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Dallasb22

  • 2 years ago

Given: DR tangent to Circle O. If (measure of)DB = 150°, then (angle)A = ?degrees.

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  1. Dallasb22
    • 2 years ago
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  2. Dallasb22
    • 2 years ago
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    @CliffSedge

  3. CliffSedge
    • 2 years ago
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    More of these shenanigans, eh?

  4. Dallasb22
    • 2 years ago
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    Hehe, yup.

  5. CliffSedge
    • 2 years ago
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    Which angle is 150º?

  6. Dallasb22
    • 2 years ago
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    Arc DB is 150 degrees

  7. CliffSedge
    • 2 years ago
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    Oh that's for the arc, ok. then that means that angle BCD is half of that because it is an inscribed angle cutting the same arc.

  8. CliffSedge
    • 2 years ago
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    (I'm assuming from the picture that you mean arc BAD and not arc BCD, since it could go either way around the circle.)

  9. Dallasb22
    • 2 years ago
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    Yes sorry about that, that's how they put it in on the sheet.

  10. CliffSedge
    • 2 years ago
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    I think the easiest way to find A is the same property: inscribed angles are half of the arc they cut, so if arc BAD is 150, then arc BCD is the other part of the circle (the whole thing is 360º remember).

  11. Dallasb22
    • 2 years ago
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    Yes arc BCD is 210 So angle A is: 105 degrees

  12. CliffSedge
    • 2 years ago
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    Exactly.

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