## rishabh.mission 3 years ago A ball of mass m bounces back b/w two surfaces with a speed u . a) find the average force on each wall. b) If one surface slowly move toward the other with a speed of v <<<< u .find the force exerted by the ball on moving surface .the gravity is neglected & the collision is perfectly elastic.

1. rishabh.mission

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2. akash123

a. if 2l is smaller than u....then no of collisions per sec= u / 2l so av force on each wall= change in momentum per second av force= (2mu)* u/2l

3. rishabh.mission

can u plz elaborate..

4. akash123

tell me...where u got stuck in part 'a' answer?

5. akash123

do u agree that no of collisions per sec= u/2l?

6. akash123

distance traveled by ball in 1s= u m

7. rishabh.mission

how i solve 1st part ?

8. akash123

1st...how many times the ball will collide with any one of the wall in 1s?

9. akash123

distance traveled by ball in 1s= u m.....right?

10. rishabh.mission

i don't know

11. akash123

speed of ball is u m/s...so how much distance it'll travel in 1 second?

12. rishabh.mission

u know hindi

13. akash123

yes