kymber
\(f(27)=\) \(\sqrt{2x5}\)



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ajprincess
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What do u need to find?

arlen
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put x= 27

kymber
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Find f(27) it says.. I get to \(16=\)\(\sqrt{x}\) And don't know what to do then.

arlen
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f(27)=7

kymber
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How, nya?

arlen
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\[f(27)= \sqrt{2*275}= \sqrt 49=7\]

kymber
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Oh. You put 27 in for x? :I

kymber
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Thank you.

arlen
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yes

arlen
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:)

ajprincess
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