Worst worded question to date:
A brick is thrown upward from the top of a building at an angle of 25degrees to the horizontal and with an initial velocity of 15m/s. If the brick is in flight for 3 seconds, how tall is the building?
Stacey Warren - Expert brainly.com
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It took me a little bit to assume that the 3 seconds in flight was a terminanting time, and not just a random interval :)
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Could I suggest something? @amistre64 sir
only the velocity in vertical direction is of use here
\[V_v= 15 \sin 25 \]
now let's find the time it takes the velocity in vertical direction to get to 0
and the distance it covers|dw:1346855419638:dw|
let the height be h1 and time be t1
here acceleration due to gravity=10 m/s^2 in downwards direction so -10
we could find t_1 from here
h1 from here
now the remaining time it takes to reach ground
using this we could find h2
building's height is h2-h1
\[h_2=0\times (3-t_1)+\frac 12 (-10) (3-t_1)^2\]
while i can understand the concepts you presented, it does seem like an awful lot of extra workings. I am a mathematician at heart, and by default very lazy :)