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kymber

\(f(27)=\) \(\sqrt{2x-5}\)

  • one year ago
  • one year ago

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  1. ajprincess
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    What do u need to find?

    • one year ago
  2. arlen
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    put x= 27

    • one year ago
  3. kymber
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    Find f(27) it says.. I get to \(16=\)\(\sqrt{x}\) And don't know what to do then.

    • one year ago
  4. arlen
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    f(27)=7

    • one year ago
  5. kymber
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    How, nya?

    • one year ago
  6. arlen
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    \[f(27)= \sqrt{2*27-5}= \sqrt 49=7\]

    • one year ago
  7. kymber
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    Oh. You put 27 in for x? :I

    • one year ago
  8. kymber
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    Thank you.

    • one year ago
  9. arlen
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    yes

    • one year ago
  10. arlen
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    :)

    • one year ago
  11. ajprincess
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    |dw:1346779997510:dw|

    • one year ago
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