A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
Rafael estimates that it costs $14 to produce each unit of a
particular commodity that sells for $23 per unit. There is also a
ﬁxed cost of $1,200.
1 Express the cost C (x ), the revenue R (x ) and the proﬁt P (x )
anonymous
 3 years ago
Rafael estimates that it costs $14 to produce each unit of a particular commodity that sells for $23 per unit. There is also a ﬁxed cost of $1,200. 1 Express the cost C (x ), the revenue R (x ) and the proﬁt P (x )

This Question is Closed

gw2011
 3 years ago
Best ResponseYou've already chosen the best response.1C(x)=14x+1200 R(x)=23x P(x)=23x(14x+1200)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so P(X) isn't 9x1200

gw2011
 3 years ago
Best ResponseYou've already chosen the best response.1The profit=revenuecost. The cost has a variable part (14x) and a fixed part (1200).

gw2011
 3 years ago
Best ResponseYou've already chosen the best response.1In other words, P(x)=R(x)C(x)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh ok so how would you find the average profit function AP(x)?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0and smallest number of units needed to produce for a profit?

gw2011
 3 years ago
Best ResponseYou've already chosen the best response.1To answer your question if P(x)=9x1200 is correct, the answer is yes it is correct because if you simplify P(x)=23x(14x+1200), then you get P(x)=9x1200. The average profit is calculated by dividing by the numberof units produced. This comes out to: AP(x)=(9x1200)/x To find the samllest number of units needed to get a profit you do the following: 9x1200=0 9x=1200 x=1200/9 x=133.3=134 Therefore, the smallest number of units needed to get a profit is 134. If you substitute this value into P(x)=9x1200, you get: P(x)=9(134)1200 P(x)=12061200 P(x)=6

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thanks. so do you express R(x) when x units of product are sold at p thousand dollars per unit where p=6x+100

gw2011
 3 years ago
Best ResponseYou've already chosen the best response.1If I understand your question, then I get the following: R(x)=px R(x)=(6x+100)x R(x)=6x^2+100x

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0just to verify... how would you express revenue for a product that sells for 110/unit. total cost is fixed overhead of 7500 plus production cost of 60/unit would it be: R(x)= 110 P(x)= 50x+7500

gw2011
 3 years ago
Best ResponseYou've already chosen the best response.1R(x)=110x Profit=RevenueCost P(x)=110x(60x+7500) P(x)=110x60x7500 P(x)=50x7500

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok. so how would you find P(x) with the price of unit is p=4.2 0.01x and the cost of production is C(x)=0.002x^2 + 30

gw2011
 3 years ago
Best ResponseYou've already chosen the best response.1With p=4.20.01x and C(x)=0.002x^2+30 doesn't look right to me because this will work out to be negatives as follows: Profit=RevenueCosts P(x)=(4.20.01x)(0.002x^2+30) P(x)=4.20.01x0.002x^230 P(x)=0.002x^20.01x25.8 Unless there is something missing, the above indicates that it comes out to being a negative with no profit.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yea. that's what I got, just wasn't sure about it thanks
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.