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Dallasb22
Group Title
Given: DR tangent to Circle O.
If (measure of)DB = 150°, then (angle)A = ?degrees.
 2 years ago
 2 years ago
Dallasb22 Group Title
Given: DR tangent to Circle O. If (measure of)DB = 150°, then (angle)A = ?degrees.
 2 years ago
 2 years ago

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Dallasb22 Group TitleBest ResponseYou've already chosen the best response.0
@CliffSedge
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
More of these shenanigans, eh?
 2 years ago

Dallasb22 Group TitleBest ResponseYou've already chosen the best response.0
Hehe, yup.
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
Which angle is 150º?
 2 years ago

Dallasb22 Group TitleBest ResponseYou've already chosen the best response.0
Arc DB is 150 degrees
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
Oh that's for the arc, ok. then that means that angle BCD is half of that because it is an inscribed angle cutting the same arc.
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
(I'm assuming from the picture that you mean arc BAD and not arc BCD, since it could go either way around the circle.)
 2 years ago

Dallasb22 Group TitleBest ResponseYou've already chosen the best response.0
Yes sorry about that, that's how they put it in on the sheet.
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
I think the easiest way to find A is the same property: inscribed angles are half of the arc they cut, so if arc BAD is 150, then arc BCD is the other part of the circle (the whole thing is 360º remember).
 2 years ago

Dallasb22 Group TitleBest ResponseYou've already chosen the best response.0
Yes arc BCD is 210 So angle A is: 105 degrees
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
Exactly.
 2 years ago
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