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yakabush1 Group TitleBest ResponseYou've already chosen the best response.0
i got 480/80
 2 years ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
Is this \[2 \times \frac{3}{8}\]?
 2 years ago

yakabush1 Group TitleBest ResponseYou've already chosen the best response.0
helooooooooo
 2 years ago

BifocalComb Group TitleBest ResponseYou've already chosen the best response.0
you have to multiply only the numerator by the three
 2 years ago

BifocalComb Group TitleBest ResponseYou've already chosen the best response.0
oops i meant two
 2 years ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
Just remember that fractions are really the amount on top (numerator) divided by the amount on bottom (denominator). One way to look at it is to turn the fraction \[\frac{3}{8}\] into\[3\div8\], so you have \[2\times3\div8\]Then solve the multiplications and divisions separately\[(2\times3)\div(8)=(6)\div(8)\]and then make it look like a fraction again:\[\frac{6}{8}\]. That can be simplified, though. Or, look at the "2" like this:\[\frac{2}{1}\], and multiply numerators together and denominators together. It's the same thing. Then\[\frac{2}{1}\times\frac{3}{8}=\frac{2*3}{1*8}=\frac{6}{8}\].
 2 years ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
Those are two ways to think about multiplying fractions!
 2 years ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
Sorry I took so long!
 2 years ago

yakabush1 Group TitleBest ResponseYou've already chosen the best response.0
ok thanks
 2 years ago

yakabush1 Group TitleBest ResponseYou've already chosen the best response.0
can u help me in one more
 2 years ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
Can you simplify it? Divide top and bottom by 2! Some teachers require simplification...
 2 years ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
Possibly! I have to go soon! You post it, and I'll see if I can help!
 2 years ago

yakabush1 Group TitleBest ResponseYou've already chosen the best response.0
1 1/2 divided by 3
 2 years ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
If it's very similar, I hope that you can do it on your own, or we can do it together!
 2 years ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
So,\[1\frac{1}{2}\div3\]
 2 years ago

yakabush1 Group TitleBest ResponseYou've already chosen the best response.0
i got 1 2/20
 2 years ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
That is different!
 2 years ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
That's not quite right, but we'll get there! \[1\frac{1}{2}=1+\frac{1}{2}\], right?
 2 years ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
and 1, as a fraction, is any number over itself, like\[1=\frac{2}{2}\]right? Then you can look at \[1+\frac{1}{2}\]like\[\frac{2}{2}+\frac{1}{2}=\frac{3}{2}\]
 2 years ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
\[1\frac{1}{2}=\frac{3}{2}\]
 2 years ago

yakabush1 Group TitleBest ResponseYou've already chosen the best response.0
thanks men
 2 years ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
\[=3\div2\]
 2 years ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
That's just the fraction... You still have to divide by 3.
 2 years ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
\[\frac{3}{2}=3\div2\] I did that again.. Similar to what we did before! Fraction to division... Really the same thing. Anyway, \[1\frac{1}{2}\div3=\frac{3}{2}\div3=3\div2\div3=3\div3\div2=1\div2\] See what I did there? And, if you need the fraction, I trust you can find it!
 2 years ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
It's just lucky that \[3\div3=1\], because it made our problem easier! :)
 2 years ago

BifocalComb Group TitleBest ResponseYou've already chosen the best response.0
Eric if you want I'll take over from here if you have to go..
 2 years ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
Thanks! I trust you can help with this question and any others! :) I do have to get going. Take care, all!
 2 years ago
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