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I have \[\sqrt{-7h}/h\] but it says that is wrong and I can't figure out why

This is pre-calc

All right, then that should be the case.

so you are telling me my answer is right?

/correct

how did you get -7h out from under the root?

This is only useful for evaluating the limit.

I have no idea what you mean by that

why would I multiply the numerator and denominator by that?

My 7 sub 2 is \[\sqrt{21-7h}\]

Y sub 2*

yours simplifies to -7

f(-3+h) = \[\sqrt{-7(3+h)}\]

The original problem looks like the square root goes over the "t"

Yes, and that's how I computed it. What do you feel is wrong with my expression?

I don't understand how there is no square root sign over the 7h in your third comment

Where is there not a square root sign?

Over the "7h"

the 7h that is in the numerator of your third comment

http://imgur.com/1fwvB
This is what I have in my browser and what has been typed.

oh that is weird it doesn't look like that in my browser

so my first comment is correct then

Square root of (-7h) divided by h

No, it is not, as they are not equivalent statements.

yeah it is because square root of (x+y) is equal to square root of x plus square root of y right?

No, it does not.
\[
\sqrt{a+b}\ne\sqrt{a}+\sqrt{b}
\]Unless a or b is zero.

oh jesus I feel like an idiot. So then your third comment does not simplify any further in pre calc?

Nope. I don't think there is any need to, unless you're taking limits.

so last thing square root of x*y is equal to square root of x times the square root of y?

Never mind I just proved it.

Thanks again I'll have to look up a khan academy video on that