anonymous
  • anonymous
AD=4√3 in.; AB = 8 in. Area =? times the square root of ? sq. in.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
@timo86m Help with mine?
anonymous
  • anonymous
do you know trig? or does this only require pythogoras theorem?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
It should only require Pythagoras theorem. It is merely Geometry.
anonymous
  • anonymous
But the Sq Rt is what confuses me.
anonymous
  • anonymous
I tried using the 30-60-90 ratio and i got the answer: 2 times sqrt of 1.5 sq in which is wrong.
anonymous
  • anonymous
|dw:1346873004579:dw|
anonymous
  • anonymous
Don't i take half of 4√3 since its the hypotunese?
anonymous
  • anonymous
|dw:1346873167383:dw| once you have a then a*2 would be height
anonymous
  • anonymous
And how do i find A? A is what?
anonymous
  • anonymous
a is 4 i think the height is 8
anonymous
  • anonymous
SO it would be area= 8 times the sqrt of 3?
anonymous
  • anonymous
then i think it is just 8*8 the area Something seems odd tho. THe figure is not to scale or i am wrong.
anonymous
  • anonymous
i did it wrong
anonymous
  • anonymous
all you have to do is find height then it is simply 8*h
anonymous
  • anonymous
But how will that get me a sq rt?
anonymous
  • anonymous
i found where i gone wrong lol
anonymous
  • anonymous
Lol
anonymous
  • anonymous
|dw:1346874388605:dw|
anonymous
  • anonymous
a=2*sqrt(3) So h = 2*sqrt(3)*sqrt(3) and A=h*b can you do that?
anonymous
  • anonymous
The height is √3 correct?
anonymous
  • anonymous
a=2*sqrt(3) So h = 2*sqrt(3)*sqrt(3) and A=h*b can you do that?
anonymous
  • anonymous
19-3= 16 times √3
anonymous
  • anonymous
Thanks man!
anonymous
  • anonymous
I got it.
anonymous
  • anonymous
:)

Looking for something else?

Not the answer you are looking for? Search for more explanations.