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lindseyharrisonBest ResponseYou've already chosen the best response.1
x – 6, with the restriction x ≠ –6 x – 6, with the restriction x ≠ 6 x + 6, with the restriction x ≠ 6 x + 6, with the restriction x ≠ –6
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
Hint: Factor x^2  36 to get (x+6)(x6)
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
Use the difference of squares rule to factor
 one year ago

lindseyharrisonBest ResponseYou've already chosen the best response.1
@jim_thompson5910
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
The x6 terms do cancel to give x+6 So the first part is x+6
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
but the restriction is not x ≠ –6 since x = 6 actually works (x^2  36)/(x6) ((6)^2  36)/(66) (36  36)/(12) 0 So (x^2  36)/(x6) = 0 when x = 6
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
no, B has x6 when it should be x+6
 one year ago

timo86mBest ResponseYou've already chosen the best response.0
\[{\frac {{x}^{2}36}{x6}}\] you mean this?
 one year ago

lindseyharrisonBest ResponseYou've already chosen the best response.1
Oh okay! I see now, I think lol... It seems like it would be C then
 one year ago
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