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lindseyharrison

  • 2 years ago

x^2 - 36 / x - 6

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  1. telltoamit
    • 2 years ago
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    whr r u stuck

  2. lindseyharrison
    • 2 years ago
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    x – 6, with the restriction x ≠ –6 x – 6, with the restriction x ≠ 6 x + 6, with the restriction x ≠ 6 x + 6, with the restriction x ≠ –6

  3. jim_thompson5910
    • 2 years ago
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    Hint: Factor x^2 - 36 to get (x+6)(x-6)

  4. jim_thompson5910
    • 2 years ago
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    Use the difference of squares rule to factor

  5. lindseyharrison
    • 2 years ago
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    D?

  6. lindseyharrison
    • 2 years ago
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    @jim_thompson5910

  7. jim_thompson5910
    • 2 years ago
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    The x-6 terms do cancel to give x+6 So the first part is x+6

  8. jim_thompson5910
    • 2 years ago
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    but the restriction is not x ≠ –6 since x = -6 actually works (x^2 - 36)/(x-6) ((-6)^2 - 36)/(-6-6) (36 - 36)/(-12) 0 So (x^2 - 36)/(x-6) = 0 when x = -6

  9. lindseyharrison
    • 2 years ago
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    so B?

  10. jim_thompson5910
    • 2 years ago
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    no, B has x-6 when it should be x+6

  11. timo86m
    • 2 years ago
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    \[{\frac {{x}^{2}-36}{x-6}}\] you mean this?

  12. lindseyharrison
    • 2 years ago
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    Oh okay! I see now, I think lol... It seems like it would be C then

  13. jim_thompson5910
    • 2 years ago
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    it is C

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