anonymous
  • anonymous
Why is (a+b)^n+1 =(a+b)^n(a+b) =a(a+b)^n +b(a+b)^n
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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hartnn
  • hartnn
its the property: \(x^{n+1}=x*x^n\) then distributive property is used p(q+r)=pq+pr ok?
anonymous
  • anonymous
It's a formula.
anonymous
  • anonymous
i don't get why (a+B)^n = a(a+b)^n +b(a+b)^n

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anonymous
  • anonymous
Just give us the question xD I mean, if there is one.
anonymous
  • anonymous
*(a+b)^n x (a+b)
ganeshie8
  • ganeshie8
p(q+r)=pq+pr
ganeshie8
  • ganeshie8
say p = (a+b)^n
hartnn
  • hartnn
(a+b)^n = a(a+b)^n +b(a+b)^n<----not true (a+b)^n+1 = a(a+b)^n +b(a+b)^n<---true
anonymous
  • anonymous
(a+b)^n x (a+b) =a(a+b)^n +b(a+b)^n
anonymous
  • anonymous
i don't get why that is
ganeshie8
  • ganeshie8
you want proof of distrubution property ?
anonymous
  • anonymous
ok
ganeshie8
  • ganeshie8
no its okay.... ..u didnt get why distribution prperty works is it ?
anonymous
  • anonymous
yes
ganeshie8
  • ganeshie8
basically you wanto understand why 2(3+4) = 2*3 + 2*4
anonymous
  • anonymous
LOL
anonymous
  • anonymous
LOL that sounds pretty cool the way you put it
ganeshie8
  • ganeshie8
idk the proof id love to see @TuringTest @KingGeorge @mukushla explain it
ganeshie8
  • ganeshie8
well let me try
ganeshie8
  • ganeshie8
2*100 = 100 + 100 right ?

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