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Why is (a+b)^n+1 =(a+b)^n(a+b) =a(a+b)^n +b(a+b)^n

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its the property: \(x^{n+1}=x*x^n\) then distributive property is used p(q+r)=pq+pr ok?
It's a formula.
i don't get why (a+B)^n = a(a+b)^n +b(a+b)^n

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Other answers:

Just give us the question xD I mean, if there is one.
*(a+b)^n x (a+b)
say p = (a+b)^n
(a+b)^n = a(a+b)^n +b(a+b)^n<----not true (a+b)^n+1 = a(a+b)^n +b(a+b)^n<---true
(a+b)^n x (a+b) =a(a+b)^n +b(a+b)^n
i don't get why that is
you want proof of distrubution property ?
no its okay.... ..u didnt get why distribution prperty works is it ?
basically you wanto understand why 2(3+4) = 2*3 + 2*4
LOL that sounds pretty cool the way you put it
idk the proof id love to see @TuringTest @KingGeorge @mukushla explain it
well let me try
2*100 = 100 + 100 right ?

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