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sandy2413

the factor 3m^3+5m^2-12m-20 help me plezz i have one day to finsh last resort

  • one year ago
  • one year ago

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  1. cathyangs
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    Ok, well I would start out by looking at the coefficients. Those are: 3, 5, -12, and -20. Do any of those have any factors in common? :)

    • one year ago
  2. sandy2413
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    3 has -12in common and 5 has -20 in common

    • one year ago
  3. cathyangs
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    Yes, so if you group the ones that have something in common with each other together...

    • one year ago
  4. sandy2413
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    what im lost

    • one year ago
  5. cathyangs
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    If you group the monomials (3m^3 is one monomial) that have factors in common together...you're basically just grouping the 3-coefficient monomial with the -12 coefficient monomial, and the same for the 5 and -20 ones. Then you can divide out the factor that each group has in common.

    • one year ago
  6. sandy2413
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    so for 3and -12 the grouping would be -4 and the grouping for 5 and -20 is -4 right?

    • one year ago
  7. cathyangs
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    Yes! So if you use the "reverse distributive property" on each group?

    • one year ago
  8. sandy2413
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    reverse distributive property ?

    • one year ago
  9. cathyangs
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    If you apply the distributive property, but reverse it. Instead of multiplying everything in parenthesis by the same thing, you divide "out" a common factor.

    • one year ago
  10. sandy2413
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    so (3-20)4 like that

    • one year ago
  11. cathyangs
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    um...Not quite. Do you know what a factor is? The GCF, or Greatest Common Factor of two numbers is the largest number that both of those numbers can both be evenly divide by. To put it simply, here's an example: the GCF of 40 and 8 is 8, because both 40 and 8 are evenly divisible y 8, with no remainders. Now fiind the GCF for 3 and -12 and the numbers 5 and -20

    • one year ago
  12. sandy2413
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    3 and 5

    • one year ago
  13. cathyangs
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    That's right. And now, can you group the numbers, and divide out the GCF for each group?

    • one year ago
  14. sandy2413
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    so 3 in to 3 is one 3 in to 12 is 4 5 in to 5 is one 5 in to 20 is 4

    • one year ago
  15. cathyangs
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    Yes. Can you rewrite each group with parenthesis around the quotients? ( the 3 and 4 in the first group, for example)

    • one year ago
  16. sandy2413
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    (3/3)=1 (3/12)=4 (5/5)=1 (5/20)=4

    • one year ago
  17. cathyangs
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    XD ok, that's one way to write it. Here's more of what I was looking for: For the first group: 3m^3-12m is rewritten as 3 (m^3-4) Try the second group.

    • one year ago
  18. sandy2413
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    5m^2-20 5(m^2-4

    • one year ago
  19. sandy2413
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    so was that right

    • one year ago
  20. sandy2413
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    cathyangs u there

    • one year ago
  21. cathyangs
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    Sorry, just a family thing. That's right! (but remember to close the parenthesis) Now look back at the first one. What other factor do the two monomials inside the parenthesis have in common? (Big 'ol hint, it's a variable)

    • one year ago
  22. sandy2413
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    m

    • one year ago
  23. cathyangs
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    And you can pull that out of the parenthesis, right? :) So now, write the two groups added together (since they were two parts of the same equation in the beginning)

    • one year ago
  24. sandy2413
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    3(m^3-4)5(m^2-20)

    • one year ago
  25. sandy2413
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    like this

    • one year ago
  26. cathyangs
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    *added together. you need a plus sign in there...also, double check each of the "groups" You forgot the m in the first one, and -20 should be something else in the second one ;)

    • one year ago
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