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Dims116

  • 3 years ago

Can someone help me with this question: Using 1.5V cells with internal resistance of 0.05Ohms. a. draw a representation of a12V battery. b.Determine the numbers of cells required c. Calculate the internal resistance of the battery d. Calculate the battery terminal voltage when the load resistance is 10Ohm.

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  1. nick67
    • 3 years ago
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    From data we have that each cell is represented as an ideal 1.5 V battery with a 0.05 Ohms series resistance: |dw:1346700404204:dw| The total requested voltage is 12V. We can obtain this voltage serially linking together the following number of cells: \[N _{C}=\frac{ V _{T} }{ V _{C} }=\frac{ 12 }{ 1.5 }=8\] |dw:1346700632616:dw| The battery terminal voltage with a load of 100 Ohm can be obtained with the voltage divider formula: |dw:1346700812438:dw|

  2. ugochukwu
    • 3 years ago
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    |dw:1346903761040:dw|

  3. ugochukwu
    • 3 years ago
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    I included the polarities (+ve and _ve) in case of practical connections using the your digital meter probes because I feel it is important

  4. stefo
    • 3 years ago
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    surely! Anyway, battery symbol says the same.

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