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virtus

  • 2 years ago

16Cn +16C9 =17C9

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  1. lgbasallote
    • 2 years ago
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    \[16Cn \implies \frac{16!}{n!(16-n)!}\] \[16C9 \implies \frac{16!}{9!(16-9)!} \] \[17C9 \implies \frac{17!}{9!(17-9)!}\] does that help?

  2. virtus
    • 2 years ago
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    so how do you find n?

  3. hartnn
    • 2 years ago
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    u know that property: \[^nC_r+^nC_{r-1}=^{n+1}C_r\] ?

  4. hartnn
    • 2 years ago
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    @virtus use this property, and put n=16,r=9 so now can u find your 'n' ??

  5. satellite73
    • 2 years ago
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    oh i see, your job is to find \(n\) for thie equality correct?

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