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virtus Group Title

Why is (a+b)^n+1 =(a+b)^n(a+b) =a(a+b)^n +b(a+b)^n

  • 2 years ago
  • 2 years ago

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  1. hartnn Group Title
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    its the property: \(x^{n+1}=x*x^n\) then distributive property is used p(q+r)=pq+pr ok?

    • 2 years ago
  2. Fall12-13 Group Title
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    It's a formula.

    • 2 years ago
  3. virtus Group Title
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    i don't get why (a+B)^n = a(a+b)^n +b(a+b)^n

    • 2 years ago
  4. Fall12-13 Group Title
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    Just give us the question xD I mean, if there is one.

    • 2 years ago
  5. virtus Group Title
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    *(a+b)^n x (a+b)

    • 2 years ago
  6. ganeshie8 Group Title
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    p(q+r)=pq+pr

    • 2 years ago
  7. ganeshie8 Group Title
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    say p = (a+b)^n

    • 2 years ago
  8. hartnn Group Title
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    (a+b)^n = a(a+b)^n +b(a+b)^n<----not true (a+b)^n+1 = a(a+b)^n +b(a+b)^n<---true

    • 2 years ago
  9. virtus Group Title
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    (a+b)^n x (a+b) =a(a+b)^n +b(a+b)^n

    • 2 years ago
  10. virtus Group Title
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    i don't get why that is

    • 2 years ago
  11. ganeshie8 Group Title
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    you want proof of distrubution property ?

    • 2 years ago
  12. virtus Group Title
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    ok

    • 2 years ago
  13. ganeshie8 Group Title
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    no its okay.... ..u didnt get why distribution prperty works is it ?

    • 2 years ago
  14. virtus Group Title
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    yes

    • 2 years ago
  15. ganeshie8 Group Title
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    basically you wanto understand why 2(3+4) = 2*3 + 2*4

    • 2 years ago
  16. Fall12-13 Group Title
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    LOL

    • 2 years ago
  17. virtus Group Title
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    LOL that sounds pretty cool the way you put it

    • 2 years ago
  18. ganeshie8 Group Title
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    idk the proof id love to see @TuringTest @KingGeorge @mukushla explain it

    • 2 years ago
  19. ganeshie8 Group Title
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    well let me try

    • 2 years ago
  20. ganeshie8 Group Title
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    2*100 = 100 + 100 right ?

    • 2 years ago
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