anonymous
  • anonymous
question below
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
\[nC4 + nC5\]
anonymous
  • anonymous
use d formula for n c r and do d simplification
anonymous
  • anonymous
nCr= n!/ r! (n-r)!

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More answers

anonymous
  • anonymous
is it ok if you show me, kinda new to this
anonymous
  • anonymous
n!/ 4! (n-4)! + n!/ 5! (n-5)!
anonymous
  • anonymous
n(n-1)(n-2)(n-3)/24 + n(n-1)(n-2)(n-3)(n-4)/ 120
anonymous
  • anonymous
it's ok?
anonymous
  • anonymous
i still can't see it
anonymous
  • anonymous
see... n!= 1.2.3.4....n
anonymous
  • anonymous
right?
anonymous
  • anonymous
yes
anonymous
  • anonymous
n!/ (n-4)! = 1.2.3....(n-4)(n-3)(n-2)(n-1)n / (1.2.3....(n-4))
anonymous
  • anonymous
yeah...
anonymous
  • anonymous
so now u can solve ur problem....:)
anonymous
  • anonymous
let me try
anonymous
  • anonymous
n(n-1)(n-2)(n-3)/24 + n(n-1)(n-2)(n-3)(n-4)/ 120
anonymous
  • anonymous
i got that, but how do you simplify further?
anonymous
  • anonymous
LOL @hba looks like you have no choice but to help this damsel in distress
hba
  • hba
@virtus i dont think so lol
anonymous
  • anonymous
16Cn +16C9 =17C9
anonymous
  • anonymous
FIND "n"
anonymous
  • anonymous
why not @hba
hba
  • hba
Its been along time ive studied it and i dont want to get you into another confusion :(
anonymous
  • anonymous
OH LOL ok then
anonymous
  • anonymous
16Cn +16C9 =17C9 16Cn+16C9=16C9 + 16C8 16Cn=16C8 n=8
anonymous
  • anonymous
use the identity nCr + nC(r-1) = (n+1)Cr

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