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amistre64
 2 years ago
Best ResponseYou've already chosen the best response.2My math teacher says that she could not understand my write up

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.2It was of course not meant to be a professional dissertation, but just a means of explaining how I got to the final outcome ...

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1maybe his/her computer didn't have microsoft word

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.2all the school computers have MS Word installed

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.2and if not, the attachment could have been opened in the webpage that the faculty email account uses.

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1maybe he/she expected \(a_1=2, a_2=3, a_n=a_{n1}a_{n2}\)

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.2maybe ... but thats just too mundane.

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1i would say this is pretty damn cool. but then again i am too old to know what is cool

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.2she even said my setup did not match the 2,3,6 ... which leads me to believe that she either used the wrong expression, or was trying to integrate this along successive intervals ([0,1],[1,2],[2,3]) instead of cumulative intervals ([0,1],[0,2],[0,3]).

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.2by the very design of it, it matches. the area from 0 to 1 is 2 the area from 1 to 2 is 1 , 2+1 = 3 the area from 2 to 3 is 3 , 2+1+3 = 6

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.2i did learn how to integrate an absolute value tho :) I had gotten it to\[\int xdx=\frac{x^2}{2}+C\]but I couldnt get past that and had to look it up; i was thiiissss close :)\[\int xdx=\frac{xx}{2}+C\]

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.2lol, I also figured out the mystery behind continued fractions, at least for rational values \[\frac{9}{49}=\frac{1}{49/9}\] \[\frac{1}{49/9}=\cfrac{1}{5+\cfrac{4}{9}}=\cfrac{1}{5+\cfrac{1}{9/4}}...\]

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.2I feel like David Bowie in the Labrynth

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.2I devised a way to get an equation with a curve in it too; if we construct the absolute values to match the slopes we want; then integrating it produces the desired graph:dw:1346851055201:dw

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.2well, something better shaped that that id imagine lol
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