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CliffSedgeBest ResponseYou've already chosen the best response.1
Is there a diagram to go with this information?
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
Thank you. Can we assume AP is tangent to the circle and that BE is a diameter?
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
Well, first thing that comes to mind (because I can't remember the tangentchord theorems off the top of my head right now..) is that you can form a right triangle AOP with O the center of the circle and AO a radius. From there you can use Pythagoras' theorem to get the missing lengths.
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
It's not very direct, but will work.
 one year ago

Dallasb22Best ResponseYou've already chosen the best response.0
How can AOP form a right triangle? I drew the line(auxillary lines) and it appears acute.
 one year ago

Dallasb22Best ResponseYou've already chosen the best response.0
Angle AOP being acute.
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
Yes. Angle OAP is the right angle because tangents to a circle are always at right angles to their radii.
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
I think that's the preliminary proposition that is used to prove the various tangent and chord theorems. I like this website for reviewing such things: http://www.mathwarehouse.com/geometry/circle/tangentsecantsidelength.php
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
Line OEP is therefore the hypotenuse, and when you add OB=OA, you get BP. Yes, OA is a radius so is half the diameter BE.
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
Oh, that's nice, everything works out to rational numbers. Very kind of them . . .
 one year ago

Dallasb22Best ResponseYou've already chosen the best response.0
dw:1346780775442:dw
 one year ago

Dallasb22Best ResponseYou've already chosen the best response.0
I'm still not sure how to find EP?
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
I don't think you need EP, but did you use Pythagoras' theorem to get OP?
 one year ago

Dallasb22Best ResponseYou've already chosen the best response.0
10(^2)+10.5(^2)=c(^2) I get 210.25???
 one year ago

Dallasb22Best ResponseYou've already chosen the best response.0
I was going to find EP. Then add BE+EP=BP
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
(take square root of c^2)
 one year ago

Dallasb22Best ResponseYou've already chosen the best response.0
Ahhh. 14.5 + 10.5 correct? Equaling 25
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
If you use the theorem from that website I linked to, it shows the following: dw:1346781296754:dw Which when you simplify and put into standard form yields the quadratic equation x^2+21x100=0. I find that unnecessary if you don't like quadratics. Either way it includes an extra step and Pythagoras' theorem gets us there just as easily.
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
Yes, the solutions to that quadratic equation are x=4 and x=25. Throw out the negative length as meaningless, and EP=4; add that to the diameter and BP=25.
 one year ago

Dallasb22Best ResponseYou've already chosen the best response.0
Okay good. Sometimes I just need someone to make me ask myself the right questions.
 one year ago

Dallasb22Best ResponseYou've already chosen the best response.0
Thanks for helping! I have another if you don't mind...?
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
I usually never bother to remember such specific theorems, I prefer to deduce everything from more basic stuff that is easy to remember.
 one year ago

Dallasb22Best ResponseYou've already chosen the best response.0
Yes, and the PT is very easy.
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
Exactly, it shows up everywhere; only thing you had to remember is that tangents are perpendicular to radii.
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
Might as well start a new thread for your next question; maybe we can get others to jump in and add their insights as well.
 one year ago
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