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anonymous
 3 years ago
Given: DR tangent to Circle O.
If (measure of)DB = 150°, then (angle)A = ?degrees.
anonymous
 3 years ago
Given: DR tangent to Circle O. If (measure of)DB = 150°, then (angle)A = ?degrees.

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0More of these shenanigans, eh?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Arc DB is 150 degrees

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Oh that's for the arc, ok. then that means that angle BCD is half of that because it is an inscribed angle cutting the same arc.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0(I'm assuming from the picture that you mean arc BAD and not arc BCD, since it could go either way around the circle.)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yes sorry about that, that's how they put it in on the sheet.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I think the easiest way to find A is the same property: inscribed angles are half of the arc they cut, so if arc BAD is 150, then arc BCD is the other part of the circle (the whole thing is 360º remember).

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yes arc BCD is 210 So angle A is: 105 degrees
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