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lindseyharrison
 2 years ago
Best ResponseYou've already chosen the best response.0I don't see the simplifies result @MarkRijckenberg

CliffSedge
 2 years ago
Best ResponseYou've already chosen the best response.0Is this the expression you're looking at? \[\frac{\frac{4x}{x^2  9}}{\frac{8x^2}{x^2 + 6x + 9}}\]

CliffSedge
 2 years ago
Best ResponseYou've already chosen the best response.0It's a bit ambiguous when written out horizontally like that. I recommend liberal use of parentheses.

lindseyharrison
 2 years ago
Best ResponseYou've already chosen the best response.0Yes that is correct.

CliffSedge
 2 years ago
Best ResponseYou've already chosen the best response.0If you're going to enter it into a calculator (or wolframalpha), then you'll need to express it like this: (4x/(x^2  9)) / ((8x^2)/(x^2 + 6x + 9)) Even then, I tried that in wolframalpha, and it didn't give the fully simplified result.

timo86m
 2 years ago
Best ResponseYou've already chosen the best response.0\[1/2\,{\frac {x+3}{ \left( x3 \right) x}}\]

CliffSedge
 2 years ago
Best ResponseYou've already chosen the best response.0Best first step is to express the fractiondivision as fractionmulitplication. (Division is defined as multiplication by the reciprcal.) Then factor the crap out of everything and see what cancels.

timo86m
 2 years ago
Best ResponseYou've already chosen the best response.0from wolfram if you type it like this 4*x/((x^29)*(8*x^2/(x^2+6*x+9)))

CliffSedge
 2 years ago
Best ResponseYou've already chosen the best response.0Or you could just write it down and do the algebra . . .

MarkRijckenberg
 2 years ago
Best ResponseYou've already chosen the best response.0Guys, both your formula's give the same results in WolfRam....

CliffSedge
 2 years ago
Best ResponseYou've already chosen the best response.0Yep, and neither shows Lindsey how to do it herself.

CliffSedge
 2 years ago
Best ResponseYou've already chosen the best response.0Intermediate step looks like this: \[\frac{4x}{(x+3)(x3)} \space \times \space \frac{(x+3)(x+3)}{8x^2}\]
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