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Dallasb22 Group Title

Given: DR tangent to Circle O. If (measure of)DB = 150°, then (angle)A = ?degrees.

  • 2 years ago
  • 2 years ago

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  1. Dallasb22 Group Title
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    • 2 years ago
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    @CliffSedge

    • 2 years ago
  3. CliffSedge Group Title
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    More of these shenanigans, eh?

    • 2 years ago
  4. Dallasb22 Group Title
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    Hehe, yup.

    • 2 years ago
  5. CliffSedge Group Title
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    Which angle is 150º?

    • 2 years ago
  6. Dallasb22 Group Title
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    Arc DB is 150 degrees

    • 2 years ago
  7. CliffSedge Group Title
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    Oh that's for the arc, ok. then that means that angle BCD is half of that because it is an inscribed angle cutting the same arc.

    • 2 years ago
  8. CliffSedge Group Title
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    (I'm assuming from the picture that you mean arc BAD and not arc BCD, since it could go either way around the circle.)

    • 2 years ago
  9. Dallasb22 Group Title
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    Yes sorry about that, that's how they put it in on the sheet.

    • 2 years ago
  10. CliffSedge Group Title
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    I think the easiest way to find A is the same property: inscribed angles are half of the arc they cut, so if arc BAD is 150, then arc BCD is the other part of the circle (the whole thing is 360º remember).

    • 2 years ago
  11. Dallasb22 Group Title
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    Yes arc BCD is 210 So angle A is: 105 degrees

    • 2 years ago
  12. CliffSedge Group Title
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    Exactly.

    • 2 years ago
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