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Given: DR tangent to Circle O.
If (measure of)DB = 150°, then (angle)A = ?degrees.
 one year ago
 one year ago
Given: DR tangent to Circle O. If (measure of)DB = 150°, then (angle)A = ?degrees.
 one year ago
 one year ago

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CliffSedgeBest ResponseYou've already chosen the best response.1
More of these shenanigans, eh?
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
Which angle is 150º?
 one year ago

Dallasb22Best ResponseYou've already chosen the best response.0
Arc DB is 150 degrees
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
Oh that's for the arc, ok. then that means that angle BCD is half of that because it is an inscribed angle cutting the same arc.
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
(I'm assuming from the picture that you mean arc BAD and not arc BCD, since it could go either way around the circle.)
 one year ago

Dallasb22Best ResponseYou've already chosen the best response.0
Yes sorry about that, that's how they put it in on the sheet.
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
I think the easiest way to find A is the same property: inscribed angles are half of the arc they cut, so if arc BAD is 150, then arc BCD is the other part of the circle (the whole thing is 360º remember).
 one year ago

Dallasb22Best ResponseYou've already chosen the best response.0
Yes arc BCD is 210 So angle A is: 105 degrees
 one year ago
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