kymber
  • kymber
\(f(27)=\) \(\sqrt{2x-5}\)
Mathematics
schrodinger
  • schrodinger
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ajprincess
  • ajprincess
What do u need to find?
arlen
  • arlen
put x= 27
kymber
  • kymber
Find f(27) it says.. I get to \(16=\)\(\sqrt{x}\) And don't know what to do then.

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arlen
  • arlen
f(27)=7
kymber
  • kymber
How, nya?
arlen
  • arlen
\[f(27)= \sqrt{2*27-5}= \sqrt 49=7\]
kymber
  • kymber
Oh. You put 27 in for x? :I
kymber
  • kymber
Thank you.
arlen
  • arlen
yes
arlen
  • arlen
:)
ajprincess
  • ajprincess
|dw:1346779997510:dw|

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