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yakabush1 Group TitleBest ResponseYou've already chosen the best response.0
i got 480/80
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
Is this \[2 \times \frac{3}{8}\]?
 one year ago

yakabush1 Group TitleBest ResponseYou've already chosen the best response.0
helooooooooo
 one year ago

BifocalComb Group TitleBest ResponseYou've already chosen the best response.0
you have to multiply only the numerator by the three
 one year ago

BifocalComb Group TitleBest ResponseYou've already chosen the best response.0
oops i meant two
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
Just remember that fractions are really the amount on top (numerator) divided by the amount on bottom (denominator). One way to look at it is to turn the fraction \[\frac{3}{8}\] into\[3\div8\], so you have \[2\times3\div8\]Then solve the multiplications and divisions separately\[(2\times3)\div(8)=(6)\div(8)\]and then make it look like a fraction again:\[\frac{6}{8}\]. That can be simplified, though. Or, look at the "2" like this:\[\frac{2}{1}\], and multiply numerators together and denominators together. It's the same thing. Then\[\frac{2}{1}\times\frac{3}{8}=\frac{2*3}{1*8}=\frac{6}{8}\].
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
Those are two ways to think about multiplying fractions!
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
Sorry I took so long!
 one year ago

yakabush1 Group TitleBest ResponseYou've already chosen the best response.0
ok thanks
 one year ago

yakabush1 Group TitleBest ResponseYou've already chosen the best response.0
can u help me in one more
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
Can you simplify it? Divide top and bottom by 2! Some teachers require simplification...
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
Possibly! I have to go soon! You post it, and I'll see if I can help!
 one year ago

yakabush1 Group TitleBest ResponseYou've already chosen the best response.0
1 1/2 divided by 3
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
If it's very similar, I hope that you can do it on your own, or we can do it together!
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
So,\[1\frac{1}{2}\div3\]
 one year ago

yakabush1 Group TitleBest ResponseYou've already chosen the best response.0
i got 1 2/20
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
That is different!
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
That's not quite right, but we'll get there! \[1\frac{1}{2}=1+\frac{1}{2}\], right?
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
and 1, as a fraction, is any number over itself, like\[1=\frac{2}{2}\]right? Then you can look at \[1+\frac{1}{2}\]like\[\frac{2}{2}+\frac{1}{2}=\frac{3}{2}\]
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
\[1\frac{1}{2}=\frac{3}{2}\]
 one year ago

yakabush1 Group TitleBest ResponseYou've already chosen the best response.0
thanks men
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
\[=3\div2\]
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
That's just the fraction... You still have to divide by 3.
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
\[\frac{3}{2}=3\div2\] I did that again.. Similar to what we did before! Fraction to division... Really the same thing. Anyway, \[1\frac{1}{2}\div3=\frac{3}{2}\div3=3\div2\div3=3\div3\div2=1\div2\] See what I did there? And, if you need the fraction, I trust you can find it!
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
It's just lucky that \[3\div3=1\], because it made our problem easier! :)
 one year ago

BifocalComb Group TitleBest ResponseYou've already chosen the best response.0
Eric if you want I'll take over from here if you have to go..
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
Thanks! I trust you can help with this question and any others! :) I do have to get going. Take care, all!
 one year ago
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