## anonymous 4 years ago x^2 - 36 / x - 6

1. anonymous

whr r u stuck

2. anonymous

x – 6, with the restriction x ≠ –6 x – 6, with the restriction x ≠ 6 x + 6, with the restriction x ≠ 6 x + 6, with the restriction x ≠ –6

3. jim_thompson5910

Hint: Factor x^2 - 36 to get (x+6)(x-6)

4. jim_thompson5910

Use the difference of squares rule to factor

5. anonymous

D?

6. anonymous

@jim_thompson5910

7. jim_thompson5910

The x-6 terms do cancel to give x+6 So the first part is x+6

8. jim_thompson5910

but the restriction is not x ≠ –6 since x = -6 actually works (x^2 - 36)/(x-6) ((-6)^2 - 36)/(-6-6) (36 - 36)/(-12) 0 So (x^2 - 36)/(x-6) = 0 when x = -6

9. anonymous

so B?

10. jim_thompson5910

no, B has x-6 when it should be x+6

11. anonymous

${\frac {{x}^{2}-36}{x-6}}$ you mean this?

12. anonymous

Oh okay! I see now, I think lol... It seems like it would be C then

13. jim_thompson5910

it is C

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