Delete
Share
This Question is Open
yakabush1
Best Response
You've already chosen the best response.
0
i got 480/80
theEric
Best Response
You've already chosen the best response.
1
Is this \[2 \times \frac{3}{8}\]?
yakabush1
Best Response
You've already chosen the best response.
0
yes
yakabush1
Best Response
You've already chosen the best response.
0
helooooooooo
yakabush1
Best Response
You've already chosen the best response.
0
1
BifocalComb
Best Response
You've already chosen the best response.
0
you have to multiply only the numerator by the three
BifocalComb
Best Response
You've already chosen the best response.
0
oops i meant two
theEric
Best Response
You've already chosen the best response.
1
Just remember that fractions are really the amount on top (numerator) divided by the amount on bottom (denominator).
One way to look at it is to turn the fraction \[\frac{3}{8}\] into\[3\div8\], so you have \[2\times3\div8\]Then solve the multiplications and divisions separately\[(2\times3)\div(8)=(6)\div(8)\]and then make it look like a fraction again:\[\frac{6}{8}\]. That can be simplified, though.
Or, look at the "2" like this:\[\frac{2}{1}\], and multiply numerators together and denominators together. It's the same thing. Then\[\frac{2}{1}\times\frac{3}{8}=\frac{2*3}{1*8}=\frac{6}{8}\].
theEric
Best Response
You've already chosen the best response.
1
Those are two ways to think about multiplying fractions!
theEric
Best Response
You've already chosen the best response.
1
Sorry I took so long!
yakabush1
Best Response
You've already chosen the best response.
0
ok thanks
yakabush1
Best Response
You've already chosen the best response.
0
can u help me in one more
theEric
Best Response
You've already chosen the best response.
1
Can you simplify it? Divide top and bottom by 2!
Some teachers require simplification...
theEric
Best Response
You've already chosen the best response.
1
Possibly! I have to go soon! You post it, and I'll see if I can help!
yakabush1
Best Response
You've already chosen the best response.
0
1 1/2 divided by 3
theEric
Best Response
You've already chosen the best response.
1
If it's very similar, I hope that you can do it on your own, or we can do it together!
theEric
Best Response
You've already chosen the best response.
1
So,\[1\frac{1}{2}\div3\]
yakabush1
Best Response
You've already chosen the best response.
0
i got 1 2/20
theEric
Best Response
You've already chosen the best response.
1
That is different!
theEric
Best Response
You've already chosen the best response.
1
That's not quite right, but we'll get there!
\[1\frac{1}{2}=1+\frac{1}{2}\], right?
yakabush1
Best Response
You've already chosen the best response.
0
yeah
theEric
Best Response
You've already chosen the best response.
1
and 1, as a fraction, is any number over itself, like\[1=\frac{2}{2}\]right?
Then you can look at \[1+\frac{1}{2}\]like\[\frac{2}{2}+\frac{1}{2}=\frac{3}{2}\]
theEric
Best Response
You've already chosen the best response.
1
\[1\frac{1}{2}=\frac{3}{2}\]
yakabush1
Best Response
You've already chosen the best response.
0
thanks men
theEric
Best Response
You've already chosen the best response.
1
\[=3\div2\]
theEric
Best Response
You've already chosen the best response.
1
That's just the fraction...
You still have to divide by 3.
yakabush1
Best Response
You've already chosen the best response.
0
1.5
theEric
Best Response
You've already chosen the best response.
1
\[\frac{3}{2}=3\div2\]
I did that again.. Similar to what we did before! Fraction to division... Really the same thing.
Anyway,
\[1\frac{1}{2}\div3=\frac{3}{2}\div3=3\div2\div3=3\div3\div2=1\div2\]
See what I did there? And, if you need the fraction, I trust you can find it!
theEric
Best Response
You've already chosen the best response.
1
It's just lucky that \[3\div3=1\], because it made our problem easier! :)
BifocalComb
Best Response
You've already chosen the best response.
0
Eric if you want I'll take over from here if you have to go..
theEric
Best Response
You've already chosen the best response.
1
Thanks! I trust you can help with this question and any others! :) I do have to get going. Take care, all!