Given: AB is diameter, BC is tangent to circle O. Prove: AXB~ABC

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Given: AB is diameter, BC is tangent to circle O. Prove: AXB~ABC

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Hmm, ok, seeing a couple things here ..
There you are. :)

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Other answers:

Angle CBA is right angle, but not for reason given. It is not inscribed in the circle.
Sorry for delay, was giving help on 3D coordinates in space...
Looks like you have those two reasons switched in lines 3 and 4.
Likewise, lines 5 and 6 need to be switched.
I can't see those any longer, I cleared the sheet.
SO far i have, AB is diameter, BC is tangent to circle O: GIVEN
Ah. Can you still see this pic? http://assets.openstudy.com/updates/attachments/5046434ae4b08ef7b166cfbd-dallasb22-1346782099850-untitled.png
Angle A = Angle A: REFLEXIVE
There we go. *FacePalm*
I think you can take it from here. :-)
Yes, mind if i post another Screeny for you to look over?
Go ahead. If I'm wandering around elsewhere, just tag my name to it @Cliffsedge
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Looks good to me.
Thanks very much!

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