anonymous
  • anonymous
Given: DR tangent to Circle O. If (measure of)DB = 150°, then (angle)A = ?degrees.
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
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anonymous
  • anonymous
anonymous
  • anonymous
More of these shenanigans, eh?

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anonymous
  • anonymous
Hehe, yup.
anonymous
  • anonymous
Which angle is 150º?
anonymous
  • anonymous
Arc DB is 150 degrees
anonymous
  • anonymous
Oh that's for the arc, ok. then that means that angle BCD is half of that because it is an inscribed angle cutting the same arc.
anonymous
  • anonymous
(I'm assuming from the picture that you mean arc BAD and not arc BCD, since it could go either way around the circle.)
anonymous
  • anonymous
Yes sorry about that, that's how they put it in on the sheet.
anonymous
  • anonymous
I think the easiest way to find A is the same property: inscribed angles are half of the arc they cut, so if arc BAD is 150, then arc BCD is the other part of the circle (the whole thing is 360º remember).
anonymous
  • anonymous
Yes arc BCD is 210 So angle A is: 105 degrees
anonymous
  • anonymous
Exactly.

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