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ErinWeeks
 3 years ago
Help would be appreciated (:
Find the values of the 30th and 90th percentiles of the data. 129, 113, 200, 100, 105, 132, 100, 176, 146, 152
A. 30th percentile = 105; 90th percentile = 200
B. 30th percentile = 113; 90th percentile = 200
C. 30th percentile = 105; 90th percentile = 176
D. 30th percentile = 113; 90th percentile = 176
ErinWeeks
 3 years ago
Help would be appreciated (: Find the values of the 30th and 90th percentiles of the data. 129, 113, 200, 100, 105, 132, 100, 176, 146, 152 A. 30th percentile = 105; 90th percentile = 200 B. 30th percentile = 113; 90th percentile = 200 C. 30th percentile = 105; 90th percentile = 176 D. 30th percentile = 113; 90th percentile = 176

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ErinWeeks
 3 years ago
Best ResponseYou've already chosen the best response.0@jim_thompson5910 .. do you know this ?

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.10First sort the values 129, 113, 200, 100, 105, 132, 100, 176, 146, 152 becomes 100, 100, 105, 113, 129, 132, 146, 152, 176, 200

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.10The 30th percentile is the point where 30% of the data is below that value

ErinWeeks
 3 years ago
Best ResponseYou've already chosen the best response.0but them in order . okay ! i did that part . & what does that mean ?

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.10So if you have say 100 values, then 30% of that (0.3*100 = 30 values) are below the 30th percentile

ErinWeeks
 3 years ago
Best ResponseYou've already chosen the best response.0so in this case we have 10 right .

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.10yes, I'm looking up a percentile formula now, one sec

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.10hmm there are multiple percentile formulas, so it depends on what your book says...do you have your book with you?

ErinWeeks
 3 years ago
Best ResponseYou've already chosen the best response.0yes let me look quick !

ErinWeeks
 3 years ago
Best ResponseYou've already chosen the best response.0my book doesnt have a formula .. it just says percentiles : seperate data sets into 100 equal parts

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.10well i found one formula to be n = (P/100)*N + 1/2 So the 30th percentile is at... n = (30/100)*10 + 1/2 n = 300/100 + 1/2 n = 3 + 1/2 n = 3.5 which rounds to n = 4, so the 4th value (which is 113) is the 30th percentile

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.10If we use the same formula for the 90th percentile, then... n = (P/100)*N + 1/2 So the 30th percentile is at... n = (90/100)*10 + 1/2 n = 900/100 + 1/2 n = 9 + 1/2 n = 9.5 which rounds to 10 so the 10th value, which is 200, is the 90th percentile

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.10so if we're using the correct formula (I hope we are), then the answer is B. 30th percentile = 113; 90th percentile = 200

ErinWeeks
 3 years ago
Best ResponseYou've already chosen the best response.0okay i get that ! (: thank you so much

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.10let me know if it's the right answer or not

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yup, you were right :)

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.10thanks for the confirmation

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thanks for explaining :)

LaurenBrianna1917
 one month ago
Best ResponseYou've already chosen the best response.0I did it a different way and go a different answer. I used the same formula. 100,100,105,113,129,132,146,152,176,200 n=(p/100)*n n=(30/100)*10 n=0.3*10 n=3 Answer: 3 values fall at or below 105 the value at the 30th percentile. n=(p/100)*n n=90/100*10 n=0.9*10 n=9 Answer: 9 values fall at or below 176 the value at the 90th percentile. I know this problem has been solved already but its just for anyone has this problem too. Hope it helps (: !!!
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