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rishabh.mission

  • 3 years ago

A ball of mass m bounces back b/w two surfaces with a speed u . a) find the average force on each wall. b) If one surface slowly move toward the other with a speed of v <<<< u .find the force exerted by the ball on moving surface .the gravity is neglected & the collision is perfectly elastic.

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  1. rishabh.mission
    • 3 years ago
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    |dw:1346771852468:dw|

  2. akash123
    • 3 years ago
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    a. if 2l is smaller than u....then no of collisions per sec= u / 2l so av force on each wall= change in momentum per second av force= (2mu)* u/2l

  3. rishabh.mission
    • 3 years ago
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    can u plz elaborate..

  4. akash123
    • 3 years ago
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    tell me...where u got stuck in part 'a' answer?

  5. akash123
    • 3 years ago
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    do u agree that no of collisions per sec= u/2l?

  6. akash123
    • 3 years ago
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    distance traveled by ball in 1s= u m

  7. rishabh.mission
    • 3 years ago
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    how i solve 1st part ?

  8. akash123
    • 3 years ago
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    1st...how many times the ball will collide with any one of the wall in 1s?

  9. akash123
    • 3 years ago
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    distance traveled by ball in 1s= u m.....right?

  10. rishabh.mission
    • 3 years ago
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    i don't know

  11. akash123
    • 3 years ago
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    speed of ball is u m/s...so how much distance it'll travel in 1 second?

  12. rishabh.mission
    • 3 years ago
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    u know hindi

  13. akash123
    • 3 years ago
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    yes

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