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amistre64Best ResponseYou've already chosen the best response.2
My math teacher says that she could not understand my write up
 one year ago

amistre64Best ResponseYou've already chosen the best response.2
It was of course not meant to be a professional dissertation, but just a means of explaining how I got to the final outcome ...
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
maybe his/her computer didn't have microsoft word
 one year ago

amistre64Best ResponseYou've already chosen the best response.2
all the school computers have MS Word installed
 one year ago

amistre64Best ResponseYou've already chosen the best response.2
and if not, the attachment could have been opened in the webpage that the faculty email account uses.
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
maybe he/she expected \(a_1=2, a_2=3, a_n=a_{n1}a_{n2}\)
 one year ago

amistre64Best ResponseYou've already chosen the best response.2
maybe ... but thats just too mundane.
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
i would say this is pretty damn cool. but then again i am too old to know what is cool
 one year ago

amistre64Best ResponseYou've already chosen the best response.2
she even said my setup did not match the 2,3,6 ... which leads me to believe that she either used the wrong expression, or was trying to integrate this along successive intervals ([0,1],[1,2],[2,3]) instead of cumulative intervals ([0,1],[0,2],[0,3]).
 one year ago

amistre64Best ResponseYou've already chosen the best response.2
by the very design of it, it matches. the area from 0 to 1 is 2 the area from 1 to 2 is 1 , 2+1 = 3 the area from 2 to 3 is 3 , 2+1+3 = 6
 one year ago

amistre64Best ResponseYou've already chosen the best response.2
i did learn how to integrate an absolute value tho :) I had gotten it to\[\int xdx=\frac{x^2}{2}+C\]but I couldnt get past that and had to look it up; i was thiiissss close :)\[\int xdx=\frac{xx}{2}+C\]
 one year ago

amistre64Best ResponseYou've already chosen the best response.2
lol, I also figured out the mystery behind continued fractions, at least for rational values \[\frac{9}{49}=\frac{1}{49/9}\] \[\frac{1}{49/9}=\cfrac{1}{5+\cfrac{4}{9}}=\cfrac{1}{5+\cfrac{1}{9/4}}...\]
 one year ago

amistre64Best ResponseYou've already chosen the best response.2
I feel like David Bowie in the Labrynth
 one year ago

amistre64Best ResponseYou've already chosen the best response.2
I devised a way to get an equation with a curve in it too; if we construct the absolute values to match the slopes we want; then integrating it produces the desired graph:dw:1346851055201:dw
 one year ago

amistre64Best ResponseYou've already chosen the best response.2
well, something better shaped that that id imagine lol
 one year ago
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