mayankdevnani
  • mayankdevnani
Very Confusing Question .....????
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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mayankdevnani
  • mayankdevnani
Can We found INTEGERS between TWO INTEGERS..True or False?? Why or Why not?
mayankdevnani
  • mayankdevnani
@mathslover
mayankdevnani
  • mayankdevnani
@KingAditya

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More answers

mayankdevnani
  • mayankdevnani
@UnkleRhaukus
mayankdevnani
  • mayankdevnani
@mukushla
mathslover
  • mathslover
ahha must say that grammatical mistake : can we found? or can we find?
mathslover
  • mathslover
may or may not ....
mayankdevnani
  • mayankdevnani
don't try to point out mistake @mathslover
mathslover
  • mathslover
False...
mayankdevnani
  • mayankdevnani
why?? @mathslover
mayankdevnani
  • mayankdevnani
why??
mayankdevnani
  • mayankdevnani
plz help @mathslover
mathslover
  • mathslover
now .... because 5 and 4 are integers so we have no integer between them
mathslover
  • mathslover
but still we have 5 and 8 that is 6,7 are the integers between 5 and 8 hence it is may or may not be
mayankdevnani
  • mayankdevnani
we can find by average method...
anonymous
  • anonymous
Well there are always two sides of the coin... Yes you can find a find a integer in between two if the differ by atleast 1
mathslover
  • mathslover
ok so let us take : 5 and 6 (5+6)/2 = 11/2 (not an integer) @mayankdevnani
mayankdevnani
  • mayankdevnani
for ex @punnus
mathslover
  • mathslover
@mayankdevnani the example is given by me... 5 and 6 and 5 and 8
mayankdevnani
  • mayankdevnani
let us 4 and 1 @mathslover
anonymous
  • anonymous
are you looking for more than none integer between the 2 or even one will work
mathslover
  • mathslover
(4+1)/2 = 5/2 ( not an integer ) though we have 2 and 3 as integers between 4 and 1
mayankdevnani
  • mayankdevnani
oh !! sry 3 and 1
mathslover
  • mathslover
(3+1)/2 = 4/2 =2 (an integer) it only works in some cases
mathslover
  • mathslover
I will say "may or may not be" in this quest.
mayankdevnani
  • mayankdevnani
so, what's answer
anonymous
  • anonymous
is the question "we can always find..."
mayankdevnani
  • mayankdevnani
no @satellite73
mathslover
  • mathslover
I hope for another option " may or may not be " or "none of these"
mayankdevnani
  • mayankdevnani
i think!! thnx..
mathslover
  • mathslover
You r welcome ....

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