anonymous
  • anonymous
x^2 - 36 / x - 6
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
whr r u stuck
anonymous
  • anonymous
x – 6, with the restriction x ≠ –6 x – 6, with the restriction x ≠ 6 x + 6, with the restriction x ≠ 6 x + 6, with the restriction x ≠ –6
jim_thompson5910
  • jim_thompson5910
Hint: Factor x^2 - 36 to get (x+6)(x-6)

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jim_thompson5910
  • jim_thompson5910
Use the difference of squares rule to factor
anonymous
  • anonymous
D?
anonymous
  • anonymous
jim_thompson5910
  • jim_thompson5910
The x-6 terms do cancel to give x+6 So the first part is x+6
jim_thompson5910
  • jim_thompson5910
but the restriction is not x ≠ –6 since x = -6 actually works (x^2 - 36)/(x-6) ((-6)^2 - 36)/(-6-6) (36 - 36)/(-12) 0 So (x^2 - 36)/(x-6) = 0 when x = -6
anonymous
  • anonymous
so B?
jim_thompson5910
  • jim_thompson5910
no, B has x-6 when it should be x+6
anonymous
  • anonymous
\[{\frac {{x}^{2}-36}{x-6}}\] you mean this?
anonymous
  • anonymous
Oh okay! I see now, I think lol... It seems like it would be C then
jim_thompson5910
  • jim_thompson5910
it is C

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