rishabh.mission
A ball of mass m bounces back b/w two surfaces with a speed u .
a) find the average force on each wall.
b) If one surface slowly move toward the other with a speed of v <<<< u .find the force exerted by the ball on moving surface .the gravity is neglected & the collision is perfectly elastic.
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rishabh.mission
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|dw:1346771852468:dw|
akash123
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a. if 2l is smaller than u....then no of collisions per sec= u / 2l
so av force on each wall= change in momentum per second
av force= (2mu)* u/2l
rishabh.mission
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can u plz elaborate..
akash123
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tell me...where u got stuck in part 'a' answer?
akash123
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do u agree that no of collisions per sec= u/2l?
akash123
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distance traveled by ball in 1s= u m
rishabh.mission
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how i solve 1st part ?
akash123
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1st...how many times the ball will collide with any one of the wall in 1s?
akash123
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distance traveled by ball in 1s= u m.....right?
rishabh.mission
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i don't know
akash123
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speed of ball is u m/s...so how much distance it'll travel in 1 second?
rishabh.mission
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u know hindi
akash123
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yes