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elica85

  • 3 years ago

the motion of a particle is defined by the equations x=(2t+t^2) and y=(t^2) where t is in seconds. determine the normal and tangential components of the particle's velocity and acceleration when t=2s.

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  1. elica85
    • 3 years ago
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    i was able to get the speed although i don't know if i did it the right way. find dx/dt and dy/dt, plug in t=2, |v|=7.21m/s

  2. Pallavi06
    • 3 years ago
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    different the both equations with respect to time to find the equations of velocities in normal and tangential direction.... put t=2 to find value of velocty at that time......

  3. elica85
    • 3 years ago
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    answer to a_n is 0.555m/s/s answer to a_t is 2.77m/s/s

  4. elica85
    • 3 years ago
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    so i'm stuck on finding a_n and a_t

  5. Pallavi06
    • 3 years ago
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    u have to find normal and tangential velocity....why are u finding a_n and a_t???

  6. Pallavi06
    • 3 years ago
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    and a_t is 2 ....

  7. elica85
    • 3 years ago
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    that's what the problem asks. i already found v_t ^^^ and v_n=0.

  8. elica85
    • 3 years ago
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    a_t is not 2 according to answer on the back

  9. elica85
    • 3 years ago
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    that's what i thought since a=second derivative of x(t)

  10. elica85
    • 3 years ago
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    but it's not..

  11. Pallavi06
    • 3 years ago
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    the equations shows that partical is moving in a parabolic path....

  12. elica85
    • 3 years ago
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    right, so..

  13. elica85
    • 3 years ago
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    gotta run, i appreciate the help. i will check back later, thx thx thx

  14. Pallavi06
    • 3 years ago
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    hey \[a (total) = \sqrt{a_t ^{2}+a_n ^{2}}\]

  15. Pallavi06
    • 3 years ago
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    i am sorry coudnt help u more than this....

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