lindseyharrison
15x^7/9y^5 divided by 45y^2/5x^3



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Dallasb22
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Can you do another beautiful drawing?

lindseyharrison
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a) 15x^4/y^3
b) 5x^10/27y^7
c) 27y^7/5x^10
d) y^3/15x^4

Fall1213
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\[\frac{ 15x ^{7} }{ 9y ^{5} }\div \frac{ 45y ^{2} }{ 5x ^{3} } = \frac{ 15x ^{7} }{ 9y ^{5} }*\frac{ 5x ^{3} }{ 45y ^{2} } = \frac{ 75x ^{10} }{ 405y ^{7} }=\frac{ 5x ^{10} }{ 27y ^{7} } \]

Fall1213
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Second choice :)

Dallasb22
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It is B.

Dallasb22
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I second Falls' work :P

Fall1213
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Lol