Here's the question you clicked on:
experimentX
Evaluate: given that b > a \[ \int_0^\infty {x^{a-1} \over 1 + x^b}\; dx\]
man ... I stuck at finding the simple residue.
if my memory serves me, it is the numerator divided by the derivative of the denominator evaluated at the pole
yeah you are correct ... had trouble fixing. \[ \huge \lim_{z \rightarrow e^{i \pi \over b}} {(z - e^{i{\pi }\over b}) z^{a-1} \over 1 + z^b} = \lim_{z \rightarrow e^{i \pi \over b}} {z^{a-1} \over -bz^{b-1}}\]
|dw:1346858176216:dw| somehow it got this fixed. I had this Q on my exam paper ... Man i couldn't do it.