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A ball of mass m bounces back b/w two surfaces with a speed u . a) find the average force on each wall. b) If one surface slowly move toward the other with a speed of v <<<< u .find the force exerted by the ball on moving surface .the gravity is neglected & the collision is perfectly elastic.

Physics
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a. if 2l is smaller than u....then no of collisions per sec= u / 2l so av force on each wall= change in momentum per second av force= (2mu)* u/2l
can u plz elaborate..

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Other answers:

tell me...where u got stuck in part 'a' answer?
do u agree that no of collisions per sec= u/2l?
distance traveled by ball in 1s= u m
how i solve 1st part ?
1st...how many times the ball will collide with any one of the wall in 1s?
distance traveled by ball in 1s= u m.....right?
i don't know
speed of ball is u m/s...so how much distance it'll travel in 1 second?
u know hindi
yes

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