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elica85
the motion of a particle is defined by the equations x=(2t+t^2) and y=(t^2) where t is in seconds. determine the normal and tangential components of the particle's velocity and acceleration when t=2s.
i was able to get the speed although i don't know if i did it the right way. find dx/dt and dy/dt, plug in t=2, |v|=7.21m/s
different the both equations with respect to time to find the equations of velocities in normal and tangential direction.... put t=2 to find value of velocty at that time......
answer to a_n is 0.555m/s/s answer to a_t is 2.77m/s/s
so i'm stuck on finding a_n and a_t
u have to find normal and tangential velocity....why are u finding a_n and a_t???
that's what the problem asks. i already found v_t ^^^ and v_n=0.
a_t is not 2 according to answer on the back
that's what i thought since a=second derivative of x(t)
the equations shows that partical is moving in a parabolic path....
gotta run, i appreciate the help. i will check back later, thx thx thx
hey \[a (total) = \sqrt{a_t ^{2}+a_n ^{2}}\]
i am sorry coudnt help u more than this....