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Dallasb22
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AD=4√3 in.; AB = 8 in. Area =? times the square root of ? sq. in.
 one year ago
 one year ago
Dallasb22 Group Title
AD=4√3 in.; AB = 8 in. Area =? times the square root of ? sq. in.
 one year ago
 one year ago

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Dallasb22 Group TitleBest ResponseYou've already chosen the best response.0
@timo86m Help with mine?
 one year ago

timo86m Group TitleBest ResponseYou've already chosen the best response.1
do you know trig? or does this only require pythogoras theorem?
 one year ago

Dallasb22 Group TitleBest ResponseYou've already chosen the best response.0
It should only require Pythagoras theorem. It is merely Geometry.
 one year ago

Dallasb22 Group TitleBest ResponseYou've already chosen the best response.0
But the Sq Rt is what confuses me.
 one year ago

Dallasb22 Group TitleBest ResponseYou've already chosen the best response.0
I tried using the 306090 ratio and i got the answer: 2 times sqrt of 1.5 sq in which is wrong.
 one year ago

timo86m Group TitleBest ResponseYou've already chosen the best response.1
dw:1346873004579:dw
 one year ago

Dallasb22 Group TitleBest ResponseYou've already chosen the best response.0
Don't i take half of 4√3 since its the hypotunese?
 one year ago

timo86m Group TitleBest ResponseYou've already chosen the best response.1
dw:1346873167383:dw once you have a then a*2 would be height
 one year ago

Dallasb22 Group TitleBest ResponseYou've already chosen the best response.0
And how do i find A? A is what?
 one year ago

timo86m Group TitleBest ResponseYou've already chosen the best response.1
a is 4 i think the height is 8
 one year ago

Dallasb22 Group TitleBest ResponseYou've already chosen the best response.0
SO it would be area= 8 times the sqrt of 3?
 one year ago

timo86m Group TitleBest ResponseYou've already chosen the best response.1
then i think it is just 8*8 the area Something seems odd tho. THe figure is not to scale or i am wrong.
 one year ago

timo86m Group TitleBest ResponseYou've already chosen the best response.1
i did it wrong
 one year ago

timo86m Group TitleBest ResponseYou've already chosen the best response.1
all you have to do is find height then it is simply 8*h
 one year ago

Dallasb22 Group TitleBest ResponseYou've already chosen the best response.0
But how will that get me a sq rt?
 one year ago

timo86m Group TitleBest ResponseYou've already chosen the best response.1
i found where i gone wrong lol
 one year ago

timo86m Group TitleBest ResponseYou've already chosen the best response.1
dw:1346874388605:dw
 one year ago

timo86m Group TitleBest ResponseYou've already chosen the best response.1
a=2*sqrt(3) So h = 2*sqrt(3)*sqrt(3) and A=h*b can you do that?
 one year ago

Dallasb22 Group TitleBest ResponseYou've already chosen the best response.0
The height is √3 correct?
 one year ago

timo86m Group TitleBest ResponseYou've already chosen the best response.1
a=2*sqrt(3) So h = 2*sqrt(3)*sqrt(3) and A=h*b can you do that?
 one year ago

Dallasb22 Group TitleBest ResponseYou've already chosen the best response.0
193= 16 times √3
 one year ago

Dallasb22 Group TitleBest ResponseYou've already chosen the best response.0
Thanks man!
 one year ago

Dallasb22 Group TitleBest ResponseYou've already chosen the best response.0
I got it.
 one year ago
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