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anonymous
 4 years ago
the factor 3m^3+5m^212m20 help me plezz i have one day to finsh last resort
anonymous
 4 years ago
the factor 3m^3+5m^212m20 help me plezz i have one day to finsh last resort

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cathyangs
 4 years ago
Best ResponseYou've already chosen the best response.0Ok, well I would start out by looking at the coefficients. Those are: 3, 5, 12, and 20. Do any of those have any factors in common? :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.03 has 12in common and 5 has 20 in common

cathyangs
 4 years ago
Best ResponseYou've already chosen the best response.0Yes, so if you group the ones that have something in common with each other together...

cathyangs
 4 years ago
Best ResponseYou've already chosen the best response.0If you group the monomials (3m^3 is one monomial) that have factors in common together...you're basically just grouping the 3coefficient monomial with the 12 coefficient monomial, and the same for the 5 and 20 ones. Then you can divide out the factor that each group has in common.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so for 3and 12 the grouping would be 4 and the grouping for 5 and 20 is 4 right?

cathyangs
 4 years ago
Best ResponseYou've already chosen the best response.0Yes! So if you use the "reverse distributive property" on each group?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0reverse distributive property ?

cathyangs
 4 years ago
Best ResponseYou've already chosen the best response.0If you apply the distributive property, but reverse it. Instead of multiplying everything in parenthesis by the same thing, you divide "out" a common factor.

cathyangs
 4 years ago
Best ResponseYou've already chosen the best response.0um...Not quite. Do you know what a factor is? The GCF, or Greatest Common Factor of two numbers is the largest number that both of those numbers can both be evenly divide by. To put it simply, here's an example: the GCF of 40 and 8 is 8, because both 40 and 8 are evenly divisible y 8, with no remainders. Now fiind the GCF for 3 and 12 and the numbers 5 and 20

cathyangs
 4 years ago
Best ResponseYou've already chosen the best response.0That's right. And now, can you group the numbers, and divide out the GCF for each group?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so 3 in to 3 is one 3 in to 12 is 4 5 in to 5 is one 5 in to 20 is 4

cathyangs
 4 years ago
Best ResponseYou've already chosen the best response.0Yes. Can you rewrite each group with parenthesis around the quotients? ( the 3 and 4 in the first group, for example)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0(3/3)=1 (3/12)=4 (5/5)=1 (5/20)=4

cathyangs
 4 years ago
Best ResponseYou've already chosen the best response.0XD ok, that's one way to write it. Here's more of what I was looking for: For the first group: 3m^312m is rewritten as 3 (m^34) Try the second group.

cathyangs
 4 years ago
Best ResponseYou've already chosen the best response.0Sorry, just a family thing. That's right! (but remember to close the parenthesis) Now look back at the first one. What other factor do the two monomials inside the parenthesis have in common? (Big 'ol hint, it's a variable)

cathyangs
 4 years ago
Best ResponseYou've already chosen the best response.0And you can pull that out of the parenthesis, right? :) So now, write the two groups added together (since they were two parts of the same equation in the beginning)

cathyangs
 4 years ago
Best ResponseYou've already chosen the best response.0*added together. you need a plus sign in there...also, double check each of the "groups" You forgot the m in the first one, and 20 should be something else in the second one ;)
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