw:1346700632616:dw| The battery terminal voltage with a load of 100 Ohm can be obtained with the voltage divider formula: |dw:1346700812438:dw|
|dw:1346903761040:dw|
I included the polarities (+ve and _ve) in case of practical connections using the your digital meter probes because I feel it is important

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surely! Anyway, battery symbol says the same.

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